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Journal of Algebra
www.elsevier.com/locate/jalgebra
Maximal τ
d-rigid pairs
Karin M. Jacobsena,∗,1, Peter Jørgensenb
aNorwegianUniversityofScienceandTechnology,DepartmentofMathematical Sciences,Sentralbygg2, Gløshaugen,7491Trondheim,Norway
bSchoolofMathematicsandStatistics,NewcastleUniversity,NewcastleuponTyne NE17RU,UnitedKingdom
a r t i c l e i n f o a b s t r a c t
Articlehistory:
Received30April2019
Availableonline14November2019 CommunicatedbyDavidHernandez
MSC:
16G10 18E10 18E30
Keywords:
d-Abeliancategory (d+ 2)-Angulatedcategory Higherhomologicalalgebra Maximald-rigidobject Maximalτd-rigidpair
LetT bea2-Calabi–Yautriangulatedcategory,T a cluster tilting object with endomorphism algebra Γ. Consider the functor T(T,−) : T → mod Γ. It induces a bijection fromtheisomorphismclassesofclustertiltingobjectstothe isomorphismclassesofsupportτ-tiltingpairs.Thisisdueto Adachi,Iyama,andReiten.
Thenotionof(d+2)-angulatedcategoriesisahigheranalogue oftriangulatedcategories.Weshowahigheranalogueofthe aboveresult,basedonthenotionofmaximalτd-rigidpairs.
©2019PublishedbyElsevierInc.
0. Introduction
In triangulated categories, the notions of cluster tilting objects (introduced in [4, p. 583]) and maximal rigid objects have recently been extensively investigated. They
* Correspondingauthor.
E-mailaddresses:[email protected](K.M. Jacobsen),[email protected] (P. Jørgensen).
URL:http://www.staff.ncl.ac.uk/peter.jorgensen(P. Jørgensen).
1 Currentaddress:FakultätfürMathematik,UniversitätBielefeld,33501Bielefeld,Germany.
https://doi.org/10.1016/j.jalgebra.2019.10.046 0021-8693/©2019PublishedbyElsevierInc.
frequentlycoincide,by[22,thm.2.6],andtheyarecloselylinkedtothenotionofsupport τ-tiltingpairsinabeliancategories (introducedin[1, def.0.3]).Indeed,there isoftena bijection betweenthecluster tiltingobjects inatriangulated categoryand thesupport τ-tiltingpairsinasuitable(abelian)modulecategory, see[1, thm.4.1].
This paperinvestigatestheanalogoustheoryin(d+ 2)-angulatedand d-abeliancat- egories, whichare the main objectsof higher homologicalalgebra,see [8, def.2.1] and [15,def.3.1].Severalkeypropertiesfromtheclassiccasedonotcarryover.Forexample, cluster tilting objects are maximal d-rigid, but the converse is rarely true. Moreover, the higher analogueof support τ-rigid pairs permita bijection to the maximal d-rigid objects, butnottotheclustertiltingobjects.
For furtherreading inhigherhomological algebraanumber ofreferences havebeen included inthe bibliography,see [3], [6], [7], [8], [9], [10], [11],[12],[13],[14], [15], [16], [17],[18],[19],[20],[21].
Let k be an algebraically closed field, d 1 an integer, T a k-linear Hom-finite (d+ 2)-angulated category with split idempotents, see [8, def. 2.1].Assume thatT is 2d-Calabi–Yau,see[21,def.5.2],andletΣd denote thed-suspensionfunctorofT. Clustertiltingandmaximald-rigidobjects.AnobjectX ∈T isd-rigid ifExtdT(X,X)= 0.Werecallthreeimportantdefinitions.
Definition 0.1 ([21, def. 5.3]).Anobject X ∈T is Oppermann–Thomas cluster tilting in T if:
(i) X isd-rigid.
(ii) ForanyY ∈T there existsa(d+ 2)-angle
Xd → · · · →X0→Y →ΣdXd
withXi∈addX forall0≤i≤d.
Definition 0.2.AnobjectX∈T isd-self-perpendicularinT if addX ={Y ∈T |ExtdT(X, Y) = 0}. Definition 0.3.AnobjectX∈T ismaximal d-rigidin T if
addX={Y ∈T |ExtdT(X⊕Y, X⊕Y) = 0}. Ourfirstmain resultis:
TheoremA.X isOppermann–Thomascluster tilting⇒X isd-self-perpendicular⇒X is maximald-rigid.
Weprove this inTheorem 1.1. Of equalimportance is thatthe implications cannot bereversedingeneral,seeRemark1.2.Inparticular, whend2,theclassofmaximal d-rigidobjects istypically strictly largerthanthe classof Oppermann–Thomascluster tiltingobjects,incontrasttotheclassiccased= 1 wherethetwoclassesusuallycoincide, see[22,thm.2.6].
Maximalτd-rigidpairs.LetT ∈T beanOppermann–Thomasclustertiltingobjectand letΓ= EndT(T).Recallthefollowingresult.
Theorem0.4 ([14,thm.0.6]). Consider theessentialimage D of thefunctorT(T,−): T →mod Γ.Then D isad-clustertiltingsubcategoryofmod Γ.Thereisacommutative diagram,asshownbelow,wheretheverticalarrowisthequotientfunctorandthediagonal arrowisan equivalence ofcategories:
T
T/add ΣdT.
D
(−)
T(T ,−)
∼
ThecategoryDisad-abeliancategoryby[15,thm.3.16].Ithasad-Auslander–Reiten translationτd,whichisahigheranalogueoftheclassicAuslander–Reitentranslationτ, see[12,sec. 1.4.1].AmoduleM ∈D iscalledτd-rigid ifHomΓ(M,τdM)= 0.
Remark0.5.Theclassicadd-proj-correspondenceholds,asT(T,−) restrictstoanequiv- alenceaddT →proj Γ.ThefunctoralsorestrictstoanequivalenceaddST →inj Γ.[14, lem.2.1]
It isnaturalto ask if D permitsahigheranalogueof theτ-tiltingtheory of [1]. We willnotanswerthisquestion,butwillinsteadintroducethefollowingdefinitionsinspired byit.
Definition0.6.A pair(M,P) withM ∈D and P ∈proj Γ iscalledaτd-rigid pairin D ifM isτd-rigidand HomΓ(P,M)= 0.
Definition 0.7.A pair(M,P) withM ∈D and P ∈proj Γ is called amaximal τd-rigid pairin D ifitsatisfies:
(i) IfN ∈D then
N∈addM ⇔
⎧⎪
⎨
⎪⎩
HomΓ(M, τdN) = 0, HomΓ(N, τdM) = 0, HomΓ(P, N) = 0.
(ii) IfQ∈proj Γ,then
Q∈addP ⇔HomΓ(Q, M) = 0.
A maximalτd-rigid pairisaτd-rigidpair.
Oursecond mainresultis:
Theorem B.If eachindecomposable objectof T isd-rigid,thenthere isabijection isomorphism classes of
maximald-rigid objects inT
→
isomorphism classes of maximal τd-rigid pairs inD
.
We prove this inSection 3. If d = 1, then (M,P) is amaximal τ1-rigid pairif and only ifit isasupportτ-tiltingpairinthesense of[1,def.0.3(b)],see [1, def.0.3,prop.
2.3, andcor.2.13].HenceTheoremBisahigheranalogueofthebijection
isomorphism classes of cluster tilting object inT
→
isomorphism classes of supportτ-tilting pairs in mod Γ
which exists by[1, thm. 4.1] when T is triangulated, i.e. inthe cased = 1. However, when d2, wedonot thinkofmaximal τd-rigid pairsas supportτd-tiltingpairs. The reasonisthatbyTheoremB,maximalτd-rigidpairsarelinkedtomaximald-rigidobjects inhigherangulated categories. Asremarkedabove,this classis typicallystrictly larger than theclass ofOppermann–Thomasclustertiltingobjectswhend2.
Note that[19] makes anapproachtohighersupporttiltingtheory.
Thispaperisorganisedasfollows:Section1provesTheoremA,Section2investigates thepreciserelationbetweenHom spacesin T and D,Section3provesTheoremB,and Section4givesanexample.
Setup0.8. Throughoutthepaperweusethefollowingnotation:
k: Analgebraically closedfield.
D: ThedualityfunctorHomk(−,k).
T: Ak-linear,Hom-finite,(d+ 2)-angulatedcategorywithsplit idempotents.Weas- sume that T is 2d-Calabi–Yau, that is T(X,Y) ∼= DT(Y,Σ2dX) naturally in X,Y ∈T.
Σd: Thed-suspensionfunctoronT.
T: AnOppermann–ThomasclustertiltingobjectinT.
(−): ThecanonicalfunctorT →T/add ΣdT,whosetargetisthenaivequotientcate- goryofT modulothemorphismswhichfactorthroughanobjectinadd ΣdT.
Γ: TheendomorphismringEndT(T).
νΓ: TheNakayamafunctoronmod Γ.
τd: Thed-Auslander–Reitentranslationonmod Γ.
D: Theessentialimageofthefunctor T(T,−):T →mod Γ.
1. ProofofTheoremA
Theorem1.1. LetX∈T be given.
(i) There are implications
X is Oppermann–Thomas cluster tilting
⇓
X isd-self-perpendicular
⇓
X is maximal d-rigid
⇓ X isd-rigid.
(ii) Ifeach indecomposableobjectin T isd-rigid, then
X isd-self-perpendicular ⇔X is maximal d-rigid.
Proof. (i), thefirst implication:Suppose X is Oppermann–Thomas cluster tilting. We mustprovetheequalityinDefinition0.2,andtheinclusion⊆isclear.Fortheinclusion
⊇, suppose ExtdT(X,Y) = 0. Then each morphism X0 → ΣdY with X0 ∈ addX is zero.This applies in particular to the(d+ 2)-angleXd → · · · → X0 → ΣdY →ΣdXd withXi ∈addX,whichexists sinceX isOppermann–Thomascluster tilting.Butthen themorphism ΣdY → ΣdXd is asplit monomorphism, and applying Σ−d givesasplit monomorphismY →Xd provingY ∈addX.
(i), the second implication: Suppose that X is d-self-perpendicular. We must prove theequalityinDefinition0.3,andtheinclusion⊆isclear.Fortheinclusion⊇,suppose ExtdT(X⊕Y,X⊕Y)= 0.Theninparticular,ExtdT(X,Y)= 0,whenceY ∈addX.
(i),thethirdimplication:Thisisclear.
(ii):Supposethateachindecomposable objectinT isd-rigid.Because ofpart(i),it isenoughtoprovetheimplication ⇐in(ii), sosuppose thatX ismaximal d-rigid. We mustprovetheequalityinDefinition0.2,and⊆isclear.
Fortheinclusion⊇, observethat{Y ∈T |ExtdT(X,Y)= 0}isclosedunderdirect sumsand summands by additivityof Ext. Henceit is enoughto suppose that Y is an
indecomposable objectinthissetand proveY ∈addX.However,ExtdT(X,Y)= 0 im- pliesExtdT(Y,X)= 0 because T is2d-Calabi–Yau,andExtdT(Y,Y)= 0 byassumption.
Finally, X isd-rigidbypart(i),so ExtdT(X,X)= 0.Combining these equalitiesshows ExtdT(X⊕Y,X⊕Y)= 0, andY ∈addX follows. 2
Remark1.2.TheimplicationsinTheorem1.1(i)cannotbe reversedingeneral:
– An example of a d-self-perpendicular object X which is not Oppermann–Thomas cluster tilting is given in Section 4. In fact, the objects in the last three rows of Fig.4aresuchexamples.Theexamplewasoriginally givenin[21, p.1735].
– An example of a maximal d-rigid object which is not d-self-perpendicular can be obtainedbycombiningproposition 2.6andcorollary 2.7in[5].These resultsgivea maximal1-rigidobjectwhichisnotclustertilting,butinthetriangulatedsettingof [5],clustertiltingisequivalent to1-self-perpendicular,see[5,bottomofp.963].
– Finally,anexampleofad-rigidobjectwhichisnotmaximald-rigidisthezeroobject, assoonasT hasanon-zerod-rigidobject.
WeendthesectionbyobservingthatTheorem1.1(ii)canbeappliedtoanimportant class ofcategories.
Proposition 1.3. Let Λ be a d-representation finite algebra, OΛ the (d+ 2)-angulated cluster category associatedtoΛin [21,thm.5.2].Theneach X ∈OΛ satisfies
X isd-self-perpendicular ⇔X is maximald-rigid.
Proof. Each indecomposable in OΛ is d-rigid by [21, Lemma 5.41], so the equivalence follows fromTheorem 1.1(ii). 2
2. Adimensionformula forExtdT
Recall from Setup 0.8 that T is a fixed Oppermann–Thomas cluster tilting object in T, and that T is 2d-Calabi–Yau, that is, T(X,Y) ∼= DT(Y,Σ2dX) naturally in X,Y ∈T.
Lemma 2.1.There isanaturalisomorphism νΓT(T, T)∼=T
T,Σ2d(T) forT ∈addT.
Proof. Bythe2d-Calabi-Yau propertywehave T
T,Σ2d(T) ∼= DT(T, T).
By[14,Lemma2.2(i)],
DT(T, T)∼= DHomΓ
T(T, T),T(T, T) = DHomΓ
T(T, T),Γ .
Finally,bydefinitionwehave DHomΓ
T(T, T),Γ =νΓT(T, T), see[2,def.III.2.8]. 2
Lemma2.2.If X ∈T has nonon-zerodirectsummandsinadd ΣdT,thenthereexistsa (d+ 2)-angle
Td→ · · · →T0→X →ΣdTd
in T withthefollowingproperties:EachTiisinaddT,andapplyingthefunctor T(T,−) gives acomplex
T(T, Td)→ · · · →T(T, T0)→T(T, X)→0
whichisthestart oftheaugmented minimalprojectiveresolutionof T(T,X).
Proof. Given X,there existsa(d+ 2)-angle
Σ−dX→Td → · · · →T0→X
with eachTi inaddT byDefinition 0.1. Since X hasno non-zero directsummands in add ΣdT, the first morphism in the (d+ 2)-angle is in the radical of T. Bydropping trivialsummandsoftheformT ∼−→= T,wecanassumethatsoaretheothermorphisms exceptthelastmorphism.
By[8,prop.2.5(a)],applyingthefunctor T(T,−) givesanexactsequence T(T,Σ−dX)→T(T, Td)→ · · · →T(T, T0)→T(T, X)→T(T,ΣdTd) = 0.
ByTheorem 0.4, applying the functor T(T,−) is,up to isomorphism, justto apply a quotient functor, and this preserves radical morphisms. So in the exactsequence each morphism,exceptpossibly T(T,T0)→T(T,X),isintheradicalofmod Γ.Thisproves theclaimofthelemma. 2
Lemma 2.3. If X ∈ T has no non-zero direct summands in add ΣdT, then there is a naturalisomorphism
τdT(T, X)∼=T(T,ΣdX).
Proof. As X has no non-zero directsummands inadd ΣdT, we can consider the (d+ 2)-angle from Lemma 2.2. Apply T(T,−) to get the following part of an augmented minimal projectiveresolutioninmod Γ:
T(T, Td)→ · · · →T(T, T0)→T(T, X)→0.
UsingtheNakayamafunctorandLemma2.1wegetthefollowingcommutativediagram.
0 τdT(T, X) νΓT(T, Td) · · · νΓT(T, T0)
0 T(T,ΣdX) T(T,Σ2dTd) · · · T(T,Σ2dT0)
∼ ∼
Thetopsequenceisexactbythedefinitionofτd,see[12,sec.1.4.1].Thebottomsequence isexactbecauseitisobtainedbyapplyingHomT(T,−) toa(d+ 2)-angleinT,see [8, prop. 2.5(a)].Thefirsttermofthebottomsequence isactually T(T,ΣdT0),butthisis zero.Since wehaved≥1,thediagramimplies
τdT(T, X)∼=T(T,ΣdX). 2
Wewrite [addT](X,Y)={f ∈T(X,Y)|f factors through an object of addT}. Lemma 2.4.There isanaturalisomorphism
D[addT](X, Y)∼= HomT/add ΣdT(Y ,Σ2dX) forX,Y ∈T.
Proof. Picka(d+ 2)-angleinT:
Td→. . .→T0→Y →ΣdTd,
with Ti ∈addT.Use T(X,−) toobtainthemorphismΨ:T(X,T0)→T(X,Y).This isahomomorphismofk-vectorspaces,hencewecantalkabouttheimageofΨ.Wefirst note thatany morphismf intheimage ofΨ must factorthroughaddT.Now suppose f ∈T(X,Y) factorsthroughT ∈addT.Wehavethefollowingcommutativediagram, where thelowerrowisapartofthe(d+ 2)-angleabove:
· · · T0 Y ΣdTd.
· · · T T 0
X
1T
f
Thedashedarrow existsbycompletingthecommutativesquareto amorphism of(d+ 2)-angles.Weconcludethatf ∈Im Ψ.Hence
Im Ψ = [addT](X, Y).
Wenowreturntothelongexactsequence
· · · →T(X, T0)−→Ψ T(X, Y)→T(X,ΣdTd)→ · · ·.
Usingthe dualityfunctorD andSerre dualitywe getthefollowing diagram withexact rows:
DT(X,ΣdTd) DT(X, Y) DT(X, T0)
T(ΣdTd,Σ2dX) T(Y,Σ2dX) T(T0,Σ2dX)
DΨ
α β
∼ ∼ ∼
[add ΣdT](Y,Σ2dX) T(Y,Σ2dX)/[add ΣdT](Y,Σ2dX)
α β
Analogous to the above discussion, the space [add ΣdT](Y,Σ2dX) is the image of the map α.Hence αisthe kernel ofβ and DΨ (by isomorphism).The morphismβ is by definitionthecokernel of α,and T(Y,Σ2dX)/[add ΣdT](Y,Σ2dX) is thusthe image of DΨ.Thuswehave
D[addT](X, Y)∼= D Im Ψ∼= Im DΨ∼=T(Y,Σ2dX)/[add ΣdT](Y,Σ2dX)
∼= HomT/add ΣdT(Y ,Σ2dX). 2
Lemma2.5. SupposeX,Y ∈T.Thenwe haveashortexact sequence
0→DHomT/add ΣdT(Y ,ΣdX)→ExtdT(X, Y)→HomT/add ΣdT(X,ΣdY)→0.
Proof. Bythedefinitionofthequotientfunctorwehaveashort exactsequence 0→[add ΣdT](X,ΣdY)→T(X,ΣdY)→HomT/add ΣdT(X,ΣdY)→0.
Wehave[add ΣdT](X,ΣdY)∼= [addT](Σ−dX,Y).ByLemma2.4wehave
[addT](Σ−dX, Y)∼= DHomT/add ΣdT(Y ,Σ2dΣ−dX)∼= DHomT/add ΣdT(Y ,ΣdX).
Wealsoknow thatT(X,ΣdY)∼= ExtdT(X,Y),so theconclusionfollows. 2
Lemma 2.6. Suppose X,Y ∈ T have no non-zero direct summands in add ΣdT. Then we haveashortexact sequence
0→DHomΓ
T(T, Y), τdT(T, X) →ExtdT(X, Y)
→HomΓ
T(T, X), τdT(T, Y) →0.
Proof. Considerthe short exactsequence from Lemma 2.5. ByTheorem 0.4 we know that
DHomT/add ΣdT(Y ,ΣdX)∼= DHomΓ
T(T, Y),T(T,ΣdX) .
Applying Lemma2.3wehave DHomΓ
T(T, Y),T(T,ΣdX) ∼= DHomΓ
T(T, Y), τdT(T, X) .
SimilarlywecanshowHomT/add ΣdT(X,ΣdY)∼= HomΓ
T(T,X),τdT(T,Y) . 2
Themap definednextwilleventuallyinducetheequivalence ofTheoremB.
Definition 2.7. Foreach X ∈T, pickanisomorphism X ∼=X⊕X suchthatX has nonon-zerodirectsummandsinadd ΣdT andX∈add ΣdT.Let
Δ(X) =
T(T, X),T(T,Σ−dX) .
This isapairofΓ-moduleswhere T(T,X) isinD andT(T,Σ−dX) isinproj Γ.
Proposition 2.8. Given X,Y ∈T,set(M,P)= Δ(X) and(N,Q)= Δ(Y),where Δ is themapin Definition 2.7.Then
dimkExtdT(X, Y) = dimkHomΓ(M, τdN) + dimkHomΓ(N, τdM) + dimkHomΓ(P, N) + dimkHomΓ(Q, M).
Proof. ByadditivityofExt we have ExtdT(X, Y)∼= ExtdT(X⊕X, Y⊕Y)
∼= ExtdT(X, Y)⊕ExtdT(X, Y)⊕ExtdT(X, Y)⊕ExtdT(X, Y).
AsT isd-rigid,weseethatExtdT(X,Y)= 0,and hencewehave
dim ExtdT(X, Y) = dim ExtdT(X, Y) + dim ExtdT(X, Y) + dim ExtdT(X, Y). (2.1) FromLemma2.6wehavetheshort exactsequence:
0→DHomΓ
T(T, Y), τdT(T, X) →ExtdT(X, Y)
→HomΓ
T(T, X), τdT(T, Y) →0, whichmeansthat
dim ExtdT(X, Y) = dimkHomΓ
T(T, X), τdT(T, Y) + dimkHomΓ
T(T, Y), τdT(T, X)
= dimkHomΓ(M, τdN) + dimkHomΓ(N, τdM). (2.2) Weseethat
ExtdT(X, Y)∼=T(X,ΣdY)∼=T(Σ−dX, Y)∼= HomΓ
T(T,Σ−dX),T(T, Y)
∼= HomΓ(P, N).
Thethirdisomorphismfollowsfrom[14,Lemma2.2(i)] andthefactthatΣ−dX∈addT. Similarly,
ExtdT(X, Y)∼= DExtdT(Y, X)∼= DHomΓ(Q, M).
Thuswehave
dim ExtdT(X, Y) = dimkHomΓ(P, N) (2.3) dim ExtdT(X, Y) = dimkHomΓ(Q, M). (2.4) Substituting(2.2),(2.3),and(2.4) into(2.1) givestheresult. 2
Asaconsequencewehave:
Corollary2.9. Given X,Y ∈T,set(M,P)= Δ(X)and(N,Q)= Δ(Y).Then ExtdT(X, Y) = 0⇔
HomΓ(M, τdN) = HomΓ(N, τdM) = HomΓ(P, N) = HomΓ(Q, M) = 0.
3. ProofofTheorem B
Thefollowing resultsusethemapΔ fromDefinition2.7.
Lemma3.1.GivenX,Y ∈T,set(M,P)= Δ(X)and(N,Q)= Δ(Y).ThenY ∈addX if andonly ifN ∈addM andQ∈addP.
Proof. Let X ∼=X⊕X be thedecomposition from Definition2.7, where X has no non-zero directsummands from add ΣdT while X is in add ΣdT. We have (M,P) = T(T,X),T(T,Σ−dX) .Similarly,(N,Q)=
T(T,Y),T(T,Σ−dY) .
The condition Q ∈addP is equivalent to Y ∈ addX by theadd-proj-correspon- dence, (see Remark 0.5). The condition N ∈ addM is equivalent to Y ∈ addX by Theorem 0.4becauseX,Y havenonon-zerodirectsummandsinadd ΣdT. Theresult follows. 2
Lemma 3.2.The category T is skeletallysmall.The mapΔ inducesabijection
δ: isoT →isoD×iso proj Γ, (3.1) where isodenotesthesetof isomorphismclassesof askeletally smallcategory.
Proof. Let Iso denote the class of isomorphisms of a category. For a skeletally small category C wehavethatIsoC = isoC.Notethatsinceamodulecategoryoveraringis skeletally small,wehavethatD,proj Γ⊆mod Γ areskeletally small.
It isclearthatΔ inducesawell-definedmapoftheform δ : IsoT →isoD×iso proj Γ.
To see thatδ is injective,arguelike the proofof Lemma3.1,replacing membership of add withisomorphism.
ItfollowsthatT isskeletallysmall.Wecanthusreplaceδwiththemapδfrom(3.1).
To see thatδ is surjective, let (M,P) be a pair with M ∈ D and P ∈ proj Γ. By Theorem 0.4 thereis anobjectX ∈T withno non-zerodirectsummandsinadd ΣdT such that M ∼= T(T,X). By the add-proj correspondence, see Remark 0.5, there is an object X ∈ add ΣdT such that P ∼= T(T,Σ−dX). Setting X = X ⊕X gives (M,P)∼= Δ(X). 2
Lemma3.3.IfX ∈T isd-self-perpendicular,then(M,P)= Δ(X)isamaximalτd-rigid pair.
Proof. LetN ∈D and Q∈proj Γ begiven. ByLemma3.2, thereis anobject Y ∈T suchthat(N,Q)∼= Δ(Y).Then
N ∈addM andQ∈addP
⇔Y ∈addX
⇔ExtdT(X, Y) = 0
⇔HomΓ(M, τdN) = HomΓ(N, τdM) = HomΓ(P, N) = HomΓ(Q, M) = 0, wheretheequivalences,respectively,arebyLemma3.1,Definition0.2,andCorollary2.9.
TheconditionsofDefinition0.7arerecoveredbysettingQ= 0 respectivelyN = 0. 2 Lemma3.4. LetX ∈T begiven. If(M,P)= Δ(X)isamaximal τd-rigid pair, thenX isd-self-perpendicular.
Proof. LetY ∈T begiven andset(N,Q)∼= Δ(Y).Then ExtdT(X, Y) = 0
⇔HomΓ(M, τdN) = HomΓ(N, τdM) = HomΓ(P, N) = HomΓ(Q, M) = 0
⇔N∈addM and Q∈addP
⇔Y ∈addX,
wheretheequivalences,respectively,arebyCorollary2.9,Definition0.7,andLemma3.1.
2 Theorem3.5.RecallthatthemapΔfromDefinition2.7inducesthebijectionδ: isoT → isoD×iso proj Γfrom Lemma3.2.
(i) δ restrictsto abijection
isomorphism classes of d-rigid objects inT
→
isomorphism classes of τd-rigid pairs in D
.
(ii) δ restrictsfurther toabijection
isomorphism classes of d-self-perpendicular objects inT
→
isomorphism classes of maximalτd-rigid pairs inD
.
Proof. (i):ConsiderX ∈T andset (M,P)= Δ(X).Then
ExtdT(X, X) = 0⇔HomΓ(M, τdM) = 0 and HomΓ(P, M) = 0 byCorollary2.9,so theresultfollows.
(ii):SeeLemmas3.3and3.4. 2
Proof of TheoremB(from the introduction). CombineTheorems3.5(ii)and1.1(ii). 2
1357 1358 1368
1468
2468
2469
2479
2579
3579
Fig. 1.The AR quiver of the 5-angulated categoryT.
4. Anexample
In this section we letd= 3 and T =OA32. This isthe 5-angulated (higher)cluster categoryoftypeA2,see[21,def.5.2,sec.6,andsec.8].Theindecomposableobjectscan be identifiedwith theelements oftheset
I39={1357,1358,1368,1468,2468,2469,2479,2579,3579},
see[21,sec.8].TheARquiverofT isshowninFig.1.By[21,thm.5.5andsec.8],the object
T = 1357⊕1358⊕1368⊕1468 is Oppermann–Thomasclustertilting.
IfX,Y ∈T areindecomposableobjects,then T(X, Y) =
k ifY isX or its immediate successor in the AR quiver, 0 otherwise,
see [21,prop.6.1and def.6.9].ItfollowsthatΓ= EndT(T)=kQ/I,where Q= 1→2→3→4
andIistheidealgeneratedbyallcompositionsoftwoconsecutivearrows.Theactionof thefunctorT(T,−):T →mod Γ on indecomposableobjectsisshowninFig.2,where P(q) andI(q) denotetheindecomposableprojectiveandinjectivemodulesassociatedto thevertex q∈Q.Note thattheessentialimageof T(T,−) is
X 1357 1358 1368 1468 2468 2469 2479 2579 3579
T(T , X) P(4) P(3) P(2) P(1) I(1) 0 0 0 0
Fig. 2.The action of the functorT(T ,−) :T →mod Γ.
X
◦
◦
◦
Y1
Y2
◦
◦
◦
Fig. 3.The functor Ext3T(X,−) is non-zero onY1andY2. It is zero on every other indecomposable object.
Maximal 3-rigid objectX Maximalτ3-rigid pair Δ(X) 1357⊕1358⊕1368⊕1468 (Γ,0)
1358⊕1368⊕1468⊕2468 (DΓ,0) 1368⊕1468⊕2468⊕2469
P(2)⊕P(1)⊕I(1), P(4) 1468⊕2468⊕2469⊕2479
P(1)⊕I(1), P(4)⊕P(3) 2468⊕2469⊕2479⊕2579
I(1), P(4)⊕P(3)⊕P(2) 2469⊕2479⊕2579⊕3579 (0,Γ)
2479⊕2579⊕3579⊕1357
P(4), P(3)⊕P(2)⊕P(1) 2579⊕3579⊕1357⊕1358
P(4)⊕P(3), P(2)⊕P(1) 3579⊕1357⊕1358⊕1368
P(4)⊕P(3)⊕P(2), P(1) 1357⊕1468⊕2479
P(4)⊕P(1), P(3) 1358⊕2468⊕2579
P(3)⊕I(1), P(2) 1368⊕2469⊕3579
P(2), P(4)⊕P(1)
Fig. 4.Theseareallthebasicmaximal3-rigidobjectsofT andtheircorrespondingmaximalτ3-rigidpairs inD.
D= add{P(4), P(3), P(2), P(1), I(1)}.
Thisisa3-clustertiltingsubcategoryofmod Γ andhenceitis3-abelian.
The3-suspension functorΣ3 acts ontheAR quiver bymovingfour stepsclockwise.
Combined withour knowledgeofHom, this shows thatifX is afixed indecomposable objectinT,thentheindecomposableobjectsY withExt3T(X,Y)= 0 arepreciselythe twoobjectsfurthest fromX intheARquiver,seeFig.3.
Based on this, we can compute all basic 3-self-perpendicular objects in T, and by Proposition 1.3 they coincide with the basic maximal 3-rigid objects in T. For each suchobject X,there is amaximal τ3-rigid pairΔ(X)=
T(T,X),T(T,Σ−3X) by TheoremB.SeeFig.4.NotethatthefirstnineobjectsinFig.4areOppermann–Thomas clustertilting,butthethreelast objectsarenot.
Acknowledgment
This work was supported by EPSRC grant EP/P016014/1 “Higher Dimensional Homological Algebra”. Karin M. Jacobsen is grateful for the hospitality of Newcastle University duringhervisitinOctober2018.
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