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F U L L P A P E R

Unique continuation for the magnetic Schrödinger equation

Andre Laestadius

1

| Michael Benedicks

2

| Markus Penz

3

1Department of Chemistry, Hylleraas Centre for Quantum Molecular Sciences, University of Oslo, Oslo, Norway

2Department of Mathematics, Uppsala University, Uppsala, Sweden

3Max Planck Institute for the Structure and Dynamics of Matter, Hamburg, Germany

Correspondence

Andre Laestadius, Department of Chemistry, Hylleraas Centre for Quantum Molecular Sciences, University of Oslo, P.O. Box 1033 Blindern, N-0315 Oslo, Norway.

Email: [email protected]

Funding information

Austrian Science Fund, Grant/Award Number:

J 4107-N27; H2020 European Research Council, Grant/Award Number: 639508;

Norges Forskningsråd, Grant/Award Number:

262695; Vetenskapsrådet, Grant/Award Number: 2016-05482

Abstract

The unique-continuation property from sets of positive measure is here proven for the many-body magnetic Schrödinger equation. This property guarantees that if a solution of the Schrödinger equation vanishes on a set of positive measure, then it is identically zero. We explicitly consider potentials written as sums of either one-body or two-body functions, typical for Hamiltonians in many-body quantum mechanics.

As a special case, we are able to treat atomic and molecular Hamiltonians. The unique-continuation property plays an important role in density-functional theories, which underpins its relevance in quantum chemistry.

K E Y W O R D S

Hohenberg-Kohn theorem, Kato class, magnetic Schrödinger equation, molecular Hamiltonian, unique-continuation property

1 | I N T R O D U C T I O N

Within the Schrödinger model for quantum systems of (interacting) electrons, in order to be able to describe interesting phenomena like the Zee- man effect, the quantum Hall effect, or the Hofstadter butterfly one has to include the effects of both an electric and a magnetic field. Hohenberg and Kohn showed for systems without magnetic fields that the one-body ground-state particle density determines the electric (scalar) potential up to a constant.[1]Strictly speaking, the particle density determines at most one potential (modulo an additive constant) since some densities are not associated with any potential.[2]The above correspondence between densities and potentials constitutes the theoretical foundation on which density functional theory (DFT)—a ubiquitous tool in quantum chemistry and materials science[3,4]—is built.

In the presence of magnetic fields though, the approach of Hohenberg and Kohn to set up a universal density functional requires more than just the particle density due to the fact that an additional vector potential enters the system's Hamiltonian. Both the paramagnetic current density and the total (physical) current density have been suggested as basic variables alongside the particle density[5–7]and the resulting framework is called current density functional theory (CDFT). For the theory that uses the paramagnetic current density, counterexamples to a Hohenberg- Kohn theorem are known,[8,9]although a weaker version still holds. Note that even for degenerate systems the weaker version is enough to define a universal paramagnetic current density functional.[10]Diener has presented an argument[7]for establishing a full Hohenberg-Kohn theorem using the total current density. However, as first noted in Reference [11], the argument is at best incomplete.

For more detailed accounts on the existence of generalized Hohenberg-Kohn theorems within CDFT see References [9, 11, 12], and for related and positive results within the Maxwell-Schrödinger theory and quantum-electrodynamical DFT see References [13–15]. An interesting and recent develop- ment is also given in Reference [16] where the existence of generalized Hohenberg-Kohn theorems is further explored. A different route, where a Hohenberg-Kohn result comes for free by virtue of the convex-analytic properties of aregularizedenergy functional was taken in References [17, 18]. It was specifically implemented for CDFT in Reference [19] and can even be used to prove convergence of the associated Kohn-Sham iteration Scheme.[20]

This is an open access article under the terms of the Creative Commons Attribution License, which permits use, distribution and reproduction in any medium, provided the original work is properly cited.

© 2020 The Authors.International Journal of Quantum Chemistrypublished by Wiley Periodicals, Inc.

Int J Quantum Chem.2020;120:e26149. http://q-chem.org 1 of 12

https://doi.org/10.1002/qua.26149

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The current work arises as a natural ingredient for proving a generalized Hohenberg-Kohn theorem in total (physical) CDFT. It addresses the property that a solution of the magnetic Schrödinger equation cannot vanish on a set of positive measure, a property called unique con- tinuation, see Definition 1. Unique continuation is also a fundamental property for solutions of the magnetic Schrödinger equation in its own right and has been well-studied.[21–26]In the context of CDFT the issue was first raised in Reference [9]. As far as DFT and CDFT are con- cerned, it is useful to have the assumptions guaranteeing the unique-continuation property as particle-number independent as possible (at least avoid increasing integrability constraints with increasingN), which is a difficult task. In the present work we obtain results that are adapted to the many-body Schrödinger equation and that furthermore include vector potentials, building on the results of Kurata[25] and Regbaoui.[26]This means that the specific structure of the potentials is beneficially taken into account. The main results, Theorem 6 and Cor- ollary 8, that include the singular Coulomb potentials of atoms and molecules as a special case (Corollary 9), are formulated in terms of the Kato classKnlocand its generalizationKn,δloc, withn= 3 andn= 6 (Definition 3). Although we cannot answer the question of the existence of a gener- alized Hohenberg-Kohn theorem for the total current in CDFT, we exemplify the use of the unique-continuation property in a limited special case (Corollary 11).

2 | U N I Q U E - C O N T I N U A T I O N P R O P E R T Y A N D T H E H O H E N B E R G - K O H N T H E O R E M

In the most simple setting of only one particle and without vector potential, it is known that the (unique) ground stateψinH1(R3) can be chosen to be strictly positive, see Theorem 11.8 in Lieb-Loss.[27]This means that we can setρ1/2=ψ> 0 and the following relation to the scalar potential vmust hold (from the Schrödinger equation, here written as [−Δ+v]ψ=eψ)

v xð Þ=e+Δρð Þx1=2

ρð Þx1=2 , x∈R3, ð1Þ

whereΔdenotes the Laplacian andeis the ground-state energy. Conversely, given a particle densityρwe can ask if a potentialvexists such that the givenρis the ground-state density of that potential. For the one-particle case, this problem has been studied by Englisch and Englisch[2]and was answered in the negative even for well-behaved densities (N-representable densities). Corollary 3 in Reference [28] (including the additional constraintΔρ1/2≤Cρ1/2andρ−1∈L1locbesidesN-representability) provides sufficient conditions for one-particlev-representability, that is,vcan be computed fromρas given in Equation (1) andρis the ground-state density of thatv.

Returning to the generalN-electron case without magnetic field, we first recall the Hohenberg-Kohn theorem: Given two systems, ifρ12

thenv1=v2+ constant, whereρk,k= 1,2, is the ground-state particle density of the corresponding system defined by the potentialvk. The proof of this result relies on the fact that ifψis a ground state of both systems, thenPN

k= 1ðv1ð Þxk −v2ð Þxk Þψ= constant×ψ. Ifψdoes not vanish on a set of positive (Lebesgue) measure we havev1=v2+ constant almost everywhere. The proof can then be completed by means of the variational prin- ciple, using the Hohenberg-Kohn argument by reductio ad absurdum.[1](Note that a strict inequality in the variational principle is not needed, see, eg, Reference [29] and that the results also hold for systems with degeneracy.[2])

In this article we address the more general case ofNinteracting, nonrelativistic (spinless) particles subjected to both a scalar and a vector potential. The fundamental question then is, whether any eigenfunction of the corresponding Hamiltonian

HN=XN

j= 1

irj+A xj 2

+v xj +X

l<j

u x j,xl

" #

ð2Þ

can be zero on a set of positive measure without being identically zero. This is a problem ofunique continuation.

Definition 1 We say that the Schrödinger equation HNψ= eψhas the unique-continuation property (UCP) from sets of positive (Lebesgue) measure if a solution that satisfiesψ= 0 on a set of positive measure is identically zero. Furthermore, the Schrödinger equation is said to have the strong UCP if when- everψvanishes to infinite order at some point x0, that is, for all m > 0

ð

jx−x0j≤rjψð Þxj2dx=Oð Þrm ðr!0Þ,

thenψ is identically zero. Additionally, ifψ = 0 on a non-empty open set implies that ψ is identically zero, then the Schrödinger equation has the weak UCP.

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Remark 1 The strong UCP implies the weak UCP. The UCP from sets of positive measure allows us to concludeψ6¼0 almost everywhere for any eigen- function of HN.

There exists a considerable amount of literature that treats the UCP for differential inequality |Δψ|≤|ξ1||rψ| + |ξ2||ψ|.[21–26] In particular if ξ1∈Lnlocð ÞRn andξ2∈Ln=2locð Þ, the corresponding differential equationRn Δψ=ξ1rψ+ξ2ψhas the UCP from sets of positive measure.[26]Note that suchLplocconstraints become more restrictive with increasing particle number, since the dimension of the configuration spacenenters in the con- ditions. Directly applied toHNψ=eψthis means that if a solutionψin the Sobolev spaceH2N=locðN+ 2ÞR3N

vanishes on a set of positive measure,

XN

j= 1

½v xj +A xj 2+irjA xj

+X

l<j

u xj,xl

∈L3N=2loc R3N ,

and each component ofAbelongs toL3NlocR3N

, thenψis identically zero.

Such results are used by Lammert,[30]particularly in his Theorem 5.1, to give a mathematically precise proof of the Hohenberg-Kohn theo- rem[1]in DFT including the UCP as remarked by Lieb.[31]Yet he does not consider magnetic fields and the constraints are very susceptible to the particle number. A recent effort by Garrigue[29]removed the dependence on particle numbers for the constraints on the scalar potential by exploi- ting their specific shape in the context of many-body (molecular) Hamiltonians. Reference [29] also contains a rigorous proof of the Hohenberg- Kohn theorem including all the mathematical details for potentialsv∈Lploc R3,p> 2.

3 | P R E R E Q U I S I T E S

Let the Hamiltonian HN be as in Equation (2). The Schrödinger equation is then given by HNψ = eψ. We write HN = TA+V+U, where TA=PN

j= 1irj+A xj 2

,rj= ∂x1 j

,∂x2

j

,∂x3

j

andxj=x1j,x2j,x3j

∈R3are the coordinates of thejth electron. Here we use (irj+A(xj))2inTAinstead of (−irj+A(xj))2in order to follow the notation in Kurata.[25]We use a slight variation of atomic unitsℏ= 2me= 1 andqe=−1, such that the Laplace operator appears without a factor 1/2.

The electric potentialVis a one-body potential given byV xð Þ=PN

j= 1v xj withv:R3!R. The two-particle interactionUbetween the electrons is modeled byU(x) =P

1≤j<l≤Nu(xj,xl), for some nonnegative functionuonR3×R3. We setW=V+U. Furthermore,A:R3!R3denotes the vec- tor potential, from which the magnetic field is obtained byB=r×A. With the notationA xð Þ= A xj

N

j= 1, the Schrödinger equation is rewritten as

−Δψ+ 2iArψ+ðWA−eÞψ= 0, ð3Þ

whereWA=W+j jA2+iðrAÞ.

A functionf∈L2locð ÞRn belongs to the Sobolev spaceHklocð ÞRn iffhas weak derivatives up to orderkthat belong toL2locð Þ. Let the set of infi-Rn nitely differentiable functions with compact support onR3Nbe denoted byC0R3N

. We say thatψ∈H1locR3N

is a solution of Equation (3) in the weak sense, which will be our standard notion for solutions from here on, if for allφ∈C0R3N

ð

R3Nrψrφdx+ 2i ð

R3NA rð ψÞφdx+ ð

R3NðWA−eÞψφdx= 0: ð4Þ

The present work takes off from the following result:

Theorem 2 (Theorem 1.2 in Regbaoui[26]).LetN≥1. Assume thatWA∈L3N=2loc R3N

and each component ofAis an element ofL3NlocR3N

.Then the Schrödinger equation has the UCP from sets of positive measure, that is, if a solutionψ∈H2N=locðN+ 2ÞR3N

vanishes on a set of positive measure then it is identically zero.

Remark 2 See also Theorem 1.1 in Regbaoui[26]for the strong UCP and Wolff[23]for the weak UCP.

If one employs Theorem 2 withN= 1, since there is no two-particle interaction it suffices to assume thatv,|A|2andrAare elements of L3=2loc R3 to obtain the UCP from sets of positive measure. With increasing particle number, however, the assumptions on the potentialsv,u, and Aare such that they rule out most types of singularities. On the other hand, the particle-number dependence that enters inH2N=locðN+ 2Þfulfills the inequality 2N/(N+ 2)≤2 for allN. Following Kurata[25]theLplocconstraints, withpproportional toN, can be avoided.

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Definition 3 A function f∈L1locð ÞRn belongs to the Kato class Knloc, n6¼2, if for every R > 0, lim

r!0 +ηKð Þr;f = 0, where

ηKð Þr;f = sup

jxj≤R

ð

Brð Þx

jf yð Þ j x−y j jn−2dy:

Furthermore, f∈Kn,locδKnloc,δ> 0, if for every R > 0

r!0 +lim sup

jxj≤R

ð

Brð Þx

jf yð Þ j x−y

j jn−2 +δdy= 0:

We writef=f+−f, wheref(f+) is the negative (positive) part offgiven byf(x) = max(−f(x), 0) (f+(x) = max(f(x), 0)). Lety∈R3Nbe fixed and forx= (x1,…,xN)∈R3N(cf. the notation in Kurata[25])

a xð Þ=jA xð Þj2,

byð Þx =jx−yj2XN

j= 1

B xj

2, Qyð Þx = 2Wð +ðx−yÞrWÞ: With the notation above, we formulate.

Assumption 1 Suppose

rA∈L2locR3 ,

Aj∈L4loc R3 Ajcomponent ofA , a,by,W,Qy∈K3Nloc for fixedy∈R3N

,

and that for somer0> 0

ðr0 0

θyð Þr

r dr<∞ ð5Þ

holds, whereθy(r) =ηK(r; Qy) +ηK(r; by)1/2.

Remark 3 Remark 1.2 in Kurata[25]gives by,Qy∈K3N,δloc , for someδ> 0, as a sufficient condition for Equation (5) to hold.

Remark 4 The main condition inAssumption 1is with respect to the Kato class Knloc, n = 3 N being the dimensionality of the underlying configuration space. This condition isoptimalin the sense that the class cannot be enlarged tosmallerorders than n = 3 N, or the UCP will be lost. This follows from the inclusion LplocKnlocfor all p > n/2 and a sharp counterexample provided in Reference [32] for a potential in Lp, p < n/2. So if the order of the Kato class would be any m < n then it also includes Lplocwith m/2 < p < n/2 and that is ruled out by the given counterexample.

The following is obtained by adapting Corollary 1.1 in Kurata[25](denoted Lemma 5 below). For the sake of simplicity, and since it is enough for our purposes here, we make the restrictions to real-valuedVandU. In the sequel we use the notation |F| for the Frobenius norm (also called the Hilbert-Schmidt norm) of a matrix (Fj,l)j,l.

Theorem 4 Suppose Assumption 1. Ifψ∈H2locR3N

is a solution of (3) and vanishes to infinite order atx0∈R3N,thenψis identically zero. Thus the Schrödinger equation has the strong UCP.

Lemma 5 (Corollary 1.1 in Kurata[25]).Let n≥3, x0∈Rnbe fixed, x=x1,…,xn

∈Rn,Ae=eA1,…,Aen

:Rn!Rn,We:Rn!R, F= Fj,l n j,l= 1 with Fj,l=∂Aej=∂xl−∂eAl=∂xj,and suppose that

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Aej∈L4locð Þ,Rn reA∈L2locð Þ,Rn jeAj2∈Klocn , x−x0

j jj jF

ð Þ2∈Knloc, ð6Þ

and

We∈Knloc, 2We+ðx−x0ÞrWe

∈Knloc: ð7Þ

Furthermore assume, for somer0> 0, Ðr0

0 ηK r; 2 We+ðx−x0ÞrWe

Kr;ðjx−x0j jFjÞ21=2 dr

r <∞ ð8Þ

holds. Then ifψ∈H2locð ÞRn satisfies

Xn

j= 1

i∂

∂xj+Aejð Þx

2

+W xeð Þ

!

ψ= 0 ð9Þ

and vanishes to infinite order atx0, it follows thatψis identically zero.

Proof of Theorem 4 We will show that Assumption 1 directly fulfills all the conditions of Lemma 5 that thus becomes applicable. Letn = 3 N and W = We −e.By Assumption 1, (7) is then fulfilled. The choiceà = AimpliesTA=ir+eA2

and Equation (3) can be written as Equation (9).

Each component ofA∈L4loc R3 yieldsAej∈L4locR3N

for j= 1,…, 3 N.FromreA=PN

k= 1rkA xð Þk andrA∈L2loc R3,we obtainreA∈L2locR3N . Since a= |Ã|2,it holds thatjeAj2∈K3Nloc.Moreover, the matrixFsatisfies

x−x0 j jj jF

ð Þ2=jx−x0j2X3N

j,l= 1

Fj,l2= 2bx0ð Þ,x ð10Þ

sinceFcontainsNrepeated blocks of sub matrices of the form

0 −B3 xj B2 xj

B3 xj 0 −B1 xj

−B2 xj B1xj 0 2

64

3 75:

This establishes Equation (6).

From Equation (5),We=W−eand Equation (10), we conclude that Equation (8) holds. Lemma 5 gives the strong UCP for Equation (3) and the

proof is complete. □

Remark 5 As stated in Remark 1.1 in Kurata,[25]Lemma 5 and thus Theorem 4 also holds if inAssumption 1, K3Nloc is replaced by K3Nloc+FplocR3N , 1 < p≤3 N/2. Here FplocR3N

is the Fefferman-Phong class and in this case a solution must be an element of H2locR3N

\LlocR3N

, and there is an addi- tional condition onV.

4 | M A I N R E S U L T S

Theorem 4 above establishes the strong UCP under Assumption 1. If in addition the negative part ofvis locallyL3/2(R3) summable we obtain the UCP from sets of positive measure:

Theorem 6 Suppose Assumption 1. If in additionv∈L3=2loc R3 andψ∈H2locR3N

solves (3) and vanishes on a set of positive measure, thenψis identically zero. Consequently, the Schrödinger equation has the UCP from sets of positive measure.

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Remark 6 The requirement u≥0 can be relaxed if one assumes that u(x1,x2) = u0(x1−x2) (see Lemma A.2 in Lammert[30]).

If the strong UCP can be obtained under other assumptions than Assumption 1, the following corollary can be used to obtain the UCP from sets of positive measure.

Corollary 7 Suppose the strong UCP for the Schrödinger equation (not necessarily by means of Assumption 1), then the constraint v+j jA2+iðrAÞ∈L3=2loc R3 gives the UCP from sets of positive measure.

Due to the particular form of the potentials, we can write

W xð Þ=X

j

v xj +1 2

X

j6¼l

u x j,xl :

BecauseQyis defined as the negative part of the function 2W+ (x−y)rW, we have with the choicex0=ðx0,…,x0Þ∈R3N, for fixedx0∈R3, 0≤Qx0ð Þx =Qx

0ð Þx ≤X

j

q1;x

0 xj +X

j6¼l

q2;x

0xj,xl

ð11Þ

for some functionsq1;x0andq2;x0. (See below the proof of Corollary 9, where this decomposition is done for the choice ofWcorresponding to the molecular case.) Furthermore,

bx0ð Þ=x bx0ð Þx =XN

j,l= 1

xj−x0 2jB xð Þlj2

can be split as

bx0ð Þ=x X

j

b1;x0 xj +X

j6¼l

b2;x0xj,xl :

We can now formulate our main result that includesHNmodeling atoms and molecules, and where the exponents in the integrability con- straints are independent of the particle numberN.

Corollary 8 ForN≥2 andx0∈R3fixed, suppose

rA∈L2loc R3, Aj∈L4locR3 , j jA2∈K3loc,

b1;x0∈K3,locδ, b2;x0∈K6,locδ: ð12Þ

Further, letv∈L3=2loc R3 ,v∈K3loc, andu∈K6loc, as well asQx0satisfying(11)withq1;x0∈K3,δlocandq2;x0∈K6,δloc. Then the Schrödinger equation(3)has the UCP from sets of positive measure.

In particular, the magnetic Schrödinger equation has the UCP from sets of positive measure forHNmodeling atoms and molecules in magnetic fields if just Equation (12) is fulfilled.

Corollary 9 ForN≥2, suppose the magnetic field is such that Equation (12) holds. Then with

v xð Þ1 =−XMnuc

j= 1

Zj

jxnuc;j−x1j, u xð1,x2Þ= 1 jx1−x2j,

wherexnuc;j∈R3andZj>0 are the positions and charges of theMnucnuclei, respectively, the UCP from sets of positive measure holds for the Schrödinger equation.

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5 | A P P L I C A T I O N T O C D F T

In the presence of a magnetic field, no equivalence of a (general) Hohenberg-Kohn result exists at present.[9,11]However, we shall now address how the UCP from sets of positive measure for the magnetic Schrödinger equation plays an important role in the argument for restricted Hohenberg-Kohn theorems in CDFT and the nonuniversal variant magnetic-field density-functional theory (BDFT) of Grayce and Harris.[33]Given a wave functionψ, define the particle density and the paramagnetic current density according to

ρψð Þx =N ð

R3ðN−1Þjψðx,x2,…,xNÞj2dx2…dxN, jpψð Þx =N Im

ð

R3ðN−1Þψðx,x2,…,xNÞ rxψðx,x2,…,xNÞdx2…dxN:

For a vector potentialAwe may compute the total current density by the sumj=jpψψA. Now, fix the particle numberNas well as the two- particle interactionu(eg,u(x1,x2) = |x1−x2|1) and writeHN=H(v,A). Ifψis a ground state for somevandA, that is,H(v,A)ψ=eψ, whereeis the ground-state energy, thenρψ,jpψ, andj=jpψψAare called ground-state densities ofH(v,A). Whether the ground-state particle densityρand the total current densityjdeterminevandA(up to a gauge transformation) is still an open question in the general case.[9,11](For the ground-state density pair (ρ,jp) it is well-known that this density pair does not determine the potentialsvandA.[8])

Now, assume that two systems with HamiltoniansH(v1,A1) andH(v2,A2) have the same ground-state particle density (i.e.,ρ12=ρ) and r×A1=r×A2=B. Suppose thatvk,Akfork= 1,2, andBfulfill Assumption 1 and the requirements given in Theorem 6. Since there exists a functionfsuch thatA1=A2−rf, the variational principle yields

e1≤hψ2,H vð1,A1Þψ2i≤e2+ ð

R2ðv1−v2Þρdx, whereψ2is the ground state ofH(v2,A2−rf). Switching the indices, we find that

e1−e2= ð

R2

v1−v2 ð Þρdx:

Consequently,ψ2is a ground state of bothH(v1,A1) andH(v2,A2−rf), which leads to H vð 1,A1Þ−Hðv2,A2−rfÞ

½ ψ2=XN

j= 1

v1 xj −v2 xj

ψ2=ðV1−V2Þψ2=ðe1−e2Þψ2:

However, Theorem 6 allows us to concludeψ26¼0 and it followsv1=v2+ constant.

Theorem 10 Assumer×A1=r×A2= Band thatvk, Akfork = 1,2,andBfulfill Assumption 1 and take the requirements of Theorem6for H(v1,A1)andH(v2,A2)to hold. If the ground-state particle densities satisfyρ12,thenv1= v2+ Calmost everywhere for some constantC.

Remark 7 Theorem 10 is the Hohenberg-Kohn theorem for BDFT, first established by Grayce and Harris[33]but missing the UCP argument (see also Reference [9]).

Theorem 10 can be used to obtain

Corollary 11 Assume Assumption 1 and the requirements of Theorem 6 forH(v1,A1)andH(v2,A2) and that the ground-state densities fulfill ρ=ρ12, j = j1= j2.For systems withjp= 0,it followsB1= B2(evenA1= A2holds) andv1= v2+ Cfor some constantC.

Proof. For systems withjp= 0,j1=j2implies

ρA1=ρA2,

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sinceρ12=ρ. Theorem 6 givesρ> 0 almost everywhere and we may concludeA1=A2. Theorem 10 now gives the equalityv1=v2+Cfor

some constantC. □

6 | P R O O F S O F T H E M A I N R E S U L T S

Proof of Theorem 6 In the sequel letD = 3 N.By Assumption 1,the strong UCP holds for Equation (3) by Theorem4.Next, we follow the proof of Theorem 1.2 given after Lemma 3.3 in Regbaoui[26]and Lemma A.2 in Lammert.[30](Lemma A.2 corresponds to settingA = 0here, and moreover we exploitu≥0instead of the assumptionu(x1,x2) = u0(x1−x2).)We start by showing the following inverse Poincaré inequality for solutions of the Schrödinger equation:

For an arbitrary pointx0=x0;jN

j= 1∈RDandr≤r0

ð

Brð Þx0jrψð Þxj2dx≤C r2 ð

B2rð Þx0jψð Þxj2dx: ð13Þ

HereCis a positive constant that depends onr0> 0,v, andA(but is independent ofu≥0).

Chooseh∈C0ðB2rð Þx0Þthat satisfiesh(x) = 1 if |x−x0|≤r,h≤1 for |x−x0|≤2r, and |rh(x)|≤2r1. In the Schrödinger equation (4), we choose φ=h2ψand move all terms except one to the right hand side so that

ð

RDjhrψj2dx=−2 ð

RD

hðrψÞψrhdx−2i ð

RDA rð ψÞh2ψdx+ ð

RD

e−WA

ð Þj jhψ2dx: ð14Þ

We now bound each of the terms of the right hand side in Equation (14).

It is immediate that the first term is less or equal to 2khrψk2kψrhk2. Using the inequality 2ab≤a2/6 + 6b2, we obtain an upper bound

1 6 ð

RDjhrψj2dx+ 6kψrhk22: ð15Þ

To continue, letI1=−2iÐ

RDA rð ψÞh2ψdx. The Cauchy-Schwarz inequality together with 2ab≤a2/6 + 6b2yield I1≤1

6 ð

RDjhrψj2dx+ 6 ð

RD

j jA2j jhψ2dx: ð16Þ

For the last term of the right hand side in Equation (14), we use the definition ofWAand writee−WA=e−W−j jA2−iðrAÞ. Thus ð

RDðe−WAÞj jhψ2dx= ð

RDe−W−j jA2 hψ j j2dx−i

ð

RDðrAÞj jhψ2dx and it follows fromW=V++U+−V≥−Vthat

ð

RD

e−WA

ð Þj jhψ2dx≤ ð

RD

V+jej

ð Þj jhψ2dx+ ð

RDjðrAÞkhψj2dx: ð17Þ

DefineΘ=V+jej+ 6j jA2+j rAj, from Equations (15), (16), and (17) we obtain an upper bound for the right hand side of Equation (14) given by

1 3 ð

RDjhrψj2dx+ 6kψrhk22+ ð

RDΘj jhψ2dx: ð18Þ

With the notationΘ1=v+N1jej + 6|A|2+ jr Aj, the inequalityΘð Þx ≤PN

j= 1Θ1 xj holds. Furthermore, we have ð

RDΘð Þxj jhψ2dx≤XN

j= 1

ð

RDΘ1 xj j jhψ2dx=I2,

(9)

where the last equality definesI2.

By assumptionv∈L3=2loc R3 ,j jA2∈L2locR3 , andrA∈L2loc R3 , and it follows thatΘ1∈L3=2loc R3 . To bound the termI2from above, we closely follow Lammert[30]and defineeρð Þx1 =NÐ

R3ðN−1Þj jhψ2dx2dxN. ForM> 0 we letM0=kΘ1χB2rðx0;1Þχ1≥Mgk3=2, where the characteristic func- tion of a setXis denotedχX. Hölder's inequality gives

I2= ð

Θ1<M

f gΘ1eρdx1+ ð

Θ1≥M

f gΘ1eρdx1≤M hk kψ 22+M0k keρ 3,

and by a Sobolev inequality k keρ 3≤Creρ1=22

2 . A direct computation of rð~ρ1=2Þ, using the definition of ~ρ, shows that reρ1=2

2

2≤Ð

RDjrð Þhψ j2dx(see also the original argument of Lieb,[31]Theorem 1.1). From |a+b|2≤2|a|2+ 2|b|2, we get reρ1=2

2

2≤2 ð

RDjhrψj2dx+ 2kψrhk22: We chooseM> 0 such that 2CM0≤1/6 and then one has

I2≤1 6 ð

RD

hrψ j j2dx+1

6kψrhk22+M hk kψ 22: ð19Þ

Returning to Equation (18), we setC= 74 + 3Mrh 20i

=3 and use Equation (19) and |rh|≤2/rto conclude forr≤r0

1 2 ð

RDjhrψj2dx≤37

6kψrhk22+M hk kψ 22≤C r2 ð

B2rð Þx0j jψ2dx:

Hence Equation (13) holds.

Supposeψ∈H2locvanishes on a setEof positive measure. Almost every point ofEis a density point. Letx0be such a density point and let Br=Br(x0). Givenε> 0 there is anr0=r0(ε) so that (cf. (3.11) in Regbaoui[26])

jE\Brj

jBrj ≥1−ε, jEc\Brj

jBrj ≤ε, for r≤r0: ð20Þ

Lemma 3.3 in Regbaoui[26](or Lemma 3.4 in Ladyzenskaya-Ural'tzeva[34]) gives

ð

Br\Ecj jψ2dx≤CrD

jEjjBr\Ecj1=Dð

Br

j r ψ2 jdx ð21Þ

for some constantC. Applying the Cauchy-Schwarz inequality to the right hand side of Equation (21), we obtain ð

Br

ψ

j j2dx≤Cr2D

j jE2jBr\Ecj2=Dð

Br

rψ j j2dx

for some new constantC. Since |E|≥|E\Br|, Equation (20), and the inverse Poincaré inequality (13) allow us to conclude that ð

Br

ψ

j j2dx≤C ε2=D 1−ε ð Þ2r2

ð

Br

j j2dx≤C0 ε2=D 1−ε ð Þ2

ð

B2r

ψ

j j2dx: ð22Þ

Introduce the functionf rð Þ=Ð

Brj jψ2dx, fix an integernand chooseε> 0 so thatC0ε2/D/(1−ε)2= 2−n. Then Equation (22) can be written f(r)≤2−nf(2r). By iteration

f rð Þ0 ≤2knf2kr0

, r0≤21kr0

(10)

holds. For fixedrandkchosen such that 2−kr0≤r≤21kr0, it follows that

f rð Þ≤2−knfð2r0Þ≤ r r0

n

fð2r0Þ,

wherer0depends onn. Consequentlyfvanishes to infinite order, that is, for allmthere is anr0(m) such that

f rð Þ=ð

Br

ψ

j j2dx≤Cmrm, r≤r0ð Þm:

Thatψ= 0 follows now by the strong UCP given by Theorem 4. □

Proof of Corollary 7 This is a consequence of the proof of Theorem 6, sinceΘ1, by assumption, is an element ofL3=2loc R3 . □ Proof of Corollary 8 We first demonstrate that the conditions of Corollary8fulfills Assumption 1.Due to the particular form of the potentials, we make use of the following: Letf1∈K3,δlocandf2∈K6,δloc.Then bothPN

k= 1f1ð Þxk andP

k6¼lf2(xk, xl)are elements ofK3N,δloc .Similar statements forKncan be found in Simon[35] (Example F) and Aizenman-Simon[36](Theorem 1.4). We prove our claim by direct computations. Define Iδ1 and Iδ2 according to

Iδ1ð Þ=x XN

j= 1

ð

Brð Þ0

jf1 yj+xj

j y21++y2N

3N−2 +δ2 dy1dyN,

Iδ2ð Þ=x X

j6¼l

ð

Brð Þ0

jf2yj+xj,yl+xlj y21++y2N

3N−2 +δ2 dy1dyN:

We next demonstrate that

Iδ1ð Þx ≤CN ð

Br; 3ð Þx

jf1ð Þ jy1 y1−x1

j j3−2 +δdy1, ð23Þ

Iδ2ð Þx ≤CN ð

Br; 6ð Þx

jf2ðy1,y2Þ j y1,y2

ð Þ−ðx1,x2Þ

j j6−2 +δdy1dy2, ð24Þ

where the second index in the given ball-setsBr; 3(x)R3andBr; 6(x)R6refers to the respective dimensionality.

To show Equation (23), setq= (y2,…,yN) and note that

Iδ1ð Þx ≤N ð

Br; 3×Br; 3ðN−1Þ

jf1ðy1+x1Þ j y21+q2

3N−2 +δ2 dy1dq=CN

ð

Br; 3

jf1ðy1+x1Þ j ðr

0

q3ðN1Þ−1dq y21+q2

3N−2 +δ2

0

@

1 Ady1

=CN ð

Br; 3

jf1ðy1+x1Þ j y1 j j3N−2 +δ

ðr 0

q3N4dq 1 +ðq=jy12

3N−2 +δ2

0 BB

@

1 CC Ady1

≤CNJδ1 ð

Br; 3ð Þx1

jf1ð Þ jy1 y1−x1

j j3−2 +δdy1, where we have defined the integral

Jδ1= ð

0

s3N−4 1 +s2

ð Þ3N−2 +δ2 ds:

Now,Jδ1is finite since

Jδ1≤ð1 0

s3N−4ds+ ð

1

s−2−δds< +∞:

This establishes Equation (23). The proof of Equation (24) is similar and included for the sake of completeness. Setq= (y3,…,yN), then

(11)

I1≤N ð

Br; 6×Br; 3ðN−2Þ

ju yð 1+x1,y2+x2Þ j y21+y22+q2

3N−2 +δ2 dy1dy2dq=CN

ð

Br; 6

ju yð 1+x1,y2+x2Þ j ðr 0

q3ðN−2Þ−1dq y21+y22+q2

3N−2 +δ2

0

@

1 Ady1dy2

=CN

ð

Br; 6

ju yð1+x1,y2+x2Þ j y1,y2

ð Þ

j j3N−2 +δ ðr

0

q3N−7dq 1 +ðq=jðy1,y2ÞjÞ2

3N−2 +δ2

0 BB

@

1 CC Ady1dy2

≤CN ð

Br; 6ðx1,x2Þ

ju yð 1,y2Þ j y1,y2 ð Þ−ðx1,x2Þ

j j62 +δdy1dy2 ð

0

s3N−7 1 +s2 ð Þ3N−2 +δ2 ds:

Corollary 8 now follows from Theorem 6 (Equation (5) in Assumption 1 is fulfilled by Remark 3). □

Proof of Corollary 9 We first reduce the molecular case to the atomic one. Since the UCP from sets of positive measure is local, it can be applied to any open set in the domain individually. So instead of one singularity (theyof Assumption 1), we can treat an arbitrary (yet countable) number of singularities if they do not have an accumulation point. For this just choose an open cover{Uj}ofR3where each Ujcontains not more than one nucleus xnuc;j.It remains to show that allqxnuc;j,bxnuc;j belong to the respective local Kato classes and we are done if we prove the results for atoms.

In the sequel we let v(x1) = −Z|x1−xnuc|−1,xnuc∈R3,Z> 0, and u(x1,x2) = |x1−x2|−1. In this casev∈L3=2loc R3 and with the choice xnuc=ðxnuc,…,xnucÞ∈RD, we have withQxnucð Þ=x Qx

nucð Þx the equality

Qxnucð Þ=x X

j

−2Z jxj−xnucj+X

j6¼l

1

jxj−xlj +X

j

xj−xnuc

rj −Z jxj−xnucj

+1 2

X

j6¼l

xj−xnuc

rj+ðxl−xnucÞrl

1

jxj−xnuc

−ðxl−xnucÞ j

!

=ðV xð Þ+U xð ÞÞ≤2Vð Þx :

Thus, in this case we can chooseq1,xnuc=vandq2,xnuc= 0.

Furthermore, for 0 <δ< 1, we claim thatV,U∈KD,locδ. By the first part it suffices to showv∈K3,locδandu∈K6,locδ. Forv∈K3,locδ, we introduce polar coordinates with radiussand polar anglet. Then it holds thatdy= 2πs2sint dtdsandyx=−s|x|cost. Forf1(x) = |x|−1it follows that

ηKðr;f1Þ= sup

jxj≤R

ðr 0

ðπ

0

2πs1−δsintdt s2−2sjxjcost+j jx2

1=2

0 B@

1 CAds:

We integrate overt, use |s+ |x|−|s−|x|||≤2|x|, and the conclusion is obtained forv. In a similar fashion, foruwe establish that with f2(x) = |x1−x2|−1

ηKðr;f2Þ≤C ðr

0

ðr s1

s2ds2 s21+s22 2 +2δ

0

@

1

As21ds1≤Cr1−δ

such that it followsu∈K6,locδ, since ð

Brð Þ0

1 jy1−y2j

1

j jy62 +δdy1dy2≤C ðr

0

ðr 0

ðπ

0

2πs21s22sintdt s21−2s1s2cost+s22

1=2

! ds1ds2

s21+s22 2 +2δ

≤C ðr

0

ðr 0

s1+s2−js1−s2j

ð Þ

s21+s22

2 +2δ s1s2ds1ds2

≤C ðr

0

ðs1 0

s1s22ds2

s21+s22 2 +2δ+

ðr s1

s21s2ds2

s21+s22 2 +2δ

2 4

3 5ds1

≤C ðr

0

ðr s1

s2ds2 s21+s22

2 +2δs21ds1≤Cr1−δ:

The atomic case is now a consequence of Corollary 8. □

(12)

7 | C O N C L U S I O N

In this work we were able to show the unique-continuation property from sets of positive measures for the important case of the many-body magnetic Schrödinger equation for classes of potentials that are independent of the particle number. This is crucial in order to not artificially restrict the permitted potentials in large systems. We further specifically addressed molecular Hamiltonians, thus covering most cases that usually arise in physics.

A C K N O W L E D G M E N T S

AL is grateful for the hospitality received at the Max Planck Institute for the Structure and Dynamics of Matter while visiting MP. The authors want to thank Louis Garrigue for useful discussion that led to the inclusion of the molecular case, and Fabian Faulstich for comments and sugges- tions that improved the manuscript.

O R C I D

Andre Laestadius https://orcid.org/0000-0001-7391-0396

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How to cite this article:Laestadius A, Benedicks M, Penz M. Unique continuation for the magnetic Schrödinger equation.Int J Quantum Chem. 2020;120:e26149.https://doi.org/10.1002/qua.26149

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