The generalized 3-secant lemma
Introduction.. The following pages contain a proof of the conjec- ture formulated in Remark (5o2o14) of [La]o We shall use the notations of that paper, and we shall, in fact, typographi- cally make this paper fit into [La] and extend it in a natural way ..
This makes it necessary to erase Remark (5o2~11) renumber Lemma (5 .. 2o12) accordingly, and omit page 28o
The reader sh~uld note that the conclusion of the main theorem (5o2 .. 14) is proved only in characteristics greater than n ..
- 0 -
Suppose given a family of homogenous poly-
(*)
nomials of degree n
and a function
p : (P 1 , ... , P r} ~ k such that
Q. . (Pl)
~1, .... ,~s
=
(x. .. .. ox. ) 11 1s (P1 ) • p(P1 )for all 1
=
1, ••• ,r, and all indices (i1 , ... ,is) .. Then there exists a homogenous polynomial Q of degree n-s such thatProof. We know that f
coefficients.
Fix i 2 , ... ,is and find not contain the monomial tain the monomial ~.
(mod f)
contains and with non-zero
a,b E k such that Q . o, ~2, ... , J.s . - bf does
~ and Q1 . . - af does not con- '12, ••• ,~s
Then by (5.2.11) there exists a homogenous polynomial of degree n-1 , such that
In exactly the same way there are a' ,b' ,c,c'
'
Q! ~2, ••• ,~s . andQ'.' .
~2' 000 '1s such that
Q . . - b 'f = X
Qj_2'"""'is
o,~2, .... ,~s 0
Q2 . . - C If = x2 Q! .
'~2'"""'~s ~2, .... ,~s and
Using (*) we find:
and since x is not a factor in f , this implies
0
and, exactly in tbe same way
thus
(mod f)
Now using (*) again, we find that
Q_ • )(Pl)
~2, ... ,J.s Thus
since
- 2 -
does not contain the monomial ~ where (i,j,k}
=
(0,1,2}.Thus
Go on, obtain the result we want ..
Now, let n : R - S be a surjective homomorphism of local k-algebras with mR • kern ::;: 0 , S/B;s :::. k. Suppose given a commutative diagram of flat S-schemes
X ®
s
cp I ~y
®s <1.:. y'
k k
c
~ i~·h
Z'
and let
£a
denote the subdiagram consisting of cp' : X ® S - >Y
® Sk k
Suppose further that -~' , 'll' and cp' are local complete intersections that may be lifted to R , then the obstruction
the diagram (or the category) .£ relative to
A~
(.£.,0c) ®kern=
coker(l,m-n) -o - k-o c
o(c,c ) - -o sits in
=
[H0 (X,Nx ® Oz) (f) H0 (Y ,Ny ® Oy) /im(l ,m-n)} ®kernOy Oy k
and, in fact, is the class of the element
for lifting
- 3 -
where, having pi eked liftings n" of 'll' and ~ 11 of ~ ' , o (a.) and
o(~)
are the obstructions in A1 (a' ;o2 ,)®kerTT =H0 (X,Nx®o2 )®kernk ox k
respectively
A
1(~';o 2 ,)®kern
= H0(Y,Ny®o2)®kern for liftingk Oy k
the morphisms a' and ~· with respect to T111 respectively ~"
and T]11 .. We shall apply this observation to the situation above,
First, let's make the following,
Rt:mark
(5.2 .. 13)
Using the assumption that is a complete intersection, we know that ~ may be lifted everywhere.. Since Z = (P 1 , ... ,P r} is of dimension zero, Z'-:r[
IP3 may also belifted everywhere. Using the observation above, we find (see
(2»
that
dim Iz (X, Y) ~ 2 Moreover, if ::lim Iz (X, Y)
=
2 is non singular at [Y} •coker(l,m-n)
=
o thus I 2 (X,Y)Next, let's compute the cup-product, ioeo the symmetric pairing
defined by the obstruction morphism ..
This is interesting only in case the imbedding dimension of I 2 (X;Y) is 3 ' as we have just seeno
The cup-product is the obstruction for lifting the universal diagram
to T1;m3, lifting cp® 1 trivially.
- 4 ~
We have already seen that the imbedding
w'
is defined by the idealCx
3 ,f- Qx3 ) whereMoreover,
2
x3 = x3 + 'E x . y~
j=O J J
1 - 1 2 ( } 1 2
11 : Z ® T
/m =
P 1 , o .... ,Pr
® T/m
~I k
is defined by an ideal of the form
Let the imbedding X Y 1P3 be defined by the ideal
~ ~ k[x0 ,x1 ,x3
J.
Lift
w'
and 11' to T1/m3 by lifting the corresponding ideals, trivially, toNotice that set theoretically
Given these liftings 1jJ" and 11" , the obstructions for lifting a' and
~·
to T1;m3 are the elements:o(a') E H0(X,Nx® Oz) ® m2 /m3 k
o(l3') E H0 (X,Nx® Oz) ® m2 /m3
k
defined by:
""' 5 -
where for any h E OC ,
. . 2 .
o(a' )(h)
=
{h( x ,a,x ,a':'"'l ""l 2x , ._. a .x " "'l y. *) }r . , ,0 ' 0 0 . J 0 J l = '
"-'i
a = 1 , Vi
0
and where
o(i3')(x3)
=
o o(l3')(f-Q;x3 )=
J=O
. . . . 2 .
[ f x( ""l "'l ) ( "'l "'l "'l * } r
0 ,a,x ,a.2x - Q x ,a.,x ,a2x )( E a .x y .) . ,
' 0 0 0 ' 0 0 . J 0 J l=t
J=O The cup-product is therefore defined by the element
Suppose this cup-product is zero, then we may, in exactly the same way compute the ~d Massey-product. etc.,
We shall not bother to make these products explicite.. However, we shall deduce from their existence the following theorem.
Theorem (5.2.14) Let X, Y and Z be given o.s above, and assume char k > n. Then ciim{Y} Iz(X;Y)
=
2 unless there exists a hypersurface of the form:containing X. In that case Iz(X;Y) is non-singular of dimension 3 •
Proof. We know that the imbedding dimension of Iz (X; Y) is 2 or 3.,
In the first case is non-singular of dimension 2 at [Y}
(see (5.2 ..
13)),
at least when r= e
n+ 2 2) •Suppose that the dimension of Iz(X;Y) at [Y} is greater than 2 , thus 3. Then, obviously, Iz(X;Y) must be noll-singular at [Y}., Consequently all Massey products involved must be zero.
In
particular- 6 -
the cup-product described above must be zero.
Moreover, the tangent t ~(P.) of X at P. is normal to the
-x 1 1
direction x . (P. )nf (P. ) - Q . (P. )n = x. (P. ) (nf (P. ) - Q(P. )n ) •
J 1 - 1 J 1 -x3 J 1 7 1 1 -x3
Since nf(P.)- Q(P. )n is the normal at P. of the surface
- 1 1 -x3 1
at P. is contained V(f-Qx3 ) the tangent space of X l
in the tangent space of V(f-Qx3 ) tence of surjective homomorphisms
at P. 4 This implies the exis-
l
where ideal
mP./ 2 ~P-; 2 ( ~ )
mp
21 mP. ~ 1 ~- + f-I<I!;X3 P. ~ i/mp. + Otp.
l l l l l
mP.
l is the maximal ideal of 0 3 , (f-Qx3 )P. is the
IP ,P. 1
OLP.
l
is 1 the ideal 0{. .. 0 3 IP ,P.
l
0
Thus and since, by assumption, X cuts V(x3 ) regularly at Pi , the ideal ~- therefore being generated by
en
and x3 ' we find lf - Qx3 E otP. + (x3)P. ' 2
l l
and an element R2 . E 0 3 such that
, l IP ,Pi
(4)
Since the cup product is zero, there exist elements u E H0 (Z,Nz) ® m2;m3
v E H0(Y,Ny) ® m2 /m3, such that
o(a')=l(u)
v = L: (1 .. 'Q . . )y>ty*.
i.::
j lJ lJ l Jo(l3')
=
m(u)- n(v) •Since
we find:
a.D.d
- 7 -
f - Qx3
=
h 2 . (mod :£!p ) 2,~ i
=
o(a')(h2 .)=
l(u)(h2 .)=
u.(h2 .),~ ,~ ~ ,~
(f-Qx 3 )(x 0 ,a~x 0 ,~x
0 j=O , ?~ ~x y~)
J 0 J=
u. ~ (f-Qx3)-. < . I: Q •• "'iJ (P. ~ ~ )y~y~ J •~-J
Here we have used the fact that
n(u) = [n(u). }:' 1 ..
~ ~=
Subtracting the .first formula from the second, we obtain using ( 4) ,
or,
- ~j(P1) = xixj • 2 • R2 , 1 (P1 ) - Qii (Pl)
=
xi .. 2 R2,l (Pl)l
=
1, .... ,rfor i /: j , 1 = 1, ... , r for
Since char k > n we may assume char k /: 2 , therefore (5o2.12) garanties the existence of an (n-2) form Q2 E k[x0 ,x1,x2 J(n-2 )
~ 8 -
such that for and Q ..
]_]_
Thus
Put Q1
= -
Q , then by constru.ction the idealcx
3,f-Qx-..+ ? . L: < . Q . . lJ ]_ J ;y~y~)l _ J defines the imbedding
Now
for 1=1, ... ,r therefore
and, since ~ 1 + Q2 E !£p = Otp +
Cx
3)p ,' 1 1 1
the existence of elements h3 1 E 0(. p and
' 1
we deduce fron this R3 ,1 E 0 3 such that
JP ,Pl
Now computing the Massey-products one after the other, knowing they are vanishing, we obtain a series of forms ~ E k[x0 ,x1 ,x2 J(n-i) such that the ideal
defines the imbedding
for all q _:: 1 ..
y ~ T1/mn+q ~ 1P3~ T1/mn+q
T
Consider the universal family
- 9 -
and let 0 be the local ring of Iz (X; Y) at (Y} .. Take the base change Spec(O) ~ Iz(X;Y) and consider the corresponding family
Spec(O)
We know that 0 "
=
T • 1 Let17
be the ideal of O[x0 ,x1,x2,x3J
defining the imbedding Y ~ ]?3 ® 0 • What we have proved above
0 k
amounts to the following
This, however, implies that the hypersurface V(f
+.~ ~x~)
of JP3® 0~=1 k
-
containing a component of the closed contains a component of y0
fiber, i .. eo containing a component of our original Y ..
In fact, dehomogenizing at xj , j
=
o, .... , 3 we find, using [Se](II, 11, Cor 4) that there exist elements m. E m and
J -o
x0 x1 x2 X;z.
0 [ - - - -"'-] x.'X.'X.'X. such that·.
J J J J
1 n n i
( - ) ( f xj + i=1~ L: Q. x3) ( 1 + m . g . )
J J
denotes the ideal
tJ
dehomogenized at X. owhere
h
J xjLet
1D
be any prime containing41
such that a component of contained in V(1) , then obviously ( 1 + m .g.) %. rf)J J
rx.
J
thus
Y is
- 10 --
n .
f +I: . ,., Q.x~~
3
E r"P· }~=I
n . 3
Consequently the surface V(f +i:1 Qix'3) of JP contains a 0omponent of im cp containing a component of Y.
Since this component of i.m cp must necessarily contain infinite
n .
many points of X , we have proved that X c V(f + I: Q x~)
- i=1 i 3 o Q.EoD ..
Bibliograp;ro::
[La] Laudal, OoAo: Sections of functors and the problem of lifting (deforming)algebraic structureso
Preprint Series no~ 24(1975), Institute of Mathematics, University of Osloo