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Prof. Dr. Sergey Denisov WS 2015/16

Generalized Nyquist theorem

by

Stefan Gorol & Dominikus Zielke

(2)

• Introduction to the Generalized Nyquist theorem

• Derivation of the theorem

-

Dissipation

-

Fluctuations

-

Relation between dissipation and fluctuations

• Further Applications

-

General strategy to obtain the fluctuation spectrum of a dissipative system

-

1stexample: Brownian motion

-

2ndexample: Electric field fluctuations and radiation (Planck’s law)

• Summary and outlook

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• Based on the Nyquist theorem for the white noise of a resistor:

hV2i= 2 πkBT R

Z

0

• with the mean square of the voltagehV2i, Boltzmann’s constantkB, temperature T, angular frequencyωand resistanceR

• Relates a fluctuating force of a system at thermal equilibrium with energy dissipation

• First stated (in its generalized form) by[Callen&Welton](1951)

• Applicable to linear dissipative systems with small perturbations

• System is dissipative if it is capable of absorbing energy when subjected to a time periodic perturbation

• System is linear if the power dissipation is quadratic in the magnitude of the perturbation (e.g. electrical resistor:P=I2R)

(4)

Suppose:

H(t) = ˆˆ H0+V(t) ˆQ

0≡ Hamiltonian of non-perturbated system (time independent) V(t) ˆQ ≡ time depentent perturbation Furthermore suppose:

|E1i,|E2i,. . .are eigenfunctions ofHˆ0with corresponding eigenvaluesE1,E2,. . . Now solve the Schr ¨odinger Equation

i~

∂t|φ(t)iS= ˆH|φ(t)iS Use linear perturbation theory in the interaction picture

|φ(t)iS= exp

−i ˆH0t

~

|φ(t)iI

(5)

Dissipation 2/7

The Schr ¨odinger Equation turns into

|φ(t)i˙ I= 1 i~V(t) exp

i ˆH0t

~

Qˆexp

−i ˆH0t

~

|φ(t)iI

Expand|φ(t)iIin terms of|Eni

|φ(t)iI=

X

n

an(t)|Eni

The projection on|Emigives a˙m(t) = 1

i~

X

n

V(t)an(t) exp

it(E

mEn)

~

hEm|Q|Eˆ ni

(6)

Let the system be in an initial state|EniandV(t) =V0cos (ωt)

˙

am(t) = 1 i~

V0cos (ωt) exp

it(EmEn)

~

| {z }

=:ωmn

hEm|Q|Eˆ ni

Integration yields am(t) =−1

2~

V0hEm|Q|Eˆ ni

h

exp (i(ωmnω)t)1

mnω) +exp (i(ωmn+ω)t)−1 (ωmn+ω)

i

The probabilitypfor a transitionnmis

pmn= 1 4~2|V0|2

hEm|Q|Eˆ ni

2 ·

exp (i(ωmnω)t)−1

mnω) +exp (i(ωmn+ω)t)−1 (ωmn+ω)

2

(7)

Dissipation 4/7

Blue Curve: Small timet Red Curve: Large timet

For large timest→ ∞, the transition probability turns intoδ-functions. Forωmnω, which is the case whenEmEn≈~ω, one obtains

exp (i(ωmnω)t)−1

mnω) +exp (i(ωmn+ω)t)−1 (ωmn+ω)

2

≈4 sin2mnω)t2

mnω)2

Use

t→∞lim

Z

−∞

mnsin2((ωmnω)t/2)mnω)2t =π

2

(8)

We can identify from the above integral in the limitt→ ∞:

lim

t→∞

sin2((ωmnω)t/2)mnω)2 =π

2δ(ωmnω)t

Therefore the transition probabilitypmncan be expressed as:

pmn= π 2~

|V0|2

hEm|Q|Eˆ ni

2·δ(EmEn−~ω)t

The transition rateΓ = dpmn/dtthen is:

Γmn,absorb= π 2~

|V0|2

hEm|Q|Eˆ ni

2 ·δ(EmEn−~ω)

ForEmEn≈ −~ωit follows similarly Γmn,emission= π

2~

|V0|2

hEm|Q|Eˆ ni

2·δ(EmEn+~ω)

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Dissipation 6/7

Multiplying the emission and absorbance rate with−~ωand~ωrespectively, yields the total dissipated power.

PS,n= πω 2 |V0|2

h

hEn+~ω|Q|Eˆ ni

2ρ(En+~ω)

hEn−~ω|Q|Eˆ ni

2ρ(En−~ω)

i

Suppose:f(E, T)is the distribution functions of densely distributed initial energy states:

Ptotal=πω 2 |V0|2

Z

−∞

dE ρ(E)f(E,T)

h

hE+~ω|Q|Eiˆ

2ρ(E+~ω)

hE~ω|Q|Eiˆ

2ρ(E−~ω)

i

(10)

The total average dissipated power of an impedanzeZ(ω)can be written as Ptotal=1

2|V0|2 R(ω)

|Z(ω)|2

Thus in quantum mechanical systems, one can identify R(ω)

|Z(ω)|2 =πω

Z

0

dE ρ(E)f(E)

h

hE+~ω|Q|Eiˆ

2ρ(E+~ω)

Z

dE ρ(E)f(E)

hE~ω|Q|Eiˆ

2ρ(E−~ω)

i

Supposing Boltzmann distribution, one ends up with R

|Z|2 =πω 1−exp (−~ωβ)

Z

0

dE f(E)ρ(E)ρ(E+~ω)|hE+~ω|Q|Ei|ˆ 2

(11)

Fluctuations 1/3

Suppose thermal equilibrium and thus

hEn|Q|E˙ˆ ni= 0

This also follows fromHˆ0being hermitian:

hEn|Q|E˙ˆ ni= i

~

hEn|Hˆ0Q|Eˆ ni − hEn|QˆHˆ0|Eni

= iE0

~

hEn|Q|Eˆ ni − hEn|Q|Eˆ ni

= 0

There are still fluctuations given by hEn|Q˙ˆ2|Eni=

X

m

hEn|Q|E˙ˆ mihEm|Q|E˙ˆ ni

=

X

m

hEn|i

~

ˆ

H0,

|EmihEm|i

~

ˆ

H0,

|Eni

= 1

~2

X

m

(EnEm)2

hEm|Q|Eˆ ni

2

(12)

Suppose again densely distributed energy levels

hEn|Q˙ˆ2|Eni= 1

~2

Z

En 0

dEmρ(Em)(EnEm)2

hEm|Q|Eˆ ni

2

+

Z

En

dEmρ(Em)(EnEm)2

hEm|Q|Eˆ ni

2

Substitution ofEmEn=~ωyields

hEn|Q˙ˆ2|Eni=1

~

Z

0

dω ρ(En−~ω)(~ω)2

hEn−~ω|Q|Eˆ ni

2

+ρ(En+~ω)(~ω)2

hEn+~ω|Q|Eˆ ni

2

i

(13)

Fluctuations 3/3

As before, suppose distributed initial energy states.

hE|Q˙ˆ2|EiS=

Z

0

dω~ω2

Z

0

dE ρ(E)f(E, T)

h

ρ(E−~ω)

hE~ω|Q|Eiˆ

2

+ρ(E+~ω)

hE+~ω|Q|Eiˆ

2

i

=:

Z

0

dω IQ˙(ω) =hQ˙2i

From complex alternating current calculation, we know the force-response equation V(ω) =Z(ω) ˙Q(ω)

The Wiener-Khinchin theorem yields

⇒ h

IV(ω)

z }| {

|V(ω)|2i=|Z(ω)|2

IQ˙(ω)

z }| {

h|Q(ω)|˙ 2i ⇒ hV2i=

Z

0

dω IV(ω) =

Z

0

dω|Z(ω)|2IQ˙(ω)

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Thus we can identify (see above)

hVˆ2i=

Z

0

dω|Z|2[1 + exp (−~ωβ)]~ω2

Z

0

dE f(E)ρ(E)ρ(E+~ω)

hE+~ω|Q|Eiˆ

2

As a reminder, we the following solution before:

R

|Z|2 =πω 1−exp (−~ωβ)

Z

0

dE f(E)ρ(E)ρ(E+~ω)|hE+~ω|Q|Ei|ˆ 2

By seperating the integral term

Z

0

dE ρ(E)ρ(E+~ω)|hE+~ω|Q|Ei|ˆ 2= R πω|Z|2

1 1−exp(−~ωβ)

Inserting this intohV2iyields the Generalized Nyquist theorem and the Nyquist relation

hV2i= 2

Z

dω R(ω) ω

1

+ 1

k

BT~ω

⇒ hV2i= 2

Z

dω R(ω)k T

(15)

General strategy to obtain the fluctuation spectrum of a dissipative system 1/1

• Generalize the Hamiltonian from the derivation:

H(t) = ˆˆ H0+V(t) ˆQ →H(t) = ˆˆ H0+F(t) ˆx

• Modify force-response-equation:

V(ω) =Z(ω) ˙Q(ω)F(ω) =Z(ω)v(ω)

• Establish a differential equation of motion forv(t)

• Fourier transform the equation (aka. harmonic analysis)

• Specify the complex impedanceZ(ω)of the system

• Use Generalized Nyquist theorem to calculate the mean square of the fluctuating physical quantity:hA2(t)i

• Bonus: Spectral decompositionhA2(t)i=

R

0 dωIA(ω)(follows with

Wiener-Khinchin theorem see e. g.[Reif,p.690]) yields intensity spectrumIA(ω)

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• Brownian particle with massmis immersed in fluid with frictional constantf

• Langevin equation of motion in one dimension has a random and a systematic part Fran(t)−f·v(t)=! mv(t)˙

• Define Fourier Transforms ofFran(t)andv(t)

Fran(t) =

Z

−∞

F˜ran(ω)eiωtdωandv(t) =

Z

−∞

˜

v(ω)eiωt

• Apply Fourier Transforms to equation of motion

Z

−∞

F˜ran(ω)eiωtdω−f

Z

−∞

˜

v(ω)eiωtdω=m

Z

−∞

iω˜v(ω)eiωt

(17)

1stexample: Brownian motion 2/3

• Since integral kernels must be equal, the force-response-equation has the form F˜ran(ω) = (f+ imω) ˜v(ω)

• The impedance can thus be defined as

Z(ω) =f+ imω

• Application of the Generalized Nyquist theorem yields forkBT~ω

hFran2 i ≈ 2 π

Z

0

dω Re{Z(ω)}kBT =

Z

0

IFran(ω)

z }| {

2 πkBT f

IFran(ω) = const→White spectrum

• Since the integral is divergent, it follows, thatf= const.cannot be valid for high frequencies→cut-off-frequency (see e.g.[Weber])

(18)

• The velocity and the displacement are fluctuating as well

• Use spectral decomposition to determine e. g.hx2i

• Applying FT onv(t) =dx(t)dt yields˜v(ω) =iωx(ω)˜

• The force response-equation becomes with Wiener-Khinchin theorem (WK) F˜ran(ω) = (f+ imω) iωx(ω)˜

⇒ h|F˜ran(ω)|2i = f2+ (mω)2

ω2h|˜x(ω)|2i

WKIFran(ω) = f2+ (mω)2

ω2Ix(ω)

• Hence the mean square of the dispacement is

hx2i=

Z

0

Ix(ω)dω=

Z

0

IFran(ω)

(f2+ (mω)2)ω2dω=

Z

0 2 πkBT f (f2+ (mω)2)ω2

• This integral is again divergent→Introduce lower cut-off frequency to

(19)

2ndexample: electric field fluctuations and radiation (Planck’s law) 1/5

• Consider an accelerated non-relativistic point charge with massmand chargee

• Total radiated power (see[Jackson,ch.14) is

P(t) = 2 3

e2

c3v(t)˙ 2(Larmor formula)

• Establish equation of motion for point charge in electric field in one dimension eEx(t) +Frad(t)=! mv(t)˙

Frad(t)takes account for energy loss due to radiation

• Use energy conservation to specifyFrad(t)

t2

Z

t1

Frad(t)v(t) dt=−

t2

Z

t1

P(t) dt=−2 3

e2 c3

t2

Z

t1

˙ vv˙dt

(20)

• Integration by parts yields (for periodic motion)

t2

Z

t1

Fradvdt=−2 3

e2 c3

t2

Z

t1

˙

vv˙dt=−2 3

e2 c3

=0

z }| {

[ ˙v v]tt2

1

t2

Z

t1

¨ v vdt

Frad=2 3

e2 c3 ¨v

• (Abraham-Lorentz) equation of motion then reads eEx(t) +2

3 e2

c3v(t) =¨ mv(t)˙

• Solutions forEx≡0 : ˙v(t) =

n

0,

XX

XX XX X

˙ v0exp

3mc3 2e2 t

o

• Unphysical nontrivial (runaway) solution in contradiction with periodic motion

• Equation of motion only useful when radiated energy is small compared to total energy (see extensive discussion in[Jackson,ch.16])

(21)

2ndexample: electric field fluctuations and radiation (Planck’s law) 3/5

• Define Fourier Transforms ofEx(t)andv(t):

Ex(t) =

Z

−∞

E˜x(ω)eiωtdωandv(t) =

Z

−∞

˜

v(ω)eiωt

• Apply Fourier Transformation to Abraham-Lorentz equation

e

Z

−∞

E˜x(ω)eiωtdω+2 3

e2 c3

Z

−∞

−ω2v(ω)e˜ iωtdω=m

Z

−∞

iω˜v(ω)eiωt

• Since integral kernels must be equal, the force-response-equation has the form

e ˜Ex(ω) =

ω22 3

e2 c3+ iωm

˜ v(ω)

(22)

• The impedance of the system can thus be defined as Z(ω) =ω22

3 e2 c3 + iωm

• Application of the Generalized Nyquist theorem yields

he2E2xi= 2 π

Z

0

dω ω22 3

e2 c3~ω 1

2+ 1

exp k

BT

−1

!

=

Z

0

dω4 3

e2~ω3 πc3

1

2+ 1

exp k

BT

−1

!

(23)

2ndexample: electric field fluctuations and radiation (Planck’s law) 5/5

• The radiated power per unit area is given by the absolute value of the Poynting-VectorS

S=

c 4πE×B

E⊥B= c

E·BB=

E

=c c 4πE·E

c =E2

isotropic radiation

= 3Ex2

• Taking the mean value yields

⇒ hSi=3hEx2i 4π

• With this definition and withhEx2ifrom the Generalized Nyquist theorem, one obtainsPlanck’s law

hSi= ~ π2c3

Z

0

ω3

2 + ω3

exp k~ω

BT

−1

!

• First term: divergent ”zero point” contribution

(24)

• Generalized Nyquist theorem: Correlates a property of a system in thermal equilibrium (e. g. voltage fluctuations) with a parameter which characterizes an irreversible process (e. g. electrical resistance)

• Nice way to do non-equilibrium thermodynamics and rediscover underlying laws like the white spectrum of Brownian motion or Planck’s law with less effort compared to ”traditional” derivations

• Generalized Nyquist theorem is one way to formulate the fluctuation-dissipation theorem

• Other ways involve other formalisms like for example response functions, generalized susceptibility and retarded Green functions

• Since they all describe the relation between fluctuation and dissipation, they are all connected (mostly via Fourier Transformation)

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• [Callen&Welton]: Herbert B. Callen and Theodore A. Welton:Irreversibility and Generalized Noisein Physical Review Volume 38, Number 1, July 1, 1951

• [Jackson]: John David Jackson:Classical Electrodynamics(3rdedition), John Wiley & Sons, Inc., 1999

• [Reif]Frederick Reif,Statistische Physik und Theorie der W ¨arme, 3. Auflage, Walter de Gruyter, 1987

• [Weber]J. Weber:Fluctuation Dissipation theoremin Phys. Review, Volume 110, Number 6, March 15, 1956

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