𝛿 𝑡 = 0,02
𝑉𝑠
( 𝑇1) 𝑞 = 2,0
𝑎𝑔 40𝐻𝑧 𝑚/𝑠2
𝑞
C
𝑡 ℎ𝑖 𝐴𝑐 𝐴𝑙𝑜𝑜𝑝 𝑐𝑟𝑒𝑓′ 𝑐𝑐𝑟 𝐸50𝑟𝑒𝑓 𝐸𝐷 𝐸𝑆 𝐸𝑜𝑒𝑑𝑟𝑒𝑓 𝐸𝑢𝑟𝑟𝑒𝑓 𝐹𝑏 𝐹𝑖 𝐺∗ 𝐺𝑠 𝐺𝑡 [𝐾]
𝐾0 [𝑀]
𝑅𝑖𝑛𝑡 𝑅𝛾 𝑆𝑑 (𝑇) 𝑆𝑒(𝑇) 𝑇1 𝑇𝐵 𝑇𝐶 𝑇𝐷 𝑉𝑠,30 𝑉𝑠 𝑊𝐷
𝑎𝑣𝑔 𝑓1
𝑝𝑟𝑒𝑓 𝑝𝑟𝑒𝑓= 100 𝑘𝑝𝑎
𝑢̇ (𝑡) 𝑢̈ (𝑡) 𝑢𝑖 𝑣𝑖 𝛾̇
𝛾0,7 𝛾𝐼 𝛾𝑐 𝛾𝑒𝑓𝑓 𝛾𝑠𝑎𝑡 𝛾𝑢𝑛𝑠𝑎𝑡 𝛿𝑡
𝜆𝑠 Length of share wave 𝜈𝑢𝑟
𝜎1′ 𝜎3′ 𝜏𝑐 𝜔𝑛 𝑐 𝑑 𝑓 𝑔 G
𝑘 𝑚 𝑚 𝑚 𝑛 𝑝 𝑞
𝜂 𝜈 𝜉 𝜌 𝜏 𝜑 𝜓 𝜔
•
•
•
•
𝑇1 𝑞
𝑇1
•
•
•
•
•
•
• NS-EN 1998
•
𝑚𝑢̈(𝑡) + 𝑐𝑢̇ + 𝑘𝑢 = 𝑝
𝑢̈ + 2𝜉𝜔𝑛𝑢̇ + 𝜔𝑛2𝑢 = 0
𝜔𝑛 = √𝑘 𝑚 𝜉 = 𝑐
2𝑚𝜔𝑛 = 𝑐 𝑐𝑐𝑟 𝑐𝑐𝑟 = 2𝑚𝜔𝑛 = 2√𝑘𝑚 =2𝑘
𝜔𝑛 𝜔𝑛
𝜉 𝑐𝑐𝑟 𝑐
𝑐 < 𝑐𝑐𝑟 𝜉 < 1
𝑐 = 𝑐𝑐𝑟 𝜉 = 1
𝑐 > 𝑐𝑐𝑟 𝜉 > 1
𝐺
𝜏 = 𝐺 ∗ 𝛾 + 𝜂 ∗ 𝛾̇
𝐺 𝜏 𝛾 𝛾̇
𝜂
𝑢 (𝑧, 𝑡) 𝛾 =𝜕𝑢(𝑧, 𝑡)
𝜕𝑧 𝑎𝑛𝑑 𝛾̇ =𝜕𝛾(𝑧, 𝑡)
𝜕𝑡 = 𝜕𝑢2(𝑧, 𝑡)
𝜕𝑧∗ 𝜕𝑡
𝐺𝑠 𝛾
𝐺𝑠 = 𝜏𝑐 𝛾𝑐 𝜏𝑐
𝛾𝑐
𝛾 𝐺
𝜉
𝐺𝑠𝑒𝑐 𝐺𝑠𝑒𝑐
𝜉
𝜉 =4 ∗ 𝜋 ∗ 𝑊𝑠 =
2 ∗ 𝜋 ∗ 𝐺𝑠𝑒𝑐∗ 𝛾𝑐2
𝑊𝐷 𝑊𝑠 𝐴𝑙𝑜𝑜𝑝
𝐺𝑠𝑒𝑐 𝜉
𝐺
𝐺𝑚𝑎𝑥 = 𝜌 ∗ 𝑉𝑠2
𝑉𝑠 𝐺𝑚𝑎𝑥
𝐹𝑚𝑎𝑥 = 𝑚 ∗ 𝑃𝑆𝐴 =𝑃𝑆𝐴 𝑔 ∗ 𝑤 𝑔
𝑘 𝜉
𝑘 𝑇
𝑇 = 2𝜋√𝑚 𝑘
𝐸50= 𝐸50𝑟𝑒𝑓∗ ( 𝜎3′+ 𝑎 𝑝𝑟𝑒𝑓+ 𝑎)
𝑚
𝐸𝑢𝑟 = 𝐸𝑢𝑟𝑟𝑒𝑓∗ ( 𝜎3′+ 𝑎 𝑝𝑟𝑒𝑓+ 𝑎)
𝑚
𝐸𝑜𝑒𝑑= 𝐸𝑜𝑒𝑑𝑟𝑒𝑓∗ ( 𝜎1′+ 𝑎 𝑝𝑟𝑒𝑓+ 𝑎)
𝑚
𝐺0 = 𝐺0𝑟𝑒𝑓( c ∗ cos(𝜑) − 𝜎3′∗ sin (𝜑) c ∗ cos(𝜑) + 𝑝𝑟𝑒𝑓∗ 𝑠𝑖𝑛(𝜑))
𝑚
𝐺0𝑟𝑒𝑓 = 𝐸0𝑟𝑒𝑓 2 ∗ (1 + 𝜐𝑢𝑟)
𝑚 𝐸50𝑟𝑒𝑓 𝐸𝑜𝑒𝑑𝑟𝑒𝑓 𝐸𝑢𝑟𝑟𝑒𝑓 𝜈𝑢𝑟
𝑝𝑟𝑒𝑓 𝑝𝑟𝑒𝑓 = 100 𝑘𝑝𝑎
The Hardin-Drnevich relationship is perhaps t
𝐺𝑠
𝐺0 = 1 1 + |𝛾
𝛾𝑟|
𝛾𝑟 =𝜏𝑚𝑎𝑥 𝐺0 𝜏𝑚𝑎𝑥
𝐺0
𝛾𝑟 = 𝛾0,7 𝐺𝑠
𝐺𝑠
𝐺0 = 1 1 + 𝑎 | 𝛾
𝛾0,7|
𝐺𝑠 𝐺0.
𝐺0
𝜏 = 𝐺𝑠∗ 𝛾 𝐺𝑠
𝜉 = 𝐸𝐷 4𝜋𝐸𝑠 𝜉
𝐸𝐷
𝐸𝑠 𝛾𝐶
𝐺𝑠/𝐺0 𝐺𝑡/𝐺0 𝐺𝑡
𝜉
[𝐶] = 𝛼[𝑀] + 𝛽[𝐾]
𝑀 𝐾 𝛼 𝛽
𝛼 + 𝛽𝜔2 = 2𝜔𝜉 𝜔 = 2𝜋𝑓
𝛼 = 2𝜔1∗ 𝜔2∗𝜔1∗ 𝜉2− 𝜔2∗ 𝜉1 𝜔12− 𝜔22 𝛽 = 2 ∗𝜔1∗ 𝜉1− 𝜔2∗ 𝜉2
𝜔12− 𝜔22 𝜔
𝜉 𝜉 = 1
𝑢0
𝑓1 = 𝑉𝑠 4𝐻
𝑥_𝑚𝑖𝑛 𝑥_𝑚𝑎𝑥
𝑥_𝑚𝑖𝑛 𝑥_𝑚𝑎𝑥
𝑦_𝑚𝑖𝑛
𝑅𝑖𝑛𝑡𝑒𝑟 𝑅𝑖𝑛𝑡𝑒𝑟
𝛿𝑡 = Δ𝑡 𝑛 ∗ 𝑚
𝑡 𝑛 𝑚
𝜆𝑠 = 𝑉𝑠 𝑓𝑚𝑎𝑥
𝜆𝑠 8
50%
𝐺∗ = 𝐺(1 + 𝑖2𝜉)
𝐺∗ = 𝐺(1 − 𝜉2+ 𝑖2𝜉)
𝜉
𝜔 𝐺∗ 𝜔
𝑊𝑑 = 4𝜋𝑊𝑠𝜉 = 2𝜋𝜉𝐺𝛾𝑐2𝜔
𝜉 𝜔
|𝐺∗| 𝜉
|𝐺∗| = 𝐺√1 + 4𝜉2
𝜉
𝐺∗= 𝐺 {(1 − 2𝜉2) + 2𝜉𝑗√1 − 𝜉2}
𝐺∗ = 𝐺{(1 − 2𝜉2) + 4𝜉2(1 − 𝜉2)} = 𝐺
𝑊𝑑 =1
2𝜔𝛾𝑐2∫ 2𝐺𝜉√1 − 𝜉2𝑑𝑡
𝑡+2𝜋 𝜔 𝑡
= 2𝜋𝐺𝜉√1 − 𝜉2𝛾𝑐2 𝜉
𝐺𝑖 𝜉𝑖
𝛾𝑚𝑎𝑥 𝛾𝑒𝑓𝑓 𝛾𝑚𝑎𝑥
𝛾𝑒𝑓𝑓 = 𝑅𝛾∗ 𝛾𝑚𝑎𝑥 𝑅𝛾
𝐺𝑖+1 𝜉𝑖+1 𝛾𝑒𝑓𝑓
𝑉𝑠
𝑉𝑠, 30
𝑉𝑠,30= 30 Σ𝑖=1,𝑁 ℎ𝑖
𝑣𝑖 ℎ𝑖 𝑣𝑖
𝑖 − 𝑡ℎ
𝑉𝑠
𝛾𝐼)
𝛾𝐼
𝑎𝑔 = 𝛾𝐼∗ 𝑎𝑔𝑅 𝑎𝑔𝑅
𝑎𝑔𝑅 = 0,8 ∗ 𝑎𝑔40 𝐻𝑧
𝑎𝑔40 𝐻𝑧 𝑓 = 40 𝐻𝑧 𝑇 = 0,025 𝑠
0 ≤ 𝑇 ≤ 𝑇𝐵: 𝑆𝑒(𝑇) = 𝑎𝑔∗ 𝑆 ∗ [1 + 𝑇
𝑇𝐵(𝜂 ∗ 2,5 − 1)]
𝑇𝐵 ≤ 𝑇 ≤ 𝑇𝐶: 𝑆𝑒(𝑇) = 𝑎𝑔∗ 𝑆 ∗ 𝜂 ∗ 2,5 𝑇𝐶 ≤ 𝑇 ≤ 𝑇𝐷: 𝑆𝑒(𝑇) = 𝑎𝑔∗ 𝑆 ∗ 𝜂 ∗ 2,5 [𝑇𝐶
𝑇] 𝑇𝐷 ≤ 𝑇 ≤ 4𝑠: 𝑆𝑒(𝑇) = 𝑎𝑔 ∗ 𝑆 ∗ 𝜂 ∗ 2,5 [𝑇𝐶∗ 𝑇𝐷
𝑇2 ]
𝑎𝑔 𝑇𝐵 𝑇𝐶 𝑇𝐷
𝜂 𝜂 = 1
𝜂 = √ 10
(5 + 𝜉) ≥ 0,55 𝜉
𝑇𝐵 𝑇𝐶 𝑇𝐷
(𝑆𝑣𝑒)
0 ≤ 𝑇 ≤ 𝑇𝐵: 𝑆𝑣𝑒(𝑇) = 𝑎𝑣𝑔∗ [1 + 𝑇
𝑇𝐵(𝜂 ∗ 3,0 − 1)]
𝑇𝐵 ≤ 𝑇 ≤ 𝑇𝐶: 𝑆𝑣𝑒(𝑇) = 𝑎𝑣𝑔∗ 𝜂 ∗ 3,0 𝑇𝐶 ≤ 𝑇 ≤ 𝑇𝐷: 𝑆𝑣𝑒(𝑇) = 𝑎𝑣𝑔∗ 𝜂 ∗ 3,0 [𝑇𝐶
𝑇] 𝑇𝐷 ≤ 𝑇 ≤ 4𝑠: 𝑆𝑣𝑒(𝑇) = 𝑎𝑣𝑔∗ 𝜂 ∗ 3,0 [𝑇𝐶∗ 𝑇𝐷
𝑇2 ] 𝑇 𝑇𝐵 𝑇𝐶 𝜂
𝑎𝑣𝑔
𝑎𝑣𝑔 / 𝑎𝑔
𝑞
𝑞 ≤ 1,5
𝑞 > 4,0
𝑞 = 4,0
0 ≤ 𝑇 ≤ 𝑇𝐵: 𝑆𝑑(𝑇) = 𝑎𝑔 ∗ 𝑆 ∗ [2 3+ 𝑇
𝑇𝐵(2,5 𝑞 −2
3)]
𝑇𝐵 ≤ 𝑇 ≤ 𝑇𝐶: 𝑆𝑑(𝑇) = 𝑎𝑔 ∗ 𝑆 ∗2,5 𝑞 𝑇𝐶 ≤ 𝑇 ≤ 𝑇𝐷: 𝑆𝑑(𝑇) = {= 𝑎𝑔∗ 𝑆 ∗2,5
𝑞 ∗ [𝑇𝐶 𝑇]
≥ 𝛽 ∗ 𝑎𝑔
}
𝑇𝐷 ≤ 𝑇: 𝑆𝑑(𝑇) = {= 𝑎𝑔∗ 𝑆 ∗2,5
𝑞 ∗ [𝑇𝐶∗ 𝑇𝐷 𝑇2 ]
≥ 𝛽 ∗ 𝑎𝑔
} 𝑇 𝑇𝐵 𝑇𝐶 𝜂 𝑆
𝛽
𝐹𝑏
𝑇1 ≤ {4 ∗ 𝑇𝐶 2,0 𝑠}
𝐹𝑏 = 𝑆𝑑 (𝑇1) ∗ 𝑚 ∗ 𝜆
𝑆𝑑 (𝑇1) 𝑇1
𝑇1 𝑚
𝑇1 ≤ 2 = 0,85
= 1,0
𝑇1 = 𝐶𝑡∗ 𝐻 34
𝐶𝑡 0,085 0,075
0,050 𝐶𝑡
𝐶𝑡 =0,075
√𝐴𝑐
𝑇1
𝑇1 = 2√𝑑 𝑑
𝑇1
𝑇1 = 2𝜋√∑ 𝑚𝑖∗ 𝑢𝑖2
∑ 𝐹𝑖∗ 𝑢𝑖
𝑚𝑖 "𝑖 𝑢𝑖 "𝑖 𝐹𝑖 "𝑖
𝑚 ∗ 𝑢̈ (𝑡) + 𝑐 ∗ 𝑢̇(𝑡) + 𝑘 ∗ 𝑢(𝑡) = 0
𝑚 ∗ 𝑢̈ (𝑡) + 𝑐 ∗ 𝑢̇(𝑡) + 𝑘 ∗ 𝑢(𝑡) = − 𝑚 ∗ 𝑢̈ 𝑔 = 𝑝𝑒𝑓𝑓(𝑡) 𝑢(𝑡) = 1
𝜔𝑉(𝑡)
𝑉(𝑡) = ∫ 𝑢̈𝑔 (𝑡) ∗ 𝑠𝑖𝑛𝜔(𝑡 − 𝜏)𝑒−𝜉𝜔(𝑡−𝜏)
𝑡
0
𝑆𝑣(𝜉, 𝜔) = |𝑉(𝑡, 𝜉, 𝜔|𝑚𝑎𝑥
𝐹𝑚𝑎𝑥 = 𝑘 ∗ 𝑢𝑚𝑎𝑥 = 𝑘 1
𝜔𝑆𝑣(𝜉, 𝜔) = 𝑘
𝜔2𝑆𝑑(𝜉, 𝜔) = 𝑚 ∗ 𝑆𝑑(𝜉, 𝜔)
50%
𝑠𝑎𝑡 20 𝑘𝑁/𝑚3
𝑢𝑛𝑠𝑎𝑡 20 𝑘𝑁/𝑚3
𝐸50𝑟𝑒𝑓 6815 𝑘𝑁/𝑚2 𝐸𝑜𝑒𝑑𝑟𝑒𝑓 6815 𝑘𝑁/𝑚2 𝐸𝑢𝑟𝑟𝑒𝑓 20446 𝑘𝑁/𝑚2
𝑚 0,8
𝑐 𝑟𝑒𝑓′ 10 𝑘𝑁/𝑚2
(𝑝ℎ𝑖) 18
(𝑝𝑠𝑖) -
0,7 0,700E-3
𝐺0𝑟𝑒𝑓 66450 𝑘𝑁/𝑚2
0,2
0,6910
𝑅𝑖𝑛𝑡𝑒𝑟 0,8
𝐺0𝑟𝑒𝑓 𝐺𝑢𝑟𝑟𝑒𝑓
• 𝐺0𝑟𝑒𝑓= 𝐺0 = 𝐺𝑚𝑎𝑥 𝑉𝑠
• 𝐺𝑢𝑟𝑟𝑒𝑓 𝐺0
𝑟𝑒𝑓
𝐺𝑢𝑟𝑟𝑒𝑓 = (2,5 𝑡𝑜 10)𝑔𝑜𝑖𝑛𝑔 𝑓𝑟𝑜𝑚 ℎ𝑎𝑟𝑑 𝑡𝑜 𝑠𝑜𝑓𝑡 𝑠𝑜𝑖𝑙𝑠
• 𝐸𝑢𝑟𝑟𝑒𝑓
𝐺𝑢𝑟𝑟𝑒𝑓 = 𝐸𝑢𝑟𝑟𝑒𝑓 2 ∗ (1 + 𝜐𝑢𝑟)
• 𝐸𝑜𝑒𝑑𝑟𝑒𝑓 𝐸𝑢𝑟𝑟𝑒𝑓= 3 ∗ 𝐸𝑜𝑒𝑑𝑟𝑒𝑓
𝛿 𝑡 = 0,02
1,20
𝑃𝑜𝑤𝑒𝑟 (𝑈𝑥) 𝑃𝑜𝑤𝑒𝑟 (𝑎𝑥)
𝑎𝑔 = 0,288 𝑔 𝑆 = 1,65 𝑞 = 1,5 𝐻 = 15 𝑚 𝐶𝑡= 0,075
𝐺𝑟𝑜𝑢𝑛𝑑 𝑡𝑦𝑝𝑒 − 𝐸 𝑇𝐵 = 0,10 𝑠 𝑇𝐶 = 0,30 𝑠 𝑇𝐷 = 1,40 𝑠
𝐻
𝑚 = 72360 𝑘𝑔 𝜆 = 0,85 𝑇1 = 0,572 𝑠 𝑆𝑑 = 0,416 𝑚/𝑠2 𝐹𝑏 = 25,6 𝑘𝑁
𝑇1 = 0,714 𝑠 𝑆𝑑 = 0,333 𝑚/𝑠2 𝐹𝑏 = 24,1𝑘𝑁
𝑇1 = 0,833 𝑠 𝑆𝑑 = 0,285 𝑚/𝑠2 𝐹𝑏 = 20,6 𝑘𝑁
(𝑚)
𝐻 = 12 𝑚 𝑚 = 60480 𝑘𝑔 𝑇1 = 0,484 𝑠 𝑆𝑑 = 0,491 𝑚/𝑠2 𝐹𝑏 = 25,3 𝑘𝑁
𝑇1 = 0,714 𝑠 𝑆𝑑 = 0,333 𝑚/𝑠2 𝐹𝑏 = 20,1 𝑘𝑁
75,6 𝑘𝑁 64,3 ∗ 10 + 75,6 = 718,6 𝑘𝑁
723,6 𝑘𝑁. 𝑡𝑜𝑛 𝑘𝑁 10
9,8 (22 𝑘𝑁/𝑚)
(25,6 𝑘𝑁/𝑚)
(𝑅𝑖𝑛𝑡)
𝑅𝑖𝑛𝑡 𝑅𝑖𝑛𝑡 = 0,6
1 𝑘𝑁/𝑚 𝑅𝑖𝑛𝑡 = 0,8
2,3 𝑘𝑁/𝑚
2,6 𝑘𝑁/𝑚 30 𝑘𝑁/𝑚
𝑇1
𝑇1
𝑇1 𝑇1
𝑇1[𝑠] 𝑆𝑑 [𝑚/𝑠2] 𝐹𝑏 [𝑘𝑁/𝑚]
Alternative 1 - 𝑇1 , Eq 0,572 0,416 25,6 𝑇1 , Eq 0,525 0,452 27,8
𝑇1
𝑞 𝑞 = 1,5
𝑞 𝑞
𝑞 𝑞
𝑞 = 1,0 𝑞 = 1,5 𝑞 = 2,0
𝑆1 𝑆2
𝑇1 𝑇1
𝑇1
v= z u= w*z v’= v - u h’= v’ * K0
G0
G0ref G0 = G/
𝛾 = 20 𝑘𝑁/𝑚3 𝑐′ = 𝑘𝑁/𝑚2 𝜑′ = 18°
𝐾0 = 1 − 𝑠𝑖𝑛𝜑 = 0,691 𝑝𝑟𝑒𝑓 = 100 𝑘𝑁/𝑚2
𝑚 = 0,8 𝐺𝑊 = 5,0 𝑚 𝜌 = 𝛾
𝑔 = 2038,7 𝑘𝑁/𝑚3 𝜈 = 0,2
𝐺0𝑟𝑒𝑓 = 66450 𝑘𝑁/𝑚2 𝐺𝑢𝑟𝑒𝑓 = 𝐺0𝑟𝑒𝑓
7,8 = 8519 𝑘𝑁/𝑚2
𝐸𝑢𝑟𝑟𝑒𝑓= 𝐺𝑢𝑟𝑒𝑓 (2 ∗ (1 + 𝜐)) = 20446 𝑘𝑁/𝑚2 𝐸50𝑟𝑒𝑓 = 𝐸𝑢𝑟𝑟𝑒𝑓
3 = 6815 𝑘𝑁/𝑚2 𝐸𝑜𝑒𝑑𝑟𝑒𝑓 = 𝐸50𝑟𝑒𝑓 = 6815 𝑘𝑁/𝑚2
𝛿𝑡
𝛿𝑡 = Δ𝑡
𝑛 ∗ 𝑚 = 52,78
5278 ∗ 1= 0,01
•
•
•
• 𝑓2
• 𝑓2
𝑓1 𝑓2
•
• 𝑓1 𝑓2
𝑓1 = 𝑉𝑠,𝑎𝑣𝑒𝑟𝑎𝑔𝑒
4 ∗ 𝐻 = 165,4
4 ∗ 15= 2,75 𝐻𝑧 𝑓2
𝑓1 =0,79
2,75= 0,28 → 𝑓2 = 1 𝐻𝑧
𝑉𝑠
𝑎𝑔 40 𝐻𝑧 𝑎𝑔 𝛾𝐼
β
𝑆 𝑇𝑩 𝑇𝑪 𝑇𝑫 𝑞
𝐻 𝐶𝑡 𝑇𝟏
𝑆𝑑 𝐹𝑏
𝑇𝟏
𝑆𝑑 𝐹𝑏
𝑎𝑔 40 𝐻𝑧 𝑎𝑔 𝛾𝐼
β
𝑆 𝑇𝑩 𝑇𝑪 𝑇𝑫 𝑞
𝐻 𝐶𝑡 𝑇𝟏
𝑆𝑑 𝐹𝑏
𝑇𝟏
𝑆𝑑 𝐹𝑏
𝑎𝑔 40 𝐻𝑧 𝑎𝑔 𝛾𝐼
β
𝑆 𝑇𝑩 𝑇𝑪 𝑇𝑫 𝑞
𝐻 𝐶𝑡 𝑇𝟏
𝑆𝑑 𝐹𝑏
𝑇𝟏
𝑆𝑑 𝐹𝑏
𝟏
𝑇1 = 2√𝑑 = 2√0,069 = 0,52 𝑠
𝑆𝑑 𝐹𝑏
( 𝑇1)
𝑇1 = 2𝜋√𝑀
𝐾 = 2𝜋√ 𝐹ℎ
𝑔 ∗ 𝐾 = 2𝜋√𝑑
𝑔 ≅ 2√𝑑
𝐹ℎ (𝑔)
𝒒 = 𝟐, 𝟎
𝑞 𝐻 𝐶𝑡 𝑇𝟏 𝑚
𝑆𝑑 𝐹𝑏
𝑆𝑑 𝐹𝑏
𝑞 = 2,0
m1 = 108,0 𝑘𝑁/𝑚 𝑚𝟐= 129,6 𝑘𝑁/𝑚 𝑚3 = 129,6 𝑘𝑁/𝑚 𝑚4 = 129,6 𝑘𝑁/𝑚 𝑚5 = 151,2 𝑘𝑁/𝑚
𝐵𝑎𝑠𝑒 𝑝𝑙𝑎𝑡𝑒 = 75,6 𝑘𝑁/𝑚 𝑇𝑜𝑡𝑎𝑙 = 723,6 𝑘𝑁/𝑚
𝑚1 = 108,0 𝑘𝑁/𝑚 𝑚2 = 129,6 𝑘𝑁/𝑚 𝑚3 = 129,6 𝑘𝑁/𝑚 𝑚4 = 129,6 𝑘𝑁/𝑚 𝑚5 = 108,0 𝑘𝑁/𝑚 𝑇𝑜𝑡𝑎𝑙 = 604,8 𝑘𝑁/𝑚
𝑎𝑔 40𝐻𝑧 𝑚/𝑠2
𝑎𝑥 𝑢𝑥