R E S E A R C H Open Access
Some new Hardy-type inequalities for Riemann-Liouville fractional q-integral operator
Lars-Erik Persson1,2*and Serikbol Shaimardan3
*Correspondence: larserik@ltu.se
1Luleå University of Technology, Luleå, 971 87, Sweden
2Narvik University College, P.O. Box 385, Narvik, 8505, Norway Full list of author information is available at the end of the article
Abstract
We consider theq-analog of the Riemann-Liouville fractionalq-integral operator of ordern∈N. Some new Hardy-type inequalities for this operator are proved and discussed.
MSC: Primary 26D10; 26D15; secondary 33D05; 39A13
Keywords: inequalities; Hardy-type inequalities; Riemann-Liouville operator; integral operator;q-calculus;q-integral
1 Introduction
In FH Jackson definedq-derivative and definiteq-integral [] (see also []). It was the starting point ofq-analysis. Today the interest in the subject has exploded. Theq-analysis has numerous applications in various fields of mathematics,e.g., dynamical systems, num- ber theory, combinatorics, special functions, fractals and also for scientific problems in some applied areas such as computer science, quantum mechanics and quantum physics (see,e.g., [–]). For further development and recent results inq-analysis, we refer to the books [, ] and [] and the references given therein. The first results concerning integral inequalities inq-analysis were proved in by Gauchman []. Later on some further q-analogs of the classical inequalities have been proved (see [–]). Moreover, in
Maligrandaet al.[] derived aq-analog of the classical Hardy inequality. Further devel- opment of Hardy’s original inequality from (see [] and []) has been enormous.
Some of the most important results and applications have been presented and discussed in the books [, ] and []. Hence, it seems to be a huge new research area to investigate which of these so-called Hardy-type inequalities have theirq-analogs.
The aim of this paper is to obtain some q-analogs of Hardy-type inequalities for the Riemann-Liouville fractional integral operator of ordern∈Nand to find necessary and sufficient conditions of the validity of these inequalities for all non-negative real functions (see Theorems . and .).
The paper is organized as follows. In order not to disturb our discussions later on, some preliminaries are presented in Section . The main results can be found in Section , while the detailed proofs are given in Section .
©2015 Persson and Shaimardan. This article is distributed under the terms of the Creative Commons Attribution 4.0 Interna- tional License (http://creativecommons.org/licenses/by/4.0/), which permits unrestricted use, distribution, and reproduction in any medium, provided you give appropriate credit to the original author(s) and the source, provide a link to the Creative Commons license, and indicate if changes were made.
2 Preliminaries
First we recall some definitions and notations inq-analysis from the recent books [, ]
and [].
Letq∈(, ). Then aq-real number [α]qis defined by [α]q:= –qα
–q , α∈R, wherelimq→–q–qα =α.
Theq-analog of the binomial coefficients is defined by
[n]q! :=
ifn= , []q×[]q× · · · ×[n]q ifn∈N,
n k
q
:= [n]q! [n–k]q![k]q!. We introduce theq-analog of a polynomial in the following way:
(x–a)nq:=
ifn= ,
(x–a)(x–qa)· · ·(x–qn–a) ifn∈N, () (x–a)n+mq = (x–a)mq
x–qman
q, n,m= , , , . . . . ()
Theq-gamma functionqis defined by q(n+ ) := [n]q!, n∈N.
Forf : [,b)→R, <b≤ ∞, we define theq-derivative as follows:
Dqf(x) :=f(x) –f(qx)
( –q)x , x∈[,b).
Clearly, if the functionf(x) is differentiable at a pointx∈(, ), thenlimq→Dqf(x) =f(x).
Let <a≤b<∞. The definiteq-integral (also called theq-Jackson integral) of a func- tionf(x) is defined by the formulas
a
f(x)dqx:= ( –q)a ∞
k=
qkf qka
. ()
Moreover, the improperq-integral of a functionf(x) is defined by ∞
f(x)dqx:= ( –q) ∞ k=–∞
qkf qk
, ()
provided that the series on the right-hand sides of () and () converge absolutely.
Suppose thatf(x) andg(x) are two functions which are defined on (,∞). Then ∞
f(x)Dq
g(x)
= ∞
j=
f qj
g qj
–g qj+
. ()
Letbe a subset of (,∞) andX(t) denote the characteristic function of. For allz:
<z<∞, we have that ∞
X(,z](t)f(t)dqt= ( –q)
qi≤z
qif qi
()
and ∞
X[z,∞)(t)f(t)dqt= ( –q)
qi≥z
qif qi
. ()
Al-Salam (see [] and also []) introduced the fractional q-integral of the Riemann- Liouville operatorIq,nof ordern∈Nby
Iq,nf(x) := q(n)
x
Kn–(x,s)f(s)dqs, whereKn–(x,s) = (x–qs)n–q .
Next we will present a lemma (Lemma .) concerning discrete Hardy-type inequalities which are proved in []. In this paper all authors studied inequalities of the form
∞ j=
urj (Snf)jr
r
≤C ∞
i=
vpifip p
, ∀f ≥ ()
for then-multiple discrete Hardy operator with weights of the form (Snf)j=
∞ k=j
ω,k k
k=
ω,k k
k=
ω,k· · ·
kn–
kn–=
ωn–,kn–
kn–
i=
fi= ∞
i=j
An–(i,j)fi,
where u={ui}∞i=, v={vi}∞i=, ωi={ωi,k}∞k= are positive sequences of real numbers (i.e., weight sequences). She also studied inequality () for the operatorS∗ndefined by
Sn∗f
i:=
i
j=
fiAn–,(i,j),
which is the conjugate to the operatorSn, whereAn–,(i,j)≡ forn= and An–,(i,j) =
i
kn–=j
ωn–,kn–
i
kn–=kn–
ωn–,kn–· · · i
k=k
ω,k
forn≥.
We consider the following Hardy-type inequalities:
∞ j=–∞
urj (Snf)j
r
r
≤C ∞ i=–∞
vpifip p
()
and ∞ i=–∞
uri Sn∗f
i
r
r
≤C∗ ∞ i=–∞
vpifip p
. ()
In the sequel, for anyp> , the conjugate numberpis defined byp:=p/(p– ), and the considered functions are assumed to be non-negative. Moreover, the symbolMK means that there existsα> such thatM≤αK, whereαis a constant which may depend only on parameters such asp,q,r. Similarly, the caseKM. IfMKM, then we writeM≈K.
Lemma .
(i) Let <p≤r<∞andn≥.Then inequality()holds if and only if A(n) =max≤m≤n–Am(n) <∞,where
Am(n) =sup
k∈Z
∞ j=k
Apm, (j,k)v–pj
p k
i=–∞
Arn–,m+(k,i)uri r
, n∈N.
Moreover,A(n)≈C,whereCis the best constant in().
(ii) Let <p≤r<∞andn≥.Then inequality()holds if and only if A∗(n) =max≤m≤n–A∗m(n) <∞,where
A∗m(n) =sup
k∈Z
∞ i=k
Arm,(i,k)uri r k
j=–∞
Apn–,m+ (k,j)v–pj
p
, n∈N.
Moreover,A∗(n)≈C,whereCis the best constant in().
We also need the corresponding result for the case <r<p<∞, which was proved in [].
Lemma .
(i) Let <r<p<∞andn≥.Then inequality()holds if and only if B(n) =max≤m≤n–Bm(n) <∞,where
Bm(n) = ∞
i=–∞
∞ j=i
Apm, (j,i)v–pj
p(r–)p–r i
k=–∞
Arn–,m+(i,k)urk p–rp
× + ∞
j=i
Apm, (j,i)v–pj p–r
pr
, +Ei,j=Ei,j–Ei,j+,n∈N.
Moreover,B(n)≈C,whereCis the best constant in().
(ii) Let <r<p<∞andn≥.Then inequality()holds if and only if B∗(n) =max≤m≤n–B∗m(n) <∞,where
B∗m(n) = ∞
i=–∞
∞ j=i
Arm,(j,i)urj
p–rr i
k=–∞
Apn–,m+ (i,k)v–pk r(p–)p–r
× + ∞
j=i
Arm,(j,i)urj p–r
pr
, +Ei,j=Ei,j–Ei,j+,∀n∈N.
Moreover,B∗(n)≈C∗,whereC∗is the best constant in().
Let (a(n)i,j) be a matrix whose elements are non-negative and non-increasing in the second index for alli,j:∞>i≥j> –∞, and the entries of the matrixa(n)i,j satisfy the following (so- called discrete Oinarov condition):
a(n)i,j ≈ n
γ=
a(γ)i,kdk,jn,γ, γ = , , . . . ,n– ,n∈N ()
for all∞>i≥k≥j> –∞.
Remark . Note that the matrices (dγk,j,m), γ = , , . . . ,m, m≥, are arbitrary non- negative matrices which satisfy () (see []).
Moreover, in [] necessary and sufficient conditions for inequalities () and () were proved for matrix operators with a matrix (a(n)i,j) which satisfies (). For our purposes we need such characterization on the following form.
Lemma .
(i) Let <p≤r<∞and the entries of the matrix(a(n)i,j)satisfy condition().Then inequality()for the operator(A–f)j:=∞
i=ja(n)i,jfi,j∈Z,holds if and only if at least one of the conditionsB+<∞orB–<∞holds,where
B–=sup
k∈Z
∞ i=k
v–pi k j=–∞
a(n)i,jr
urj pr
p
,
B+=sup
k∈Z
k j=–∞
urj ∞
i=k
a(n)i,jp
v–pi r
pr .
Moreover,B+≈B–≈C,whereCis the best constant in().
(ii) Let <p≤r<∞.Let the entries of the matrix(a(n)i,j)satisfy condition().Then inequality()for the operator(A+f)i:=i
j=–∞a(n)i,jfj,i∈Z,holds if and only if at least one of the conditionsA+<∞orA–<∞holds,where
A–=sup
k∈Z
∞ i=k
uri k j=–∞
a(n)i,jp
v–pj r
pr ,
A+=sup
k∈Z
k j=–∞
v–pj ∞
i=k
a(n)i,jr
uri prp
.
Moreover,A+≈A–≈C,whereCis the best constant in().
3 The main results
Let <r,p≤ ∞. Then theq-analog of the two-weighted inequality for the operatorIq,n
of the form ∞
ur(x)
Iq,nf(x)r
dqx r
≤C ∞
vp(x)fp(x)dqx p
()
has several applications in various fields of science. In the classical analysis two-weighted estimates for the Riemann-Liouville fractional operator were derived by Stepanov for the case with parameters greater than one (see [, ]).
We consider the operatorIq,nof the following form:
Iq,nf(x) = q(n)
∞
X(,x](s)Kn–(x,s)f(s)dqs,
which is defined for allx> . Although it does not coincide with the operatorIq,n(they coincide at the pointsx=qk,k∈Z), we have the equality
∞
ur(x)
Iq,nf(x)r
dqx= ∞
ur(x)
Iq,nf(x)r
dqx.
Therefore, inequality () can be rewritten as ∞
ur(x)
Iq,nf(x)r
dqx r
≤C ∞
vp(x)fp(x)dqx p
. ()
Its conjugate operatorI∗q,ncan be defined by
Iq,n∗ f(s) := q(n)
∞
X[s,∞)(x)Kn–(x,s)f(x)dqx,
with the same kernel. The dual inequality of inequality () reads as follows:
∞
ur(x)
Iq,n∗ f(x)r
dqx r
≤C∗ ∞
vp(x)fp(x)dqx p
, ()
whereCandC∗ are positive constants independent off andu(·),v(·) are positive real- valued functions on (,∞),i.e., weight functions. In what follows we investigate inequal- ities () and ().
Let N= N∪ {}. Then, for ≤m≤n– ,m,n∈N, we use the following notations:
Qn–m = ∞
∞
X(,z](s)Kmp(z,s)v–p(s)dqs p(r–)p–r
× ∞
X[z,∞)(x)Kn–m–r (x,z)ur(x)dqx p–rp
×Dq ∞
X(,z](s)Kmp(z,s)v–p(s)dqs p–r
pr,
Qn–m = ∞
∞
X(,z](s)Kmr(z,s)ur(s)dqs p–rr
× ∞
X[z,∞)(x)Kn–m––p (z,x)v–p(x)dqx r(p–)p–r
×Dq ∞
X(,z](s)Kmr(z,s)ur(x)dqs p–r
pr,
Hmn–=sup
z>
∞
X[z,∞)(x)Kn–m–r (x,z)ur(x)dqx
r ∞
X(,z](s)Kmp(z,s)v–p(s)dqs p
, Hn–m =sup
z>
∞
X(,z](x)Kmr(z,x)ur(x)dqx
r ∞
X[z,∞)(s)Kn–m–p (s,z)v–p(s)dqs
p
,
A+(z) = ∞
X[z,∞)(x)ur(x) ∞
X(,z](t)Kn–p (x,t)v–p(t)dqt r
p
dqx r
,
A–(z) = ∞
X(,z](t)v–p(t) ∞
X[z,∞)(x)Kn–r (x,t)ur(x)dqx pr
dqt
p
.
A+(z) = ∞
X[z,∞)(t)v–p(t) ∞
X(,z](x)Kn–r (t,x)ur(x)dqx pr
dqt p
, A–(z) =
∞
X(,z](x)ur(x) ∞
X[z,∞)(t)Kn–p (t,x)v–p(t)dqt pr
dqx r
, Hn–= max
≤k≤n–Hkn–, Hn–= max
≤k≤n–Hn–k , A+q=sup
z>
A+(z), A–q=sup
z>
A–(z), A+q=sup
z>A+(z), A–q=sup
z>A–(z), Qn–= max
≤k≤n–Qn–k and Qn–= max
≤k≤n–Qn–k . Our main results read as follows.
Theorem .
(i) Let <r<p<∞.Then inequality()holds if and only ifQn–<∞.Moreover, Qn–≈C,whereCis the best constant in().
(ii) Let <p≤r<∞.Then inequality()holds if and only if at least one of the conditionsHn–<∞orA+q<∞orA–q<∞holds.Moreover,Hn–≈A+q≈A–q≈C, whereCis the best constant in().
Theorem .
(i) Let <r<p<∞.Then inequality()holds if and only ifQn–<∞.Moreover, Qn–≈C∗,whereC∗is the best constant in().
(ii) Let <p≤r<∞.Then inequality()holds if and only if at least one of the conditionsHn–<∞orA+q<∞,orA–q<∞holds.Moreover,Hn–≈A+q≈A–q≈C, whereCis the best constant in().
For the proofs of these results, we need the following lemmata of independent interest.
Lemma . Let x,t,s: <s≤t≤x<∞.Then
≤m≤n–max Kn–m–(x,t)Km(t,s)≤Kn–(x,s) ≤ n–
m=
n– m
q
Kn–m–(x,t)Km(t,s) ()
for m: ≤m≤n– ,n,m– ∈Nand where Kn–(x,s) = (x–qs)n–q . Lemma . Let f and g be non-negative functions on(,∞),α,β∈Rand
I(z) :=
∞
X(,z](t)f(t)dqt
α ∞
X[z,∞)(x)g(x)dqx β
.
Then
sup
z>
I(z) = ( –q)α+βsup
k∈Z
∞ j=k
qjf
qjα k i=–∞
qig qiβ
, ()
where at least one ofαandβis non-negative.
This result was proved in [], but for the readers’ convenience we will include in Sec- tion a proof which is slightly simpler than that in the Russian version given in [].
Lemma . Letα,β∈R+,K(·,·)be a non-negative function and I+(z) :=
∞
X[z,∞)(x)g(x) ∞
X(,z](t)K(x,t)f(t)dqt α
dqx β
, I–(z) :=
∞
X(,z](t)f(t) ∞
X[z,∞)(x)K(x,t)g(x)dqx α
dqt β
. Then
sup
z>
I+(z) =sup
k∈Z ( –q) k j=–∞
qjg qj
( –q) ∞
i=k
qiK qj,qi
f qiαβ
()
and
sup
z>
I–(z) =sup
k∈Z ( –q) ∞
j=k
qjf qj
( –q) k j=–∞
qjK qj,qi
g qjαβ
. ()
Lemma . Let Qn–m ,Qn–m <∞for <m≤n– .Then
Qn–m = ∞
i=–∞
( –q) ∞
t=i
qtKmp qi,qt
v–p
qtp(r–)p–r
× ( –q) i j=–∞
qjKn–m–r qj,qi
ur qjp–rp
× + ∞
n=i
( –q)qnKmr qi,qn
v–p
qnp–r
pr
and Qn–m =
∞
i=–∞
( –q) ∞
t=i
qtKmr qi,qt
ur qtp–rr
× ( –q) i j=–∞
qjKn–m–p qj,qi
v–p
qjr(p–)p–r
× + ∞
n=i
( –q)qnKmr qi,qn
ur
qnp–r
pr
,
where+En,i=En,i–En,i+.
4 Proofs
Proof of Lemma. Let <s≤t≤x<∞. First we prove the lower estimate. By using () we find that
Kn–m–(x,t)Km(t,s) = (x–qt)n–m–q (t–qs)mq
≤(x–qs)n–m–q (x–qs)mq
≤(x–qs)n–m–q
x–qn–msm q
= (x–qs)n–q =Kn–(x,s)
for <s≤t≤x<∞and ≤m≤n– ,m– ,n∈N. Hence,
≤m≤n–max Kn–m–(x,t)Km(t,s)≤Kn–(x,s), and the lower estimate in () is proved.
According to () we get thatK(x,t)K(t,s) =K(x,s)≡ forn= . Moreover, we have that
K(x,s) = (x–qs)q< (x–qt)q+ (t–qs)q
=
m=
m
q
K–m–(x,t)Km(t,s)
forn= .
This means that the inequality
Kn–(x,s) <
n–
m=
n–
m
q
Kn–m–(x,t)Km(t,s) ()
holds forn= . Our aim is now to use induction, and we assume that () holds forn=l– , l≥, and we will prove that it then holds also forn=l.
We use our induction assumption, make some calculations and obvious estimates and find that
Kl–(x,s) =Kl–(x,s)
x–ql–s
<
l–
m=
l–
m
q
Kl–m–(x,t)Km(t,s)
x–ql–s
<
l–
m=
l–
m
q
Kl–m–(x,t)Km(t,s)
x–ql–m–t+ql–m–t–ql–s
= l–
m=
l– m
q
Kl–m–(x,t)Km(t,s)
x–ql–m–t
+ l–
m=
l– m
q
Kl–m–(x,t)Km(t,s)ql–m–
t–qm+s
= l–
q
Kl–(x,t)K(t,s) + l–
m=
l– m
q
Kl–m–(x,t)Km(t,s)
+ l–
m=
ql–m–
l– m–
q
Kl–m–(x,t)Km(t,s) + l–
l–
q
K(x,t)Kl–(t,s)
= l–
q
Kl–(x,t)K(t,s)
+ l–
m=
ql–m–
l– m–
q
+ l–
m
q
Kl–m–(x,t)Km(t,s)
+
l– l–
q
K(x,t)Kl(t,s).
Since, for anym≥ (ql–m–l– m–
q+l– m
q=l– m
q), we get that Kl–(x,s) <
l–
m=
l–
m
q
Kl–m–(x,t)Km(t,s).
Hence, () holds also withn=lwhich, by the induction axiom, means that also the
upper estimate in () is proved. The proof is complete.
Proof of Lemma. From () and () it follows that
I(z) = ( –q)α+β
qj≤z
qjf
qjα
qi≥z
qig qiβ
.
Ifz=qk, then, fork∈Z, I(z) = ( –q)α+β
∞ j=k
qjf
qjα k i=–∞
qig qiβ
.
Ifqk<z<qk–, then, fork∈Z, I(z) = ( –q)α+β
∞ j=k
qjf
qjα k–
i=–∞
qig qiβ
.
Hence, fork∈Zandβ> , we find that
sup
qk≤z<qk–
I(z) = ( –q)α+β ∞
j=k
qjf
qjα k i=–∞
qig qiβ
.
Therefore sup
z>
I(z) =sup
k∈Z sup
qk≤z<qk–
I(z)
= ( –q)α+βsup
k∈Z
∞ j=k
qjf
qjα k i=–∞
qig qiβ
. ()
We have proved that () holds whereverβ> .
Next we assume thatα> . Letqk+<z<qk,k∈Z. Then we get that
I(z) = ( –q)α+βsup
k∈Z
∞ j=k+
qjf
qjα k i=–∞
qig qiβ
,
and analogously as above we find that
sup
qk+<z≤qk
I(z) = ( –q)α+β ∞
j=k
qjf
qjα k i=–∞
qig qiβ
,
and () holds also for the caseα> . The proof is complete.
Proof of Lemma. Letz=qk,k∈Z. By using () and () we have that
I+(z) = ( –q) k j=–∞
qjg qj
( –q) ∞
i=k
qiK qj,qi
f
qiαβ
.
For the casesqk+<z<qk,k∈Zandqk<z<qk–,k∈Z, we find that
I+(z) = ( –q) k j=–∞
qjg qj
( –q) ∞ i=k+
qiK qj,qi
f
qiαβ
and
I+(z) = ( –q) k–
j=–∞
qjg qj
( –q) ∞
i=k
qiK qj,qi
f
qiαβ
,
respectively.
Hence, we conclude that
sup
qk+<z<qk–
I+(z) = ( –q) k j=–∞
qjg qj
( –q) ∞
i=k
qiK qj,qi
f qiαβ
.
Sincesupz>I+(z) =supk∈Zsupqk+<z<qk–I+(z), we find that () holds. The identity () can be proved in a similar way as (). The proof is complete.
Proof of Lemma. Without loss of generality we may assume thatQn–m <∞. By using (), () and () we can deduce that
Qn–m = ∞
i=–∞
∞
X(,qi](s)Kmp qi,s
v–p(s)dqs p(r–)p–r
× ∞
X[qi,∞)(x)Kn–m–r x,qi
ur(x)dqx p–rp
× ∞
X(,qi](s)Kmp qi,s
v–p(s)dqs
– ∞
X(,qi+](s)Kmp qi+,s
v–p(s)dqs p–rpr
= ∞
i=–∞
( –q) ∞
t=i
qtKmp qi,qt
v–p
qtp(r–)p–r
× ( –q) i j=–∞
qjKn–m–r qj,qi
ur qjp–rp
× + ∞
n=i
( –q)qnKmr qi,qn
v–p
qnp–r
pr
,
and the first equality in Lemma . is proved.
The second inequality can be proved in a similar way, so we leave out the details. The
proof is complete.
Proof of Theorem. By using formulas () and () we find that inequality () can be rewritten as
∞ j=–∞
( –q)r+qjur qj ∞
i=j
qif qi
Kn–
qj,qirr
≤C ∞ i=–∞
( –q)qifp qi
vp qip
. ()
Let
urj = ( –q)r+qjur qj
, fi=qif qi
, vpi = ( –q)qi(–p)vp
qi
, W(n)(i,j) =Kn–
qj,qi .
()
Then we get that inequality () can be rewritten as the discrete weighted Hardy-type inequality (see,e.g., [])
∞ j=–∞
urj ∞
i=j
W(n)(i,j)fi
rr
≤C ∞ i=–∞
vpiapi p
. ()
Hence, inequality () is equivalent to inequality (), where (W(n)(i,j)) is the non- negative triangular matrix which has entriesW(n)(i,j)≥ forj≤iandW(n)(i,j)≡ for j>iand is non-decreasing in the first index for alli≥j> –∞.
First we will prove that, forn∈N, ( –q)n–
i
kn–=j
[n– ]qqkn–
i
kn–=kn–
[n– ]qqkn–· · · i
k=k
[]qqk=W(n)(i,j). ()
We will use induction and first we note thatW()(i,j) = (qj–qi)q≡ forn= . Ifn= , then
( –q) i
k=j
qk= i
k=j
[]q
qk–qk+
=
qj–qi+
q=W()(i,j).