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Solution 38
From the expression for the energy we get d= ¯hωdn which implies that the density of states is g(ω) = ¯hω1 .
The number of excited states is therefore hNex =i 1
¯ hω
Z ∞
0
d eβ(µ−)−1
39 Exam TFY4230 - SPRING 2020
40 Exam TFY4230 - SPRING 2020