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NTNU Norwegian University of Science and Technology Faculty of Information Technology and Electrical Engineering Department of Mathematical Sciences

Max Lunde Hauge

Cantor Minimal Systems

Bachelor’s project in Mathematical Sciences Supervisor: Eduardo Ortega Esparza

May 2021

Bachelor ’s pr oject

(2)
(3)

Max Lunde Hauge

Cantor Minimal Systems

Bachelor’s project in Mathematical Sciences Supervisor: Eduardo Ortega Esparza

May 2021

Norwegian University of Science and Technology

Faculty of Information Technology and Electrical Engineering Department of Mathematical Sciences

(4)
(5)
(6)
(7)
(8)

c

(9)

⇥ C

C

{0, 1}N

i

(⇥,)) (+,⇢)

(10)
(11)

C

R

C

C

[0, 1] ⇢ R C

0 =[0, 1] ⇠= ⇢ C

= 1

0= [0, 1],

1=⇠0\

✓1 3,2

3

=

 0,1

3 [

2 3, 1 , ...

= = ⇠= 1

3 [

✓2

3 +⇠= 1 3

◆ .

(12)

C= Ÿ1

==1

=.

= 2= 1/3=

0, 1 2 C

1 C

3,23 2 C

C

(00. . .0=) = 2N

(0=) 0=

0 1 (0=) =

= 0= 2 {0, 1}= (0=)

(0=) 2{0, 1}N

0 1

|A| < 1

1 :=0

0A: = 0 1 A. A < 1

= :=0

0A: =0

✓1 A=+1 1 A

◆ .

G 2C

1

==1

20=

3= 0= 2{0, 1}.

< 2 N < 1 ⇠< < <

(13)

<<

<

G 2 C

<

==1

20= 3=

| {z }

403

+

1

==<+1

20= 3=

| {z }

) 08;

0= 2{0, 1}.

0= 0= =1 =

1

==<+1

20=

3=  2

1

==<+1

1 3=

!

=2

1

==0

1 3=

<

==0

1 3=

! ,

 2 1 1 13

1 13 <+1 1 13

!

=2 1+ ( 1) + 13 <+1

2 3

! ,

 3

✓1 3

<+1

= 1 3<.

<

G G 2⇠< <

C=—1

<=1<

1

==1

20=

3= 0= 2{0, 1}.

0= = 0 = 0= = 1

=

0, 1 2 C

1

==1

2·0 3= =0,

1

==1

2·1 3= =2·

1 3

1 13 =1.

G 2C

G C

G

(14)

= = 4

01 = 1 02 =0 03 =1 04 =0

4

==1

20=

3= = 2·1

31 + 2·0

32 + 2·1

33 + 2·0 34 = 20

27.

0= = =4

= =4 0= = =4

1/34

C ✓ [0, 1] ✓ R R

( ✓ R ✓ = [0,1] =(0,1)

✓( ) =1 0.

C 2=

1/3=

(15)

1

3 +2· 1

9 +4· 1

27 +8· 1

81 + · · ·=

1

==1

2= 1 3= .

1

==1

2= 1 3= =

1

==1

2= 1·3 = = 1 3

1 1 23

!

=1.

1 C

1 C

C

C (0=) 2{0, 1}N

! C

! =C !

(0=) (1=) ...

N (G=)

!

! (U=)

!

(0=) 2! U0 2 (U=)

00 2 (0=) U0 =

( 1 00 =0, 0 00 =1.

(16)

U0<00 (U=) < (0=) (1=) 2!

U1 2 (U=) 10 2 (1=)

U1 =

( 1 11 =0, 0 11 =1.

U1 <11 (U=) < (1=) (G=) 2!

(U=) (G=) 2! !

(U=)

! ! (U=) !

(V=) 8 !

C C

C

⇥3 #

0 ! 1 30

1 ! 3 31

2 ! 9 32

3 ! 27 33

C G ! 2 3G

C

0 1

C ⇢ [0, 1]

[0, 3] C

C

(17)

2=3G G = log 2log 3 ' 0.631

C

C

1 2 + 1

6+ 1

18 + · · ·= 1 2+

1

==1

2 2⇤3= = 1

2 +

1

==1

1 3=. 1

0 =

(18)

1 2 +

1

==1

0=

3= 0= 2{0, 1}.

C

g

g

(19)

C

⇥ R

R

- 3 3 :-⇥- ! R

" - 3 (-,3) 3

3(G,~) >0 3(G,~) =0 G =~ 3(G,~) =3(~,G) G,~ 2-

3(G,I) 63(G,~) +3(~,I) G,~,I 2- R

3(0,1) = |0 1| 3

0,1 2 - 3(0,1) = 0 0 = 1 3(0,1) > 0 0,1 2 R

0,1,2 2R

R R

(-,3) (0:):1=0 2-

A > 0 # 2N <,=>#

3(0=,0<) <A.

" = (-,3)

- -

R R

(20)

(-,3) G 2- n > 0

n G n -

B(G;n) ={~ 2- |3(G,~) <n}.

(R,3) (G n;G+n)

G n

(-,3) ( ✓-

G 2( n B(G;n) ✓(

{ U} U 2N

* =–

U2N U 0 2 U ✓*

02* n B ✓ U ✓* 0 ⌫ ✓*

*

0,. . ., V V 2N

+ =—V

:=0 : 02* 0

: n B ✓ : 0:  V

n

n =minn0,. . .,nV B(0,n) ✓ B(0,n:) B(0,n) ✓+ +

(-,3) ( ✓ - G 2-

( B(G;n) ( G

(-,3) ( ✓- G 2(

( (

(-,3) G 2- n > 0

n G n -

B(G;n) ={~ 2R |3(G,~)6n}.

(-,3) ( ✓ -

( G (

( " = (-,3)

(0:) ( (0:) - ( ✓- "

G 2- ( ( =(

G 2( (

(21)

8 ✓ -

Ÿ

82 8

!2

⌘ÿ

82

( 8)2 ÿ

82 8

!2

⌘ Ÿ

82

( 8)2.

C

R C ⇢ R

(-,3) ( ✓ -

(-,3) ( ✓- !

( ( ( ( ✓ -

( =( [!.

( (0,1) ( = (0,1)[! = [0,1]

( =( (

(-,3) ( ✓ - (

(2 (2 ✓-

(2 ={0 2- |08(}.

( (2

( (2

( ( ✓ - G 2 (2 n

G (2 G 2(

n B ✓$

G 2$2

(22)

& & ✓- &

G 2&2 G 8& &2

n G & B ✓&2 $2

' ✓ - ('2)2 = '

(-,3) ( ✓ - ( -

( =-

(-,3) (-,3) (-, ¯3)

5 :- ! - 3¯(5(G),5(~)) =3(G,~) G,~ 2- 5(-) ={5(G) :G 2-} -

R C

(C,3) G 2C

C

3 R 0,1 2 C 3 : C⇥C! R

3

3(0,1) =3

1

==1

20=

3= ,

1

==1

21=

3=

!

=

1

==1

2|0= 1=| 3= 0=,1= 2 {0, 1}.

3

G 2 C B(G;n) ~ 2 C

n G ~

n G

1/3< < 2N n

1

3= 1 <n  31<

n > 0 = 2N G 2C

G n = 31= ~ 2 C 3(G,~) < 31= G

= G ~

G 2 C = 2 N n = 31= B(G;31=) = ~ 2C |3(G,~) < 31= G = Õ1

==02G=

3=

~ =Õ1

==0 2~= 3=

1

==1

2|G= ~=|

3= =

<

==1

2|G= ~=| 3=

| {z }

403

+

1

==<+1

2|G= ~=| 3=

| {z }

) 08;

.

1/3< n

n = 1/3< < n

(23)

1/3<

= G ~

1/3<

(-,3) ( ✓ -

A > 0 3(0,1) < A 0,1 2 ( ( (-,3)

(-,3) ( ✓ - (

( (

( ✓ R (

R

C C

[0,1] C

1 < |A| [0, 1]

3(0,1) 6 1 < A C

C ⇢ [0, 1] ⇢ R

(-,3) ( ✓ - (

02(

[2,3] 2 <3

G 2⇠11

1 =

 0,1

3 [

2 3, 1 G1 2C\⇠1 G1 <G

|G G1|  1/31 = 2 N

(24)

= G= 2 C\⇠= G= < G

|G G=|  1/3= C

(-,3) (,& ✓ -

(,& ( \& (\&

(-,3) ' ✓ - '=([&

( & ' '

0,1 2' 0 2

1 2⌫ '= [⌫

C C

:,; 2 C

: 2 ; 2! [! ✓⇠?? ✓⇠=

:,;

=

:,;

=

C

R

C

- T T ( ✓ -

-

- ; T

* T * T

(25)

* T * T

(-,T )

- B T - ⌫ ✓-

G 2- ⌫ 2B G 2⌫

D 2 T G 2D ⌫ 2B G 2⌫ ⌫ ✓D

- B T

⌫ 2B T -

⌫ 2B T *

T G 2* ⌫ 2B G 2⌫ * =–

G2* ⌫ B

(-,3) n

C

B ={B(G;n) |G 2-,n > 0}.

- . 5 :- !.

* ⇢. 5 1(*) -

- . 5 :- !.

5 5

- . - .

5 5

(26)

0 1

C - ={0, 1}N 0 1

- {0, 1}

- = {0,. . .,? 1}N ? 2

- T - T

- T -

T ;,- ✓ -

T -

G 2-

- -

? 2N ={0, 1, 2,. . .,? 1} =

N ={ }

< 2N < ={ < 2N }

=–1

<=1 < ={ < 2N }.

G 2 = ~ 2 < =,< 2N

G ~ G ~ G~ =+<

G~ =G ~ 2 =+<.

G~ <~G

G 2 = ~ 2 = G =G0G1G2. . .G=

~ =~0~1~2. . .~< G,~

G~ =G0. . .G=~0. . .~<,

~G =~0. . .~=G0. . .G<.

(27)

I 2 N I=I0I1. . .I8. . . G,I

GI =G0. . .G=I0. . .I8. . .,

IG =I0. . .I8. . . .G0. . .G=.

G 2 = ~ 2 < =,< 2N < >=

G ~ I 2 < = ~ =GI

G 2 = = ~ 2 N

G ~ 2 N

- =÷ -8. -

B = n÷

*8 |*8 ✓-8 *8 =-8 8 o

.

*8 = -8

={0,. . .,? 1} G 2

N

l l 2 /(l) N

/(l) = l 2 ,G 2 N |lG 2 N ,

={ l}.

/(l)

÷N

{0,. . .,? 1} = N ={0,. . .,? 1}N ? 2.

? 2

0

/(l) /([) l [

= ~

(28)

/(l) /([)

/(l)[/([) = 8>>>

>>><

>>>>

>>

:

/(l) [ =l~, /([) l =[~,

/(l0. . .l= 1) [= <l= =,

/(l)[/([)

l =l0. . .l= [ =[0. . .[< = < = <<

l8 <[8 0 8  min{=,<}

l [ [ =l~

~ /([) ✓ /(l) /(l) = /(l) [/([)

[ l

= =< = 1

= l =[0. . .[= 1l= [=l0. . .l= 1[=

/([0. . .[= 1)

/(l) /([) l [

= ~

8 /(l) /([)

8 =/(l)\/([) =8>>><

>>>

:

/([) l ✓[ [ =l~, /(l) [ ✓l l =[~,

;.

l =l0. . .l= [ =[0. . .[< = < = <<

l8 <[8 0 8  min{=,<}

l [ [ = l~ [

l l = [~ ~

/([) ✓ /(l) /(l) ✓ /([) /(l) \/([) /(l) /([)

l 2 {0,. . .,? 1}N

{0,. . .,? 1}N

⇥ C n {0,. . .,? 1}N

9: {0,. . .,? 1}N ! ⇥

9 n

9

(29)

{ 0, 1 }

N

? = 2 9

÷N

{0, 1} ={0, 1}N.

= =2 /(l) /([)

/(00)[/(01) =/(0), /(00)[/(0010) =/(00),

/(10)[/(110) =/(10)[/(110), /(01)[/(10) =/(01)[/(10).

/(l)

! 4

? = 2 /(l) /([)

/(00)\/(01) =;,

/(00)\/(0010) =/(0010), /(10)\/(110) =;,

/(01)\/(10) =;.

(30)

l =01

/(01) =/(00)[/(1).

9: {0, 1}N !⇥ 9 9([):/([0. . .[<)! B(Õ1

8=02[8

38 , 1/3<)

9 / (l) ✓ {0, 1}N

< 2N l =l0. . .l<

9 (/(l)) = (’1

==0

2G=

3= :G8 =l8, 808 <

)

=B

1 8=0

2l8

38 ; 1 3<

! .

G 2bZ? < > 0 9 1 B

1 8=0

2G8

38 ; 1 3<

! !

=/ (l0. . .l<).

9 1 B ✓ bZ? / (G) ✓ {0, 1}N

9 1 1 = 9 / (G)

B 9 1 9 9 1

9 {0, 1}N

G 2 {0, 1}N

B(9(G); 1/3=) /(G),

{~ 2 C |3(G,~) < 1/3=} G 2 ,~ 2 N |G~ 2 N . G =01110

B(9(G); 1/33) /(011), B(9(G); 1/35) /(01110).

B(9(G); 1/35) ✓ B(9(G); 1/33), /(01110) ✓ /(011).

(31)

{0,. . .,? 1}N ? 2

? bZ?

⌧ ⌧ ⇤

⌧ h⌧,⇤i

(0⇤1)⇤2 =0⇤(1⇤2) 0,1,2 2⌧

4 2⌧ 4⇤G =G⇤4 G 2⌧ G 2⌧ 002⌧ 0⇤00=00⇤0=4

? 2N

N[?] = G0?0· · · +G8?8 |8 2N G8 2{0,. . .,? 1} ,

= (’<

8=0

G8%8 |G8 2{0,. . .,? 1} )

.

3? N[?]

3?(G,~) =3?(00+ · · · +0=?=,10+ · · · +1<?<) = |0: 1:|

?: ,

: 0: < 1: N[?] 3?

? b Z? =

(’1

8=0

G8%8 |G8 2 {0,. . .,? 1} )

.

(32)

0 = 00. . .0< {0,. . .,? 1} <

⌘(0)=Õ1

8=008?8

⌘ / (l) ✓ {0,. . .,? 1}N

< 2N l =l0. . .l<

⌘(/(l)) = (’1

==0

G=%= :G8 =l8, 808 <

)

=B

1 8=0

l8?8; 1

?<

! .

G 2bZ? < > 0

1 B

1 8=0

G8%8; 1

?<

! !

=/ (l0. . .l<).

1 B ✓ bZ? / (G) ✓ {0,. . .,? 1}N

⌘ ⌘ 1 1 / (G)

B ⌘ 1 ⌘ ⌘ 1

⌘ {0,. . .,? 1}N bZ?

i

? 2N @ 2N i@: {0,. . .,? 1}N ! {0,. . .,? 1}N

4 2bZ?

0,1, 0, 1 2bZ? 0+1 =2

= 2N 0 1

20 =(G+~)0 =G0+~0+Y0 mod ? Y0=0, ...

2= =(G+~)= =G=+~=+Y= mod? Y= =

( 0 G= 1+~= 1+Y= 1 < ?, 1 G= 1+~= 1+Y= 1 =?.

G 2bZ? G G G 2bZ?

G+ ( G) =0.

@ 2 N ? 2 N

q@: bZ? ! bZ? q@(G) =G +@ q@1(G) =G @ G 2bZ?

(33)

q = 2N q

q@= =q@ . . . q@

| {z }

=

=q=? =? =?+ · · · +?

| {z }

=

.

q bZ?

q bZ? q

@ 2N ? 2N i@: {0,. . .,? 1}N !

{0,. . .,? 1}N G 2 {0,. . .,? 1}N i

i@ (G) =⌘ 1(q@(⌘(G))).

⌘ :{0,. . .,? 1}N !bZ? q@:bZ? !bZ? @

-,.,/ 5 :- !. 6:. !/

5 6 6 5: - !/

* ✓ / / (6 5) 1(*) = {8G 2- |6(5(G)) 2*} = 8G 2- |G 2 5 1(6 1(*)) = 5 1(6 1(*)) 6 5 6 1(*)

. 5 1(6 1(*)) - (6 5)

5 6

(6 5) (6 5)

(6 5) 1

i@ {0,. . .,? 1}N

⇥ {0,. . .,? 1}N {0,. . .,? 1}N

bZ? bZ?

i@

1

q@

' '

i = ⌘ 1q⌘ ⌘

i

(34)

@=1 ? =2

q1:bZ2!bZ2 q1(G) =G+1 q11(G) =G 1 G 2bZ2 1, 12bZ2 : 2N

1=1+0·21+0·22+ · · ·=1+

1

==1

0·?= 1=1+1·21+1·22+ · · · =

1

==0

1·?=. q=(G)

@< 1

G G 2 bZ2

{0, 1}N

G =1+21+22+23+ · · ·= (111111111111. . .), G =1+0+0+0+0+ · · ·= (100000000000. . .), G+ ( G) =0+0+0+0+0+ · · ·= (000000000000. . .).

02bZ2 0=0+0·21+0·22+. . .

i2 q@2

{0, 1}N {0, 1}N {0, 1}N

b

Z2 bZ2 bZ2

i

i2

i

q1

q12

q1

'

0+0=0 0+1=1 1+1=0 1

G G

(35)

? =2 @ =1 / (l) ✓ {0, 1}N i

l =l8l0=l0. . .l< l8

l0 l8

i(l8l0) =

( 1l0 l8 1 =0,

0i(l0) l8 1 =1 08 =.

i

? = 2 @ = 1 / (G) ✓ {0, 1}N

<

l =l0. . .l< =l0l1l0.

l =l0+l1·21+l2·22+ · · · +l<·2<, 1=1+0·21+0·22+ · · · +0·2<.

l0+1 l1+0+n

n l0 = 1

0 = 2 mod 2 1 =21

l1+0+21 1 mod 2 1 2bZ2

0 02bZ2

i i(l0l1l0) = 0l1l0 l0 = 1

i(l1l0) 1 = 21

i(l0l1l0) = 1l1l0 l0 = 0

l G,~ 2 {0, 1}N

G =G0G0=G0G1G00 ~ =~0~0=~0G1~00 G0,~0 G00,~00

i 1 l =01 i 1

12bZ2 1=1000. . . {0, 1}N

i 1(/(l)) = G 2{0, 1}N |i(G)=l~ .

i 1 G =1G0 i(1G0) =0i(G0) =0~0 i 1 G =10G00 i(10G00) =0i (0G00) =01i(G00) =01~00

i(/(01)) = G 2{0, 1}N |i(G)=01~ , i(/(01)) =/(10).

(36)
(37)

( ⇥, ) )

i = 2 Z

G 2⇥ i

i

i: ⇥ !⇥

G 2⇥ G

G

i = 2Z

G ⇥

i

G

(⇥,)) ⇥

) :⇥ !⇥

(⇥,)) G 2 ⇥

{)=(G) |= 2Z}.

) G

G

(38)

(⇥,)) G 2 ⇥

= <0 )=(G) =G

(⇥,)) G 2⇥

~ 2⇥ n > 0 = 2Z

3()=(G),~) <n.

G

.

n )=(G)

Tnx

(⇥,)) )

n

G ~

G ⇥

(⇥,)) ) : ⇥ ! ⇥

i ?

@

?,@ 2 N G,~ 2 ⇥ i: ⇥ ! ⇥

? @ gcd(?,@) =1

i = 2N 3(i(G),~) < 1/3=

= G ~

⇧: bZ? ! Z/?=Z Õ1

<=00<?< ! Õ= 1

<=00<?<

mod (2=) ⇧

?=

bZ? Z/?=Z

G 2 Z? iG =G +@ ⇧(G +@)

(39)

(⇥,))

G 2bZ? Z/?=Z

bZ? Z/?=Z

i i

⇧(G) i(⇧(G)) = ⇧(G) +@ i b

Z? i

i

i bZ? gcd(?,@) = 1

gcd(?,@) =1

? =2 @ =3 gcd(?,@) =1

G 2 {0, 1}N G < =3 G =100G0

G i=: {0, 1}N +!3 {0, 1}N = 2Z

: 100 +!3 001 +!3 111 +!3 010 +!3 101 +!3 000 +!3 110 +!3 011 +!3 100.

3 0 1

8 i8(100) = 100

G

0 1 i=(G) <G = 2 N

==0 G

0 1 i n

i=(G) ~ 2{0, 1}N :

=

? =2 @ =2 gcd(?,@) =2 : 100 +!2 110 +!2 101 +!2 111 +!2 100,

: 010 +!2 001 +!2 011 +!2 000 +!2 010.

2 0 1

8

G

n G

: i=(G) ~

=

⇥,)

(40)

( + , ⇢ )

(⇠,))

G 2C

+1

+2

+3

+4

1

2

3

= 1 (+,⇢)

+ +0. . .+=. . .

+0 = {E0} +1 = {E1,. . .,}

⇢ ⇢0. . .⇢=. . .

0 = {40,. . .,} ⇢1 = {41,. . .,}

B: ⇢= ! += 1 B 1({E}) E [= 0+= A: ⇢= ! +=

A 1({E}) E [= 1+=

E0

(+,⇢) 0  < < =

+< += %<,=

%<,= ={(?<+1,?<+2,. . .,?=) |?8 2⇢8,< <8 =, A (?8) =B (?8+1),< < 8 <=}.

(41)

(⇥,))

+0 ={E0} ?

% ={(?1,?2,. . .) |?: 2⇢:, A (?:) =B(?:+1),: 1}.

?:

?:+1

= 2N (⇢,+) = |E=|=:

= "= 2":: (N)

"=(8,9)= ⇢= 8 2+= 1 9 2+=

"= ="< =,< 2N

"= ="

" " = 2 N

"= ="· · · · ·"

| {z }

=

"

" = (2),

| {z } " = 1 1 1 1

! ,

| {z }

" = 1 0 0 1

! .

| {z }

" (1)

%

40. . .4= E0

l =40. . .4=

/ (l) ={lG 2% |l =40. . .4=,G 2%},

={ l}.

%

%

(+,⇢, ) (+,⇢)

⇢ 4,40 2 ⇢ A(4) = A(40)

(42)

W = 41. . .4= d = 51. . .5= A(W) = A(d) (+,⇢, )

-<0G =U0U1. . . U 2⇢<0G -<8= =V0V1. . . V 2⇢<8=

(+,⇢, )

% ): % !%

)(-<0G) =)(-<8=) )(G) =~(G=+1)G=+1 G= 2⇢8

G: 8 ⇢<0G : )(G) = (~1~2. . .~: 1(4: +

1)4:+1. . .) 4: +1 5

4: +1

G 2 {0, 1}N G = 1110011G0 G0

) G

)(G)=)(1110011G0) =000(0+1) 011G0=0001011G0.

: = 4 4: 8 ⇢<0G @ = 1 ? =2

{0, 1}N i1 G

i1(1110011) =0i1(110011) =00i1(10011) =· · ·=0001011.

{0, 1}N

(43)

(⇥,))

(44)

Emax Emin

0 1

0 1

0 1

0 1

0 1

0 1

0 1

0 1

0

0 1

0 1

0 1

0

0

0 0

1

1

1

(45)
(46)

NTNU Norwegian University of Science and Technology Faculty of Information Technology and Electrical Engineering Department of Mathematical Sciences

Cantor Minimal Systems

Bachelor’s project in Mathematical Sciences Supervisor: Eduardo Ortega Esparza

May 2021

Bachelor ’s pr oject

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