Contents lists available atScienceDirect
Journal of Mathematical Analysis and Applications
www.elsevier.com/locate/jmaa
A non-local approach to waves of maximal height for the Degasperis-Procesi equation
MathiasNikolai Arnesen
a r t i cl e i n f o a b s t r a c t
Articlehistory:
Received20November2018 Availableonline7June2019 Submittedby T.Yang
Keywords:
Degasperis-Procesi Globalbifurcation Peakedwaves
Weconsiderthenon-localformulationoftheDegasperis-Procesiequationut+uux+ L(3
2u2)x = 0,where Lis thenon-local Fouriermultiplier operator with symbol m(ξ)= (1+ξ2)−1.Weshow thatall L∞,pointwisetravelling-wavesolutionsare boundedabovebythewave-speedandthatifthemaximalheightisachievedthey arepeakedatthosepoints,otherwisetheyaresmooth.Forsufficientlysmallperiods wefindthehighest,peaked,travelling-wavesolutionasthelimitingcaseattheend ofthemainbifurcationcurveofP-periodicsolutions.Theresultsimplythatthere arenoL∞travellingcusponsolutionstotheDegasperis-Procesiequation.
©2019TheAuthor.PublishedbyElsevierInc.Thisisanopenaccessarticle undertheCCBYlicense(http://creativecommons.org/licenses/by/4.0/).
1. Introduction
Weconsidertheequation
ut+uux+ (L(3
2u2))x= 0, x∈R, t∈R, (1.1)
whereuisascalarfunctionandListhenonlocaloperatorL= (1−∂x2)−1.Thatis, Lf=K∗f, K=F−1m,
wherem(ξ)= (1+ξ2)−1 and F denotes theFouriertransform.Equation(1.1) isthenonlocalformulation oftheDegasperis–Procesiequation [5]
ut−uxxt+ 4uux−3uxuxx−uuxxx= 0, (1.2) which caneasily be seenby applying the inverseoperator of L, 1−∂x2, to (1.1). The Degasperis–Procesi equation wasdiscoveredas oneofthree equationswithinacertainclass ofthirdorder PDEssatisfyingan asymptoticintegrabilityconditionupto thirdorder, theother twobeingtheKdVandtheCamassa–Holm
E-mailaddress:[email protected].
https://doi.org/10.1016/j.jmaa.2019.06.014
0022-247X/©2019TheAuthor.PublishedbyElsevierInc. ThisisanopenaccessarticleundertheCCBYlicense (http://creativecommons.org/licenses/by/4.0/).
equations [5].Likethese twoequations, theDegasperis–Procesi equationhasaLaxpair,abi-Hamiltonian structure,andaninfinitenumberofconservationlaws[4].Whileitwasdiscoveredsolelyforitsmathematical properties, it has later been rigorously derived as a model for the propagation of shallow water waves, having the same asymptotic accuracy as the Camassa–Holm equation [3]. The Degasperis–Procesi and Camassa–HolmequationsfeaturestrongernonlineareffectsthantheKdVequation(orrather,thedispersion is much weaker), making them better suited to modelling nonlinear phenomena like wave breaking and solutionswithsingularities,whilemaintainingtherichmathematicalstructurementionedabovethatother weakly-dispersivemodels liketheWhithamequation[11] lack.
Shortly after its discovery, the well-posedness of (1.1) was extensively studied, establishing that it is locally well-posed in Hs both on R and S for s > 3/2, and admitting both global classical and weak solutions and classical solutions that blow up in finite time [13], [12], [14]. Moreover, the blow-up only occurs as wave-breaking. Thatis,thesolution remainsbounded, butit’sslope goesto −∞; foradetailed study oftheblow-upfor(1.1),see[8] andreferencestherein.
The weak dispersion allows not only for wave-breaking, but also for waves with singularities in the form of sharp crestsat thewave-peaks. Indeed, explicitpeaked soliton solutionsto (1.2),as well as mul- tipeakon solutions which arenot travelling waves,are known[4]. These are of thesame form as the ones forCamassa-Holm equation[2],andindeedeveryequation intheso-called‘b-family’of equationsthatthe Degasperis-Procesiand Camassa-Holmequationsbelongtohassuchsolutions[4].
In this paper we will focus on travelling-wave solutions to (1.1). Assuming u(x,t) = ϕ(x−μt) is a travelling wave,whereμ∈R isthewave-speed,(1.1) takestheform
−μϕ+1 2ϕ2+3
2L(ϕ2) =a, (1.3)
where a ∈ R is a constantof integration.By a Galilean change of variables this is equivalent to −μϕ+
1
2ϕ2+ 32L(ϕ2+kϕ)= 0, where k depends on μ and a; inparticular, k = 0 fora = 0.Hence there is no Galilean changeof variables thatremoves awhile preserving theform of theequation. Wewill workwith theequation intheform(1.3).
From the structure of the equation it is readily deducible that all non-constant solutions to (1.3) are smoothexceptpotentially atpointswherethewave-heightequals thewave-speed(cf.Theorem3.3or [10]) andsingularitiescanonlyoccurintheformofsharpcrestswithheightequaltothewave-speed.Wetherefore call suchsolutionsforwavesofmaximal height.Inthis paperwewill studytheregularity andexistenceof travelling wavesof maximalheightto (1.3) fromanonlocalperspective.
Themotivationofthispaperistwo-fold:toprovidenovelinformationaboutwavesofmaximalheightfor theDPequationspecificallyandtobetterunderstandtheformationofhighestwavesandtheirsingularities fornonlineardispersiveequationsmoregenerally.Wethereforeconsiderthenon-localformulationandfollow thegeneralframeworkof[7] and[6].Weshow firstlythatany non-constantL∞solutionof(1.3) ispeaked wherever the maximal height is achieved.That is, it is Lipschitz continuous at the crest, but not C1. In particular this means that there are no cuspon solutions of (1.3) in L∞. This is due to the smoothing effectof L, whichforces anysolutionto be at leastLipschitz; seeRemark3.6. Therestrictionto bounded solutions is quite natural. While equation (1.3) makes sense for any ϕ ∈ H−2(R), if we exclude purely distributional solutions, any function solving (1.3) a.e. clearly belongs to L∞. Secondly, for sufficiently small periods,peaked solutions of (1.3) arefound as the limitingcase at the end of themain bifurcation curve of Cevenα (SP) solutionsfor α ∈(1,2). While it has been established thatthere are peaked periodic travelling-wavesolutionsto(1.2) forallnon-zerowavespeedsin[10],theapproachofthatpaperworksonly for thelocalformulationand cannotbe extendedtoagenuinelynon-localequation. Moreoverthemethod in[10] andtheoneusedinthispaperareentirelydifferent andgivedifferentinsightandinformation.
AstravellingL∞cusponsolutionsto(1.2) havebeenclaimedbyseveralauthors,ourclaimthattheydo notexists requires somecomment.Thecuspons areinvariablyfoundstudying thelocalequation andthey
are strong solutionsin allpoints except the cusps. The exclusionof the cusps makes acrucial difference, however.Consider forinstance the stationary cuspedsoliton u(x)=√
1−e−2|x|discovered in[15], which isapointwisesolutionto (1.2) atallpointsexcept 0,where thefunctionhasacusp. Foranytest function ϕ∈C0∞(R),treatingtheleft-handside of(1.2) as adistribution(note thatuisindependentof time),one canwithbasiccalculusshowthat
4uux−3uxuxx−uuxxx, ϕ=u2,1
2ϕxxx−2ϕx=
R
u2 1
2ϕxxx−2ϕx
dx= 2ϕx(0)
andhenceitisnotaweaksolutionto (1.2),butratherto
ut−uxxt+ 4uux−3uxuxx−uuxxx=−2δ,
where δ is the usual delta-distribution.This is the case with all cuspons of the DP equation - thereare pointmassdistributionsatthecusps. Toacceptanyfunctionthatsolvestheequation pointwiseatallbut a countable number of points as a solution is equivalent to claiming that the sawtooth function u(x) = x−floor(x),orindeedanypiece-wiselinearfunction,isasolutionto theequation
u(x) = 0, x∈R.
Hencewe thinkitmorecorrect to callthe cuspons solutionsnotof(1.2) with 0 right-hand side,butwith somepointmassdistributions.
The paper is structured as follows: first some essential properties of the operator L and its kernel K are recounted in Section 2. In Section 3 we establish some general results about solutions to (1.3) and, in particular, using the properties of K, study the behaviour around points of critical height and prove Theorem 3.5, stating that any even, nonconstant solution is peaked at points where ϕ = μ. Lastly, in Section 4 we use the bifurcation Theory of [1] to construct a global bifurcation curve of even, periodic solutions in Cα for α ∈ (1,2). Using the properties of solutions established in Section 3, we show that forsufficientlysmall periodsthesolutionsalong thecurveconvergeto aneven,non-constantsolutionthat achievesthemaximalheight andmustthereforebeapeakon.
2. TheoperatorLanditskernel
AsLf(ξ) = (1+ξ2)−1f(ξ),Lf canformallybeexpressedas aconvolution Lf(x) =K∗f(x) =
R
K(x−y)f(y) dy,
whereK(x) istheinverseFouriertransformofm(ξ).Inthiscase,anexplicitexpressioniswellknownfrom virtuallyanytextbook onFourieranalysis:
K(x) =F−1((1 +ξ2)−1) = 1
2e−|x|. (2.1)
Inparticular,wenotethatKiscompletelymonotoneon(0,∞);itispositive,strictlydecreasingandstrictly convexforx>0.
Theperiodickernel is
KP(x) =
n∈Z
K(x+nP),
for P ∈(0,∞).Forx∈(−P/2,P/2),K(x+nP)= 12e−|x+nP|= 12e−xe−nP forn≥1,andK(x+nP)=
1
2exenP forn≤ −1.Thus
KP(x) =
n∈Z
K(x+nP)
=1
2e−|x|+1
2(ex+ e−x) ∞ n=1
e−nP
=1
2e−|x|+ cosh(x) 1
eP−1. (2.2)
Forperiodicfunctions,theoperatorLisgiven byLf(x)=P /2
−P /2KP(x−y)f(y)dy.
Weconcludethissectionwitharatherobvious,butcruciallemma:
Lemma 2.1.L isstrictly monotone:Lf > Lgif f andg are boundedandcontinuousfunctions withf g.
Proof. Letf andgbeasinthestatementofthelemma.AsKisstrictlypositive,wegetthatforallx∈R, K(x− ·)(f−g)0 andbycontinuitystrictlypositiveonaset ofnon-zeromeasure.Hence
Lf(x)−Lg(x) =
R
K(x−y)(f(y)−g(y)) dy >0.
Clearly, thesameargumentholdsforKp. 2 3. Periodictravellingwaves
Notethatifϕ(x) isatravellingwavesolutionto(1.1) withwave-speedμ,then−ϕ(−x) isalsoatravelling solutionto (1.1) withwave-speed−μ.Wewill thereforeonlyconsiderμ>0.
Firstweinvestigatehowtheparameterain(1.3) influencesthebehaviour/existenceofsolutions.
Theorem3.1. Fix μ>0andP <∞.Forallvaluesofa∈R,non-constantP-periodicsolutions to(1.3)(if they exist)satisfy
minϕ < μ+ μ2+ 8a
4 <maxϕ.
Moreover,
(i) Fora≤0,allsolutions are non-negative. When a<−μ82 thereare no real solutions andfor a=−μ82 there isonlytheconstant solution ϕ=μ4,
(ii) there areonly constant solutionswhen a≥μ2.
Proof. Atany pointxwhereϕ(x)2=L(ϕ2)(x)=:R2,(1.3) reducesto R(2R−μ) =a,
which has the positive solution R = μ+ μ42+8a. As L(c) = c for constants and L is strictly monotone (Lemma 2.1),there has to exist points where ϕ2 < L(ϕ2) andpoints where ϕ2 > L(ϕ2) for non-constant P-periodicsolutionsϕ.Thusthefirstinequalityhastoholdifmaxϕ>|minϕ|.
Considerfirstthecasea≤0.Thenϕcannotbenegativeinanypointasthentheleft-handsideof(1.3) wouldbestrictlypositiveinthatpoint(Lfisnon-negativeiff isnon-negative). Letm= minϕ≥0.Then L(ϕ2)≥m2withequality ifand onlyifϕ≡m.Hence,ifϕisasolutionto(1.3),weget
m(2m−μ)≤a.
Fora<−μ82 this hasnoreal solutions,and for a=−μ82 this hasonly theconstantsolutionϕ= μ4. This proves(i).
Now leta>0.Assumethatϕ<0 onsomeintervals. ByTheorem 3.3, ϕissmooth onthese intervals.
Clearly, ϕ is bounded below, so there is a point x0 such that ϕ(x0) = minϕ. Then L(ϕϕ)(x0) = 0 and L(ϕ2) attains it minimum at x0. This implies that ϕ also has to be positive at some point, and M := maxϕ>|minϕ|.Thusthefirstinequalityholds andM > μ+ μ42+8a.Inparticular, thismeansthat maxϕ≥μ2 foralla≥0 andM >√
aifa< μ2.Wehavethat
(ϕ−μ)2=μ2+ 2a−3L(ϕ2). (3.1)
Assume a ≥ μ2. Note that if ϕ = μ at any point, then 3L(ϕ2) = μ2+ 2a ≥ 3μ2 at those points. If a = μ2, then the constant solution ϕ ≡μ is avalid solution, otherwise Lemma2.1 implies thatϕ must alsotakevaluesaboveμ.Assumeϕμisanon-constantsolution.Thentheleft-handsideof(3.1) attains itsminimum where ϕis attainsitsminimum, while theright-handside attainsits minimumwhere L(ϕ2) attains its maximum. This is acontradiction. As both K and KP are even and completely monotone on (0,∞) and(0,P/2),respectively,L(ϕ2) cannotbe maximalwhereϕ2 isminimal.
Assumenowthatϕtakesvaluesbothaboveandbelowμ.ThenL(ϕ2)(x) ismaximalwheneverϕ(x)=μ and 3L(ϕ2)(x)=μ2+ 2a these points.Moreover, 3L(ϕ2)< μ2+ 2a whenϕ> μ. This impliesthatthere are infinitelymanydisjoint intervals, eachoffinite length,where ϕ> μ, andthatL(ϕ2) hasitsminimum oneachintervalatthepointswhere ϕismaximal. Thisisagainnotpossible. 2
Henceforthwewillassumethataissuchthatnon-constantsolutionsexists,i.e.that−μ2/8< a< μ2. Theorem 3.2. Let P(0,∞]. Any P-periodic, non-constant and even solution ϕ ∈ BC1(R) (the space of boundedfunctionswithboundedandcontinuousfirstderivative)thatisnon-decreasingon(−P/2,0)satisfies
ϕ>0, ϕ < μon(−P/2,0).
If ϕ∈BC2(R),then
ϕ(0)<0, and ϕ(0)< μ, andif P <∞,then
ϕ(±P/2)>0.
Proof. Letϕbeanon-constantandevensolutionthatisnon-decreasingon(−P/2,0).Wecanrewrite(1.3) as(μ−ϕ)2=μ2+ 2a−3L(ϕ2),andifϕ∈BC1(R) wecandifferentiate oneachside toget
(μ−ϕ(x))ϕ(x) =3
2L(ϕ2)(x). (3.2)
Asϕiseven,ϕ will beoddandusingtheevennessofKP weget
L(ϕ2)(x) = 2 0
−P /2
(KP(x−y)−KP(x+y))ϕ(y)ϕ(y) dy. (3.3)
WeclaimthatKP(x−y)> KP(x+y) foranyx,y∈(−P/2,0).Fixx∈(−P/2,0).AsKP strictlydecreases from theoriginin(−P/2,P/2) and isP-periodic,theclaimfollowsif,forally∈(−P/2,0),
|x−y|<min{|x+y|, x+y+P}. As xandy aresame-signed,wehave
|x+y|=|x|+|y|>|x−y|.
Moreover, wehave−x< P +xand−y < P+y,so |x−y|= max{x−y,y−x}< P+x+y.Thisproves theclaim.
Now weclaimthatϕϕ0 on(−P/2,0).Byassumption ϕ0 onthisinterval. Ifa≤0,it isplainto seethatϕ>0 astherighthandsideof(1.3) isstrictlypositivewheneverϕ≤0.ForaBC1(R) solutionthe same istrue when 0< a< μ2 too; thisfollows from equation (4.14) in[10].Hence theintegrand in(3.3) isnon-negativeandstrictlypositiveonasetofpositivemeasurein(−P/2,0),anditfollowsthattheright handsideof(3.2) isstrictlypositiveforx∈(−P/2,0).This impliesthefirstpartofthestatement.
Assumenowthatϕ∈BC2(R).Thenwecandifferentiateeachsideof(3.2) toget (μ−ϕ(x))ϕ(x)−(ϕ(x))2=3
2L(ϕ2)(x) = 3L(ϕϕ+ (ϕ)2)(x). (3.4) Evaluatingthisat x= 0 andusingtheevennessofϕ,ϕ,(ϕ)2 andKP,weget
(μ−ϕ(0))ϕ(0) = 6 0
−P /2
KP(y)
ϕ(y)ϕ(y) +ϕ(y)2 dy
= 6 [KP(y)ϕ(y)ϕ(y)]y=0y=−P /2−6 0
−P /2
KP (y)ϕ(y)ϕ(y) dy.
The first termon thesecond line vanishesas ϕ(0) =ϕ(−P/2) = 0.If P =∞, then limy→−∞K(y)= 0 and wegetthesameconclusion.AsKP isstrictlyincreasingon(−P/2,0),wegetthatthefinalintegralis strictly positive.Thatis,
(μ−ϕ(0))ϕ(0) =−6 0
−P /2
KP (y)ϕ(y)ϕ(y) dy <0
As wealreadyprovedthatϕ< μon(−P/2,0),itisnotpossible thatϕ(0)> μ,andthusweconcludethat ϕ(0)< μandϕ(0)<0.
NowweassumethatP <∞.NotethatKP(−P/2−y)=KP(P/2−y)=KP(−P/2+y)=KP(P/2+y).
Evaluating(3.4) atx=−P/2,weget
(μ−ϕ(−P/2))ϕ(−P/2) = 6 0
−P /2
KP(P/2 +y)
ϕ(y)ϕ(y) +ϕ(y)2 dy
= [KP(P/2 +y)ϕ(y)ϕ(y)]y=0y=−P /2−6 0
−P /2
KP (P/2 +y)ϕ(y)ϕ(y) dy.
As above,thefirst terminthe secondline vanishes. As KP isstrictly decreasingon (0,P/2),we getthat KP (P/2+y)<0 fory∈(−P/2,0),anditfollowsthatthelastintegralisnegative.Thatis,
(μ−ϕ(−P/2))ϕ(−P/2) =−6 0
−P /2
KP (P/2 +y)ϕ(y)ϕ(y) dy >0,
andweconcludethatϕ(−P/2)>0. 2 3.1. Singularity atϕ=μ
Nowweinvestigatewhathappensasasolutionapproaches μfrom below.Firstweshow thatasolution issmoothbelowμ:
Theorem3.3. Letϕ≤μbeasolution of (1.3).Then:
(i) If ϕ< μ uniformlyon R,thenϕ∈C∞(R) andallofitsderivativesare uniformlyboundedon R.
(ii) If ϕ< μ uniformlyon Rand ϕ∈L2(R),thenϕ∈H∞(R).
(iii) ϕissmoothon anyopen setwhereϕ< μ.
Proof. Assumefirstthatϕ< μuniformlyonR.Notethatasϕ→ −∞,theleft-handsideof(1.3) goesto∞, henceϕmustbeboundedbelowaswell.Clearly,|m(n)(ξ)|(1+|ξ|)−2−n(thatis,misaS−2-multiplier)and ListhereforecontinuousfromtheBesovspaceBp,qs (R) toBs+2p,q (R) foralls∈Rand1≤p,q≤ ∞.Denoting byCs(R),s∈RtheZygmundspaceB∞,∞s (R),wehaveinparticularthatLmapsL∞(R)⊂B∞,∞0 (R) into C2(R),andthereforeϕ→L(ϕ2) mapsL∞(R) intoC2(R).Recallthatifs∈R+\N,thenCs(R)=Cs(R), theordinaryHölderspace,and ifs∈N thenWs,∞(R)Cs(R).
Asϕsolves(1.3) wehave
(ϕ−μ)2=μ2+ 2a−3L(ϕ2).
The assumption ϕ < μ therefore implies that 3L(ϕ2) < μ2 + 2a, and the operator L(ϕ2) → μ − μ2+ 2a−3L(ϕ2) therefore maps Bp,qs (R)∩L∞(R) into itself for s >0. Since ϕ< μ, we also get that μ− μ2+ 2a−3L(ϕ2) =ϕ.Combiningthismapwithϕ→L(ϕ2) anditerating,weget(i).Whenp=q= 2, Bp,qs (R) canbe identifiedwith Hs(R).Assumenow thatϕ∈L2(R) inaddition.As ϕisalso bounded,we getthatϕ2∈L2(R)∩L∞(R),andingeneralϕ2∈Hs(R)∩L∞(R) ifϕ∈Hs(R)∩L∞,andthusϕ→L(ϕ2) maps Hs(R)∩L∞(R) to Hs+2(R)∩L∞(R),and we canapply the aboveiteration argument again.This proves(ii).
Lastly,toprove(iii),wenotethatifϕ∈L∞(R) andClocs onanopensetU inthesense thatψϕ∈ Cs(R) for any ψ∈ C0∞(U), westill get thatL(ϕ) isClocs+2 in U (the proof ofthis is the sameas inTheorem 5.1 [7]).Thuswecanapply thesameiterationargumentas aboveagain. 2
The next lemma will be essential for showing that the global bifurcation curves do not converge to a trivialcase.
Lemma 3.4. Let P < ∞, and let ϕ be an even, non-constant solution of (1.3) that is non-decreasing on (−P/2,0) withϕ≤μ.Then thereexists auniversal constant CK,P,μ>0,depending only on thekernel K and theperiodP andμ>0,suchthat
μ−ϕ(P
2)≥CK,P,μ.
Proof. If ϕ(−P/2) = ϕ(P/2) < 0, the statement is true with CK,P,μ = μ. Assume therefore that ϕ is non-negative.Fromtheevennessand periodicityofKP andϕ,wegettheformula
L(ϕ2)(x+h)−L(ϕ2)(x−h)
= 0
−P /2
(KP(x−y)−KP(x+y))(ϕ(y+h)2−ϕ(y−h)2) dy. (3.5)
As ϕ ≥ 0 is non-decreasing, both factors in the integrand are non-negative for x ∈ (−P/2,0) and h ∈ (0,P/2).Wealsohavetheequality
(2μ−ϕ(x)−ϕ(y))(ϕ(x)−ϕ(y)) = 3
L(ϕ2)(x)−L(ϕ2)(y)
, (3.6)
which shows thatL(ϕ2)(x) =L(ϕ2)(y) whenever ϕ(x) =ϕ(y). As ϕ is assumed to be non-constant and non-negative, this identity together with (3.5) implies that ϕ is strictly increasing on (−P/2,0), and it therefore followsfromTheorem 3.3thatϕissmoothawayfromx=kP,k∈Z. Letx∈
−3P8 ,−P8 .Then forasolutionϕasintheassumptions,
(μ−ϕ(P
2))ϕ(x)≥(μ−ϕ(x))ϕ(x) =3 2 lim
h→0
L(ϕ2)(x+h)−L(ϕ2)(x−h)
4h .
As theintegrandin(3.5) isnon-negative forh∈(0,P/2) andnon-positiveforh∈(−P/2,0),wecanapply Fatou’slemma tothelimitaboveandweget
(μ−ϕ(P
2))ϕ(x)≥3
P /2
−P /2
KP(x−y)ϕ(y)ϕ(y) dy
= 3 0
−P /2
(KP(x−y)−KP(x+y))ϕ(y)ϕ(y) dy.
Assume foracontradiction thatthestatement isnottrue. Thenfor allk < μ theremust exist asolution ϕ satisfyingtheassumptions and suchthatk≤ϕ≤μ. Then μ−ϕ(P/2)< μ−k.On theotherhand, as KP(x−y)> KP(x+y) forx,y∈(−P/2,0),wegetthat
(μ−ϕ(P
2))ϕ(x)≥3 0
−P /2
(KP(x−y)−KP(x+y))ϕ(y)ϕ(y) dy
≥3k
−P /8
−3P /8
(KP(x−y)−KP(x+y))ϕ(y) dy.
Thereisauniversalconstantλ˜K,P >0 dependingonlyonKP and P <∞suchthat min{KP(x−y)−KP(x+y) :x, y∈
−3P 8 ,−P
8
} ≥˜λK,P. Integratingbothsidesaboveoverx∈
−3P8 ,−P8
,wegetthat (μ−ϕ(P
2))(ϕ(−P/8)−ϕ(−3P/8))≥3kP
8˜λK,P(ϕ(−P/8)−ϕ(−3P/8)).
As shown aboveϕ is strictly increasing on (−P/2,0), so ϕ(−P/8) > ϕ(−3P/8) and we may divide out (ϕ(−P/8)−ϕ(−3P/8)) onboth sidestoget
(μ−ϕ(P
2))≥3kP 8
˜λK,P.
Thisimpliesthatμ−k≥3kP8λ˜K,P forallk < μ.Takingthelimitkμ,wegetacontradiction. 2 Nowwecome tothemainresultofthissection, concerningtheregularityatthepointwhere ϕ=μ.
Theorem3.5. Letϕ≤μbeasolutionof(1.3)whichiseven,non-constant,andnon-decreasingon(−P/2,0) with ϕ(0)=μ.Then:
(i) ϕissmoothon (−P,0).
(ii) ϕ∈C0,1(R),i.e.ϕisLipschitz.
(iii) ϕisexactlyLipschitzatx= 0;that is, thereexistsconstants0< c1< c2 such that c1|x| ≤ |μ−ϕ(x)| ≤c2|x|
for|x|1.
Proof. Part(i)willfollowdirectlyfromTheorem3.3ifwecanshowthatϕ< μon(−P/2,0).Assumethat x0∈(−P/2,0] isthesmallestnumbersuchthatϕ(x0)=μ;asϕisassumedto benon-constant,itmustbe thecasethatx0>−P/2.Thenϕ(x)=μand L(ϕ2)(x)= 0 forx∈[x0,0].Thatis,
0
−P /2
(KP (x−y) +KP (x+y)) (ϕ(y))2dy= 0, x∈[x0,0].
Clearly,0
−P /2(KP (x−y) +KP (x+y)) dy= 0, andas
KP (x−y) +KP (x+y)<0, −P/2< y < x <0, KP (x−y) +KP (x+y)>0, −P/2< x < y <0, we get thatx
−P /2(KP (x−y) +KP (x+y)) dy =−0
x(KP (x−y) +KP (x+y)) dy. Hence,by themean valuetheoremforintegrals,
L(ϕ2)(x0) = 0
−P /2
(KP (x0−y) +KP (x0+y)) (ϕ(y))2dy
=ϕ(c)2
x0
−P /2
(KP (x0−y) +KP (x0+y)) dy
+μ2 0
x0
(KP (x0−y) +KP (x0+y)) dy
= 0
x0
(KP(x0−y) +KP (x0+y)) dy(μ2−ϕ(c)2),
for some c ∈ (−P/2,x0). As −μ < ϕ < μ on (−P/2,0),we get (μ2−ϕ(c)2) >0, which is contradiction unless 0
x0(KP (x0−y) +KP (x0+y)) dy= 0. Thatcanonlyhappenifx0= 0.Thisproves part(i).
Atanypoint x0 whereϕ(x0)=μ,(3.6) reduces to (ϕ(x0)−ϕ(x))2= 3
(L(ϕ2)(x0)−L(ϕ2)(x)
. (3.7)
From (3.7),wegetinthereal linecasethat (ϕ(0)−ϕ(x))2=3
2
R
(2K(y)−K(x+y)−K(x−y))(ϕ(y))2dy
≤3 2
|y|<|x|
(2K(y)−K(x+y)−K(x−y))(ϕ(y))2dy
≤3
2ϕ2L∞(R)
|y|<|x|
|2K(y)−K(x+y)−K(x−y)|dy, (3.8)
where we used thatthefirstintegral ontheright-hand sideis clearlynon-negative,while 2K(y)−K(x+ y)−K(x−y)<0 when|y|≥ |x|.Indeed,for|y|>|x|wecanexpandK(y+x) andK(y−x) aroundy and usetheLagrange remainderto get
2K(y)−K(x+y)−K(x−y) =−x2
2(K(ξ1) +K(ξ2))<0,
where ξ1∈(y,y+x),ξ2∈(y−x,y) andthelast inequalityfollows fromthestrictconvexityofK.
Similarly,expandingto onelessorder,weget
2K(y)−K(x+y)−K(x−y) =x(K(ξ1)−K(ξ2)).
As K isuniformlybounded, thereisaconstantC thatcanbechosenindependentlyofxsuchthat
|2K(y)−K(x+y)−K(x−y)| ≤C|x|, (3.9) forally∈R.Takingthesquarerootoneachsideof(3.8) wethengetthat
|ϕ(0)−ϕ(x)| ≤CϕL∞(R)|x|=Cμ|x|.
ThisprovesthatϕisLipschitzat0.Fortheperiodickernel,wehavethat2KP(y)−KP(x+y)−KP(x−y)<0 when|x|≤ |y|≤P/2− |x|(weareonlyinterestedinxcloseto0,sowecanassume|x|< P/2− |x|).Inthe intervals |y|<|x|andP/2− |x|<|y|≤P/2,(3.9) holdsforKP andwethereforegetthesameresult.
Itremainstoshowtheoppositeinequality,i.e.that|μ−ϕ(x)||x|nearx= 0;inparticularthisimplies thatϕ∈/C1.Asϕissmoothon(−P/2,0) and(atleast)Lipschitzin0,wecanuseintegrationbypartsfor x∈(−P/2,0) toget
(μ−ϕ(x))ϕ(x) = 3
2L(ϕ2)(x)
= 3 2
0
−P /2
(KP(x−y) +KP (x+y)) (ϕ(y))2dy
= 3 0
−P /2
(KP(x−y)−KP(x+y))ϕ(y)ϕ(y) dy.
Asμ−ϕ(x)≤Cμ|x| forx∈(−P/2,0) asshownabove,we divideoutμ−ϕ(x):
ϕ(x)≥C 0
−P /2
KP(x−y)−KP(x+y)
|x| ϕ(y)ϕ(y) dy,
forsomeconstantC >0 independentof x.Letx∈(−P/2,0).Bythemeanvaluetheorem,
|μ−ϕ(x)|
|x| =ϕ(ξ)≥C 0
−P /2
KP(ξ−y)−KP(ξ+y)
|ξ| ϕ(y)ϕ(y) dy (3.10)
forsomeξ∈(x,0).Itsufficestoshowthatthisisboundedbelowbyapositiveconstantasx0,butwhile ϕ isdefinedforallx∈(−P/2,0),thelimitmaynotexist.Wethereforeconsiderthelimitinfimum.Onthe otherhand,thelimitoftheintegralontherighthandsideexists.Indeed,wehavethat
ξ0lim
KP(ξ−y)−KP(ξ+y)
|ξ| = 2KP (y)
Thisfunctionisnon-negativeandstrictlymonotonicallyincreasingon(−P/2,0),andasϕisnon-decreasing on this interval, we get by Lebesgue’s dominated convergence theorem that for any sequence {ξn}n ⊂ (−P/2,0) suchthatξn →0,
n→∞limC 0
−P /2
KP(ξn−y)−KP(ξn+y)
|ξn| ϕ(y)ϕ(y) dy
=C 0
−P /2 nlim→∞
KP(ξn−y)−KP(ξn+y)
|ξn| ϕ(y)ϕ(y) dy
≥C 0
−P /2
ϕ(y)ϕ(y) dy
= C
2 (μ2−(ϕ(−P/2))2)>0.
Inparticularthelimitexistsand thereforeequalsthelimitinfimumand from(3.10) itfollowsthatforany sequence {xn}n ⊂(−P/2,0),andbysymmetryindeedanysequencein(−P/2,P/2),suchthatxn→0,
lim inf
n→∞
|μ−ϕ(xn)|
|xn| 1.
As thesequencewasarbitrarythis proves(iii).
Sinceϕ∈L∞(R) issymmetricandϕ≥0,andthereforealsoL(ϕ2) ≥0,on(−P/2,0),wehavethatfor x<0
L(ϕ2)
(x) =
R
K(x−y)(ϕ(y))2dy
= 0
−∞
(K(x−y) +K(x+y))(ϕ(y))2dy
≤ 0
x
(K(x−y) +K(x+y))(ϕ(y))2dy
≤C|x|,
forsomeconstantC >0,whereweusedthatKiscompletelymonotoneon(0,∞) andthattheintegrandis L∞.Theresultsaboveimplythat(μ−ϕ(x))≥C|x|forsomeconstantC independentofxwhenϕ(x)> μ4 and fromtheequation
(μ−ϕ(x))ϕ(x) = 3 L(ϕ2)
(x)≤min(L(ϕ2)(0), C|x|),
which holds for x ≤ 0, we then see that ϕ is uniformly bounded on the closed interval [−P/2,0] and therefore Lipschitz.Thisproves(ii). 2
Remark 3.6 (On cuspons).Theequality (3.7) holds when ϕ(x0) =μ for any solutionof (1.3), regardless of the integrationconstanta. Theproof aboveused thatϕis even, butthis isnotneeded to showthat a solutionisat leastLipschitz,as(3.7) holdsinanycase.Ifϕ∈L∞(R),thenL(ϕ2)∈ C2(R),and(3.7) then impliesthatϕ∈C1/2(R),andhenceL(ϕ2)∈C5/2(R).Differentiatingboth sidesof(3.7),wethenget
|(ϕ(x0)−ϕ(x))ϕ(x)||x|,
whichprovesthatϕisatleastLipschitzatanypointx0whereϕ(x0)=μ,andwehavethereforeshownthat there areno cuspedtravelling L∞ solutionsfor the Degasperis-Procesiequation. We havenot yetproved thatasolutionthattouchestheline μexists,butanythatdowillbeLipschitz.
4. Globalbifurcation
In this section we will show that there are non-constantperiodic solutionswhich achieve the maximal height; i.e. periodic peakons. These will be obtained by constructing a curve of even, periodic smooth solutionsusing“standard”bifurcation theoryandshowingthatinthelimitofthecurvewegetapeakon.
Wethereforefixα∈(1,2) andconsiderCevenα (SP),thespaceofeven,real-valuedfunctionsonthecircleSP offinitecircumferenceP >0 thatareα-timesdifferentiablewiththeαderivativebeingα− α-Hölder continuous. Themain pointis toworkwith regularitystrictly higherthan Lipschitz,i.e.α >1,andavoid
integervaluesofαinorderto avoidthe Zygmundspaces whichdonotcoincidewith Cαwhen α∈Z(see theproofofTheorem 3.3).
From[10] weknowthattherearenoperiodicpeakonswhena= 0 in(1.3),onlyaone-parameterfamilyof smoothperiodicsolutionsandapeakedsolitarywave,andfora∈(−μ82,0) thereareonlysmoothsolutions.
Asourfinalgoalistofindabifurcationcurveofperiodicsolutionsthatconvergestoapeakedsolution,the casea≤0 isnotrelevantandhenceforthwewillonlyconsider a>0.
Remark4.1.Asonecaneasilycheck(followingtheprocedurebelow),fora= 0 onecandolocalbifurcation from thecurve(ϕ,μ)= (μ/2,μ) ofconstantsolutionsonlywhen theperiodis√
2π, butthis curvecannot beextendedtoaglobalone.Whena∈(−μ82,0) alltheresultsregardingbifurcationbelowholdsforperiods 0< P <√
2πandwegetglobalbifurcationcurves.However,inthiscase√
−8a < μ<∞andtheequivalent of Lemma 4.8 does not hold.That is, we cannot preclude that alternative (ii) in Theorem 4.5 occurs by μ(s) approaching√
−8a.
Fixa>0 andletF :Cevenα (SP)×R→Cevenα (SP) betheoperatordefinedby F(ϕ, μ) =μϕ−3
2L(ϕ2)−1
2ϕ2+a. (4.1)
Thenϕisasolutionto(1.3) withwave-speedμifandonlyifF(ϕ,μ)= 0.Therearetwocurvesofconstant solutionsF(ϕ(s),μ(s))= 0,namely(ϕ(s),μ(s))= (s4±√s24+8a,s) foralls∈R.Thenegativeone,however, is not interesting as (1.3) has no non-positive solutions and therefore no curve of non-trivial solutions intersects it.Wetherefore takethecurve(ϕ(s),μ(s))= (s4+√s24+8a,s) asourstartingpoint. Set
λ(μ) := μ
4+ μ2+ 8a 4 anddefine
F(φ, μ) =˜ F(λ(μ)−φ, μ) = (λ−μ)φ+ 3λL(φ)−3
2L(φ2)−1
2φ2. (4.2)
ThenF˜(0,μ)= 0 forallμ∈R,andletting
ϕ:=λ(μ)−φ, (4.3)
wehavethat
F˜(φ, μ) = 0⇔F(ϕ, μ) = 0.
Henceacurve(φ(s),μ(s)) alongwhichF˜= 0 givesrisetoacurveofsolutions(ϕ(s),μ(s)) to(1.3). Inthe sequel,ϕwillalwaysbedefinedthrough(4.3).
Notethat
DφF˜[0, μ] = (λ(μ)−μ) id +3λ(μ)L.
Whenμ2> awe havethat4λ> μwhileμ> λ,andas L(cos(p·)(x)=cos(px)1+p2 wegetthat
ker DφF[0, μ] =˜ {Ccos
4λ−μ μ−λ x
:C∈R}.
Restricting to P-periodic functions, the kernel is one-dimensional if and only if
4λ−μμ−λ = 2kπP for some k∈N.Clearly,
4λ(μ)−μ
μ−λ(μ) iscontinuous inμforμ∈(√
a,∞),strictly monotoneon thisinterval, bounded below by √
2,the bound being achieved in the limitas μ → ∞, and unboundedabove as μ2 a. This means thatforeveryP >0 andeachk∈N such that 2kπP >√
2,thereexists auniqueμ>√
asuchthat cos
4λ−μ μ−λx
∈Cevenα (SP).WhenP ≥√
2π,wegetthatk >1.
Theorem 4.2 (Local bifurcation). Fix a>0and P >0, andlet F andF˜ be defined as in (4.1) and(4.2), respectively.Thenforeachk∈N suchthat 2kπP >√
2,thereexistsauniqueμk∈(√
a,∞)suchthat (0,μk) is abifurcation pointfor F,˜ andhence (λ(μk),μk)is abifurcation pointforF.That is, there existsε>0 and ananalytic curve
s→(ϕ(s), μ(s))⊂Cevenα (SP)×(√
a,∞), |s|< ε, of nontrivial P/k-periodicsolutions, whereμ(0)=μk and
Dsφ(0) =−Dsϕ(0) = cos
4λ(μk)−μk μk−λ(μk)x
.
Proof. Itissufficient toconsider k= 1 andP <√
2π.Asshownabove,thereexists auniqueμ∈(√ a,∞) such that ker DφF˜[0,μ] is one-dimensional. The space Cevenα (SP) has basis {cos(2πPk·) : k ∈ N} and by straightforward calculationonefindsthatDφF˜[0,μ] mapsthebasiselement k= 1 tozerowhile allothers arepreservedmoduloaconstant.Thuscodim range DφF˜[0,μ]= 1 andDφF˜[0,μ] isFriedholmofindexzero.
TheresultnowfollowsfromTheorem8.3.1in[1].NotethatDsφ(0)=−Dsϕ(0) becauseDsμ(0)= ˙μ(0)= 0 (see (4.8) below). 2
Wewanttoextendthesebifurcation curvesglobally.Let U :={(ϕ, μ)∈Cevenα (SP)×(√
a,∞) :ϕ < μ}, and
S :={(ϕ, μ)∈U :F(ϕ, μ) = 0}.
Inorder to establishTheorem4.5below;thatis,to extendthecurvesglobally, itsufficesto establishthat
¨
μ(0)= 0 andthefollowing Lemma:
Lemma4.3.Whenever(ϕ,μ)∈S thefunctionϕissmooth,andboundedandclosedsubsetsofS arecompact in Cevenα (SP)×(√
a,∞).
Proof. ThesmoothnesspartwasprovedinTheorem3.3.Recallfromtheproofofthattheoremthat(ϕ,μ)∈ S implies3L(ϕ2)< μ2+ 2aandhence
ϕ=μ− μ2+ 2a−3L(ϕ2)∈Cevenα+2(SP), asL:Cα→Cα+2and√
xisrealanalyticforx>0.LetE⊂SbeboundedandclosedintheCevenα (SP)×R topology. Then, as shown above,{ϕ: (ϕ,μ) ∈E}⊂Cevenα+2(SP) is abounded subset. Bounded subsets of Cevenα+2(SP) are pre-compact in Cevenα (SP), hence any sequence {(ϕn,μn)}n ⊂ E has a subsequence that converges in theCevenα (SP)×R topology.As E is closed, thelimit must itselflie inE, proving thatE is compact. 2
In order to establish the bifurcation formulas we will apply the Lyapunov-Schmidt reduction [9]. For simplicitywe considerthecaseP <√
2πand k= 1.Letμ∗:=μ1and φ∗(x) := cos
2π P x
, (4.4)
andletfurthermore
M:={
k =1
akcos 2πkx
P
∈Cevenα (SP)},
and
N := ker DφF[0, μ˜ ∗] = span(φ∗).
ThenCevenα (SP)=M⊕N andwecanusethecanonicalembeddingCα(SP)→L2(SP) todefineacontinuous projection
Πφ=φ, φ∗L2(SP)φ∗, (4.5)
whereu,vL2(SP)= P2 P /2
−P /2uvdx.
Theorem4.4(Lyapunov-Schmidtreduction[9]). ThereexistsaneighbourhoodO×Y ⊂U around (0,μ∗)in whichtheproblem
F˜(φ, μ) = 0 (4.6)
isequivalent to
Φ(εφ∗, μ) := Π ˜F(εφ∗+ψ(εφ∗, μ), μ) = 0 (4.7) forfunctionsψ∈C∞(ON×Y,M),Φ∈C∞(ON×Y,N),andON⊂N an openneighbourhood ofthezero function in N. One has Φ(0,μ∗) = 0, ψ(0,μ∗) = 0, Dφψ(0,μ∗) = 0, and solving the finite dimensional problem(4.7)provides asolution φ=εφ∗+ψ(εφ∗,μ) totheinfinitedimensional problem(4.6).
Wewanttoshowthatμ(ε) isnotconstantaround0.Wecalculate D2φφF˜[0, μ∗](φ∗, φ∗) =−(φ∗)2−3L((φ∗)2),
D2μφF˜[0, μ∗]φ∗= (λ(μ∗)−1)φ∗+ 3λ(μ∗)L(φ∗).
AsL(cos(p·))(x)= 1+p12cos(px) forp= 0,wegetthat D2μφF˜[0, μ∗]φ∗=
λ(μ∗)(1 + 3
1 + (2π/P)2)−1
φ∗.
Bychoice,
4λ(μ∗)−μ∗
μ∗−λ(μ∗) = 2πP,sothatthecoefficientofφ∗ aboveiszeroifandonlyif λ(μ∗) = λ(μ∗)
μ∗ .